Jump to content

Recommended Posts

  • Replies 64
  • Created
  • Last Reply

Top Posters In This Topic

we're telling you what's wrong.

 

1. you have a function called login. do you ever call it from anywhere else in your code?

 

2. inside your function, you set a value for $message but it is never echoed anywhere or provided outside of the function.

 

essentially you have a function that is never called that wouldn't do anything if it was called.

 

auth.inc.php (complete w/ notes):

 

<?php

session_start();

// authenticate username/password against /data/users.db.php
// returns: -1 if user does not exist
//           0 if user exists but password is incorrect
//           1 if username and password are correct
function auth($user, $pass){

$result = -1;

if((trim($user) != "") && (trim($pass) != "")){

$sql = 'SELECT * FROM `members`';
$sqlresult = mysql_query($sql);
while ($row = mysql_fetch_assoc($sqlresult)) {

  // if username matches
  // test password
  if($row['username'] == $user){
   
   // if match, user/pass combination is correct
   // return 1
   if($row['password'] == $pass){
    $result = 1;
    break;
   }else{
    // otherwise return 0
    $result = 0;
    break;
   }
  }
}
}

// return value
return $result;
}

// Check if Sessions have exist or else see if any var's are posted
if(!isset($_SESSION["SESSION_UNAME"]) && !isset($_SESSION["SESSION_UPASS"])){
$f_user = $_POST['f_user'];
$f_pass = sha1($_POST['f_pass']);
}else{
$f_user = $_SESSION["SESSION_UNAME"];
$f_pass = $_SESSION["SESSION_UPASS"];
}

if($_GET['logout'] == "true"){
$f_user = "";
$f_pass = "";
session_unset();
session_destroy();
header("Location: ?");
}

?>

 

Then, where it's called.

 

<?php
include('config.inc.php');
include('db_fns.php');
db_connect();
include('auth.inc.php');
if(auth($f_user, $f_pass) == 1){
$_SESSION['SESSION_UNAME'] = $f_user;
$_SESSION['SESSION_UPASS'] = $f_pass;
}
?>

 

Then, if I want the message, I use 'if(isset($message)){echo $message; }'

there is no $message in the code you posted.??

 

Also it looks like there are too many braces, }

 

you may want to consider indenting your code so mistakes jump out. Your return is outside of the function:

 

function auth($user, $pass){
 
$result = -1;

if((trim($user) != "") && (trim($pass) != "")){

$sql = 'SELECT * FROM `members`';
$sqlresult = mysql_query($sql);
while ($row = mysql_fetch_assoc($sqlresult)) {
	// if username matches
	// test password
	if($row['username'] == $user){
   
		// if match, user/pass combination is correct
		// return 1
		if($row['password'] == $pass){
			$result = 1;
			break;
		} else {
			// otherwise return 0
			$result = 0;
			break;
		}
	}
 	}
}

// return value
return $result; // RETURN IS OUTSIDE OF THE FUNCTION
}

 

this shouldn't even compile. no errors shown?

i was pointing out the mistake, not correcting it. as i stated, that code you posted shouldn't even compile. one of the problems is that your return is OUTSIDE THE FUNCTION.

 

		
          }
	}
} // FUNCTION IS CLOSE HERE, BUT....

// return value
return $result; // RETURN IS OUTSIDE OF THE FUNCTION
}

This thread is more than a year old. Please don't revive it unless you have something important to add.

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.

Guest
Reply to this topic...

×   Pasted as rich text.   Restore formatting

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.


×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.