JAVASCRIPT inside PHP funtion

[thisisnuts123]

Hello all i am trying to echo out javascript funtion inside php any ideas how can this be done?

there is the code

 

/*

 

function update_dropbox($data_array, $col_check)

{

      $i = 0;

$o = array();

foreach($data_array AS $set => $items)

{

foreach($items AS $item)

{

$item = mysql_escape_string($item);

      $set  = mysql_escape_string($set);

$o[$i] = $items[$i];

 

      $query  = "SELECT `site` FROM table WHERE `item` = '$o[0]'";

      $result = mysql_query($query);

      $row = mysql_fetch_row($result);

      $value = $row[0];

      $i ++;

  }

}

 

 

 

return $value;

 

}

*/

 

 

how can i echo an javascript alert of the variabe "$o[0]"

 

Thanks in advance

 

[MadTechie]

erm..

like this

echo $o[0];

 

other example

<?php
echo '<script language="javascript">alert("test");</script>';
?>

 

 

[npsari]

or just stop the php in the middle and start it again, it works!

 

like that...

 

<?

php stuff

?>

 

Your Javascript

 

<?

php stuff

?>

[thisisnuts123]

this whole thing is a funtion

but when i run the site the page pops up without me calling the funtion

how can i make it only pop up once the funtion is called

 

 

/*

<?php

function update_dropbox($data_array, $col_check)

{

      $i = 0;

$o = array();

foreach($data_array AS $set => $items)

{

foreach($items AS $item)

{

$item = mysql_escape_string($item);

      $set  = mysql_escape_string($set);

$o[$i] = $items[$i];

 

      $query  = "SELECT `site` FROM table WHERE `item` = '$o[0]'";

      $result = mysql_query($query);

      $row = mysql_fetch_row($result);

      $value = $row[0];

      $i ++;

  }

}

if( $value != NULL )

        {

           

echo "<script type=\"text/javascript\">\n";

echo "<!--\n";

echo " window.open(\"modules/$name/copyright.php\",\"Copyright\",\"toolbar=no,location=no,directories=no,status=no,scrollbars=yes,resizable=no,copyhistory=no,width=400,height=200\");\n";

echo "//-->\n";

echo "</script>\n\n";

}

return $value;

 

}

 

 

?>

*?

[SirChick]

please put your code in tags makes life a bit easier to read =/

[thisisnuts123]

i think i have the code right!!

as my debuger picks up the alert!!

is it posible to send an alert out from php funtion..

as i do not see any alerts

 

 

my page starts of with

 

<?php ...

 

blah blah

 

function update_dropbox($data_array, $col_check)

{

     

blah blah

?> 

<script script type="text/javascript">

var site="<?= $value ?>";

alert(site);   

</script>

 

<?php

 

}

 

this should pick up value insert it in to variable site and send an alert out.. only when the php funtion is called.

in my debuger i do see the java variable "site" geting updated.. but it does not send the alert out any ideas why?

[thisisnuts123]

sorry i am new to this site i duuno how to put the code in tags so it;s nice and easy to read

[kenrbnsn]

Put the tag

[/b] before the start of the code snippet and [b]

after it.

 

Ken

[thisisnuts123]

ok perfect thanks!!

<?php ...

blah blah

function update_dropbox($data_array, $col_check)
{
         
blah blah
?>  
   <script script type="text/javascript">
   var site="<?= $value ?>";
   alert(site);     
   </script>
      
<?php   
      
}

 

 

any idea why this will not pop up an alert?

is this becuas it;s in an php funtion?

if so is there a way around it?

[roopurt18]

You repeated the word script in your script tag, remove the duplicate.