strstr question

[corillo181]

can some one tell my why this is not woking

 

$email = something@this.com;
$find = '@';

echo strstr($email,$find,true);
//prints nothing;
//expected  something;

but if i do

$email = something@this.com;
$find = '@';

echo strstr($email,$find);
//prints something;

[zq29]

Are you running PHP6? The third parameter was added in version 6.

[corillo181]

oh i looked at the documentation and it says php 4 and 5.

 

function username($id){

	$email = something@this.com;
	$search = strpos($array['email'],'@') - 1;
	$len = strlen($email);
	$sub = substr($email,0,-($len-$search)+1);
return $sub;
}

 

this is the way i did it, those any  one have a better way?