[SOLVED] NOOB Array/Menu question . . .

[Waterskier19]

Hi all,

 

  Very new to PhP, but have a lot of experience with C++ - so I have a good understanding of Arrays in general, however - I am having some problems with a form that I am trying to create.

 

Basically, what I have is a menu created from an array

 

[pre]

$cancellationMessage = array(0 => 'Select Notice', 'Weather Delay', 'Weather Cancellation', 'Other');

echo "Cancellation Notice:\n";

echo '<select name="Cancellation Message">';

foreach ($cancellationMessage as $key => $choice)

{

  echo "<option value=\"$key\">

  $choice</option>\n";

}

echo '</select>';

[/pre]

 

This creates the menu for me without a problem - but my question is, when the user hits POST - how do I find what the user chose as his selection? ($choice always seems to be the last option in the array)

 

Basically, if its a certain selection, I want to do special stuff . . . i.e.

 

if (usersSelection == "Weather Delay")

{

    then do delay stuff;

}

else

{

    do something else

}

 

I'm obviously missing something - Any help would be appreciated.

 

Thanks

 

 

[trq]

<?php

  if (isset($_POST['submit'])) {
    switch ($_POST['Cancellation Message'])) {
      case 'foo':
        // do foo
        break;
      case 'bar':
        // do bar
        break;
      default:
        // do default
    }
  }

?>

[Waterskier19]

Thanks for your help, but now I have a follow up question. Is there anyway to check user input before the Post button is pressed (i.e. as soon as the option menu is selected by the user, check the values)?

 

Basically I want to do the following:

-  As soon as the user selects cancellationMessage from the menu, check the type and if it is "Delay" enable (or create dynamically)  -  a text-box that will prompt the user to select the delay time.

 

Is this possible?  Sorry for my lack of experience with what Php can/can't do.

 

Thanks

[kenrbnsn]

That can only be done using Javascript. Since PHP is executed on the server, it doesn't see any data until the user submits the form.

 

Ken

[duclet]

That has to be done with AJAX. My suggestion, get this to work correctly first, then tackle on the advanced stuff later. Working in simple steps makes it much easier.