need regular expression help, pls

[ivytony]

<?php

$url = 'http://www.officedepot.com/?url=http://clickme.com?id=pA8dtfFoCs8&postrid=137588.443676&type=2&subid=0';

 

?>

 

for this above $url, I would like to get the main domwin and the part after ?url=. Now I can get the domain by using this regular expression

<?php
    preg_match('/([^\.\/]+\.[^\/\.]+)((\/)|($))/', $url, $d);
    echo $domain = strtolower($d[1])."<br />";
?>

 

I am wondering how to use regular expression to get the part after ?url=. I apprecate your help

 

 

[Jessica]

There's a board for regular expresions: ) But if all you need is everything after ?url you can use strpos and substr.

[ucffool]

Can you use parse_str()

http://www.php.net/manual/en/function.parse-str.php

or

parse_url()

http://www.php.net/manual/en/function.parse-url.php

 

Rather than a regular expression?

[ivytony]

I don't think I can use parse_str, because there are '&' signs in the part after $url=http://clickme.com?id=pA8dtfFoCs8&postrid=137588.443676&type=2&subid=0';

 

edit: I figured it out by using parse_url

 

<?php
echo parse_url($url, PHP_URL_QUERY);
?>

thanks!

[sasa]

preg_match patern '/\?url=(.+)$/'