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passing variables to new window in php


sudhakararaog

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1.

 

i have a self submitting form using POST

<form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="POST" id="test2" name="registrationform">

 

i am not using any javascript assuming javascript is turned off in a users browser.

 

i have a feature where in a user can click on an image to find out if a username is available or not. using javascript i am

 

able to capture the value entered, pass the value entered by the user and open a new window and display a message with a php

 

file if the username is available or not however since i am not using javascript i used the following code to call the same

 

php file which checks for the user name,

 

<a href="checkusername.php?usernameis="<?php echo($username); ?> target="_blank"> <img src="image.jpg"> </a>

 

however i am not able to pass the value of the username entered in the textfield by the user.

 

code in checkusername.php is

 

$username = $_GET["usernameis"]; and the remaining code to connect to database and display a message.

 

how can i pass the value entered in the textfield to checkusername.php when the image is clicked. also is there a way to

 

define the width and height of the new window that opens.

 

textfield is defined as follows = <input name="username" type="text" value="<?php echo($username) ; ?>" />

 

 

2.

i need to validate a password which can consist of both letters and numbers and should be between 5 to 10 characters only.

 

how can i rewrite the following preg_match to specify the condition of 5 to 10 characters only as presently it is not working

 

as i seem to be missing something in the syntax.

 

if($password == "" || !preg_match('/^[a-zA-Z0-9]{\(5)$|^\(10)}+$/', $password) )

 

please advice.

 

thanks.

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