dennismonsewicz Posted April 1, 2008 Share Posted April 1, 2008 Ok, Here is my situation. I have a SQL query running to insert data into a table field, but when it does it inserts a blank field then inserts the data. Any suggestions? Link to comment https://forums.phpfreaks.com/topic/99007-solved-blank-data-field-inserted-data-field/ Share on other sites More sharing options...
kenrbnsn Posted April 1, 2008 Share Posted April 1, 2008 Code? Please surround you code with tags. Ken Link to comment https://forums.phpfreaks.com/topic/99007-solved-blank-data-field-inserted-data-field/#findComment-506608 Share on other sites More sharing options...
trq Posted April 1, 2008 Share Posted April 1, 2008 Any suggestions? Post the relevent code. Link to comment https://forums.phpfreaks.com/topic/99007-solved-blank-data-field-inserted-data-field/#findComment-506609 Share on other sites More sharing options...
dennismonsewicz Posted April 1, 2008 Author Share Posted April 1, 2008 <?php $_SESSION['username'] = $_GET['username']; if($_POST) { // In PHP versions earlier than 4.1.0, $HTTP_POST_FILES should be used instead // of $_FILES. $uploaddir = 'path_to_dir'; $uploadfile = $uploaddir . basename($_FILES['userfile']['name']); $url = 'url_dir' . $_FILES['userfile']['name']; $filename = $_FILES['userfile']['name']; $filesize = $_FILES['userfile']['size']; $filetype = $_FILES['userfile']['type']; $uploaded_by = $_SESSION['username']; $categories = $_POST['categories']; if (move_uploaded_file($_FILES['userfile']['tmp_name'], $uploadfile)) { echo '<div class="maincontentheader"> <h2>' . ucwords($_SESSION['username']) . ', thank you for your upload!</h2> </div>'; echo "<p>File is valid, and was successfully uploaded.\n</p>"; } else { echo "<p>Possible file upload attack!\n</p>"; } echo '<p>Below is the information of the file you uploaded:</p>'; echo '<p> Name of File: ' . $filename . '</p>'; echo '<p> Type of File: ' . $filetype . '</p>'; echo '<p> Size of File: ' . $filesize . '</p>'; echo '<p> Categories: ' . $categories . '</p>'; $thumbq = "insert into thumbs (thumb_name) values ('$filename')"; $thumquery = mysql_query($thumbq) or die("ERROR: " . mysql_error()); if($_FILES['userfile']) { include "includes/sql.php"; $query = "insert into uploads (username, name, size, type, url, categories, downloaded_by) " . "values ('$uploaded_by', '$filename', '$filesize', '$filetype', '$url', '$categories', '')"; mysql_query($query) or die("ERROR: " . mysql_error()); echo '<p>File loaded into Database successfully!</p>'; } else { echo '<p>There was a problem with inserting the file into the database! Please try again!</p>'; } } else { echo '<div class="maincontentheader"> <h2>' . ucwords($_SESSION['username']) . ', use the form below to upload an image!</h2> </div> <p>Make sure to add categories to this image.</p> <p> </p> <p>Adding categories allows for the image to show up during an image search!</p> <p> </p> <p>Example Categories: Cat, Dog, Ocean, Older Male, Female, etc...</p> <p> </p> <p style="font-size: 80%"><b>Note: if you have more than one category please make sure to separate them by a comma!</b></p> <p> </p> <!-- The data encoding type, enctype, MUST be specified as below --> <form enctype="multipart/form-data" action="upload.php?username=' . $_SESSION['username'] . '" method="POST" name="uploadfile"> <!-- MAX_FILE_SIZE must precede the file input field --> <input type="hidden" name="MAX_FILE_SIZE" value="9999999" /> <!-- Name of input element determines name in $_FILES array --> <p>Image Categories: <input name="categories" type="text" /></p> <p> </p> <p>Upload this file: <input name="userfile" type="file" /></p> <p><input type="submit" value="Upload File" /></p> </form>'; } //on-th-fly thumbnail generator include "thumbtest.php"; ?> Now the weird thing it is reversed. It is inserting the data and then a blank field :/ it started doing this I moved the include "thumbtest.php" down to the bottom Link to comment https://forums.phpfreaks.com/topic/99007-solved-blank-data-field-inserted-data-field/#findComment-506611 Share on other sites More sharing options...
trq Posted April 1, 2008 Share Posted April 1, 2008 So what in thumbtest.php then? Link to comment https://forums.phpfreaks.com/topic/99007-solved-blank-data-field-inserted-data-field/#findComment-506613 Share on other sites More sharing options...
dennismonsewicz Posted April 1, 2008 Author Share Posted April 1, 2008 <?php function createThumbs( $pathToImages, $pathToThumbs, $thumbWidth ) { // open the directory $dir = opendir( $pathToImages ); // loop through it, looking for any/all JPG files: while (false !== ($filename = readdir( $dir ))) { // parse path for the extension $info = pathinfo($pathToImages . $filename); // continue only if this is a JPEG image if ( strtolower($info['extension']) == 'jpg' ) { //echo "Creating thumbnail for {$filename} <br />"; // load image and get image size $img = imagecreatefromjpeg( "{$pathToImages}{$filename}" ); $width = imagesx( $img ); $height = imagesy( $img ); // calculate thumbnail size $new_width = $thumbWidth; $new_height = floor( $height * ( $thumbWidth / $width ) ); // create a new temporary image $tmp_img = imagecreatetruecolor( $new_width, $new_height ); // copy and resize old image into new image imagecopyresized( $tmp_img, $img, 0, 0, 0, 0, $new_width, $new_height, $width, $height ); // save thumbnail into a file imagejpeg( $tmp_img, "{$pathToThumbs}{$filename}" ); } } // close the directory closedir( $dir ); } // call createThumb function and pass to it as parameters the path // to the directory that contains images, the path to the directory // in which thumbnails will be placed and the thumbnail's width. // We are assuming that the path will be a relative path working // both in the filesystem, and through the web for links createThumbs("imageuploads/","imageuploads/thumbs/",100); function createGallery( $pathToImages, $pathToThumbs ) { //echo "Creating gallery.html <br />"; $output = "<html>"; $output .= "<head><title>Thumbnails</title></head>"; $output .= "<body>"; $output .= "<table cellspacing=\"0\" cellpadding=\"2\" width=\"500\">"; $output .= "<tr>"; // open the directory $dir = opendir( $pathToThumbs ); $counter = 0; // loop through the directory while (false !== ($filename = readdir($dir))) { // strip the . and .. entries out if ($filename != '.' && $filename != '..') { $output .= "<td valign=\"middle\" align=\"center\"><a href=\"{$pathToImages}{$filename}\">"; $output .= "<img src=\"{$pathToThumbs}{$filename}\" border=\"0\" />"; $output .= "</a></td>"; $counter += 1; if ( $counter % 4 == 0 ) { $output .= "</tr><tr>"; } } } // close the directory closedir( $dir ); $output .= "</tr>"; $output .= "</table>"; $output .= "</body>"; $output .= "</html>"; // open the file $fhandle = fopen( "gallery.html", "w" ); // write the contents of the $output variable to the file fwrite( $fhandle, $output ); // close the file fclose( $fhandle ); } // call createGallery function and pass to it as parameters the path // to the directory that contains images and the path to the directory // in which thumbnails will be placed. We are assuming that // the path will be a relative path working // both in the filesystem, and through the web for links createGallery("imageuploads/","imageuploads/thumbs/"); ?> Link to comment https://forums.phpfreaks.com/topic/99007-solved-blank-data-field-inserted-data-field/#findComment-506615 Share on other sites More sharing options...
dennismonsewicz Posted April 1, 2008 Author Share Posted April 1, 2008 bump Link to comment https://forums.phpfreaks.com/topic/99007-solved-blank-data-field-inserted-data-field/#findComment-506630 Share on other sites More sharing options...
dennismonsewicz Posted April 1, 2008 Author Share Posted April 1, 2008 TOPIC SOLVED! Link to comment https://forums.phpfreaks.com/topic/99007-solved-blank-data-field-inserted-data-field/#findComment-506670 Share on other sites More sharing options...
kenrbnsn Posted April 1, 2008 Share Posted April 1, 2008 What was the solution? Ken Link to comment https://forums.phpfreaks.com/topic/99007-solved-blank-data-field-inserted-data-field/#findComment-506706 Share on other sites More sharing options...
dennismonsewicz Posted April 1, 2008 Author Share Posted April 1, 2008 It is a little difficult to explain, but I pretty much just had to rearrange some of my code and had to add this bit of code: $thumb_name = str_replace("jpg", ".jpg", $info['filename'] . $info['extension']); include "includes/sql.php"; $thumbq = "insert into thumbs (thumb_id, thumb_name) values (NULL, '$thumb_name')"; $thumquery = mysql_query($thumbq) or die("ERROR: " . mysql_error()); the $info var is used from an array reading the files out of the directory the thumbnails are in Link to comment https://forums.phpfreaks.com/topic/99007-solved-blank-data-field-inserted-data-field/#findComment-506814 Share on other sites More sharing options...
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