Basic array problems!

[Edward]

Here is the code I am using:

$members = 'Person1, Person2';
$array = explode(',',$members); //this creates an array by exploding your addresses at the character ','
foreach ($array AS $person) {
if ($person == 'Person1') { $number = 'Odd'; }
if ($person == 'Person2') { $number = 'Even'; }
$body = 'Hi there ' . $person . ', you are ' . $number;
echo $body;
}

Here is the desired outcome:
Hi there Person1, you are Odd
Hi there Person2, you are Even

Here is the ACTUAL outcome:
Hi there Person1, you are Odd
Hi there Person2, you are Odd

Can anyone see what I'm doing wrong? I'm trying to create a basic code I can use to specify one variable depending on what aother is, inside a loop.

[AndyB]

I can't see the difference between the actual outcome and the desired outcome Maybe we need a different example??

[Edward]

[!--quoteo(post=375080:date=May 18 2006, 11:49 PM:name=AndyB)--][div class=\'quotetop\']QUOTE(AndyB @ May 18 2006, 11:49 PM) [snapback]375080[/snapback][/div][div class=\'quotemain\'][!--quotec--]
I can't see the difference between the actual outcome and the desired outcome Maybe we need a different example??
[/quote]

Sorry, I'm tired, I've amended it now.

Here is the ACTUAL outcome:
Hi there Person1, you are Odd
Hi there Person2, you are Odd

[kenrbnsn]

Those darn pesky spaces ...
You wrote:
[code]<?php
$members = 'Person1, Person2';
$array = explode(',',$members); //this creates an array by exploding your addresses at the character ','
foreach ($array AS $person) {
if ($person == 'Person1') { $number = 'Odd'; }
if ($person == 'Person2') { $number = 'Even'; }
$body = 'Hi there ' . $person . ', you are ' . $number;
echo $body;
}?>[/code]

Notice you have a space after the comma, so the second member of the array is really ' Person2'. That's why the "if" fails. Remove the space or use:
[code]<?php
if (trim($person) == 'Person1') { $number = 'Odd'; }
if (trim($person) == 'Person2') { $number = 'Even'; }
?>[/code]
for your comparison statements.

Ken