How to insert the dynamically created text box values to db in php ?

[FairoojNazeer]

my name is fairooj and ama new to php and jquery. i have a proplam. i want your help.

 

<script type="text/javascript">

var count = 0;

$(function(){

$('p#add_field').click(function(){

count += 1;

$('#container').append(

'<strong>Link #' + count + '</strong><br />' 

+ '<input id="field_' + count + '" name="fields[]' + '" type="text" />'

+ '<input id="code_' + count + '" name="code[]' + '" type="text" /><br />' );



});

});

</script> 

 

this is my script to add more text boxes..

 

and this is ma code for insert it to database 

 

<?php

//If form was submitted

if (isset($_POST['btnSubmit'])) {



//create instance of database class

$db = new mysqldb();

$db->select_db();



//Insert static values into users table

$sql_user = sprintf("INSERT INTO users (Username, Password) VALUES ('%s','%s')",

mysql_real_escape_string($_POST['name']),

mysql_real_escape_string($_POST['password']) );  

$result_user = $db->query($sql_user);





//Check if user has actually added additional fields to prevent a php error

if ($_POST['fields']) {



//get last inserted userid

$inserted_user_id = $db->last_insert_id();



//Loop through added fields

foreach ( $_POST['fields'] as $key=>$value ) {



//Insert into websites table

$sql_website = sprintf("INSERT INTO websites (Website_URL, web_Link) VALUES ('%s', '%s')",

      mysql_real_escape_string($value), mysql_real_escape_string($value) );  

$result_website = $db->query($sql_website);

$inserted_website_id = $db->last_insert_id();





//Insert into users_websites_link table

$sql_users_website = sprintf("INSERT INTO users_websites_link (UserID, WebsiteID) VALUES ('%s','%s')",

      mysql_real_escape_string($inserted_user_id),

  mysql_real_escape_string($inserted_website_id) );  

$result_users_website = $db->query($sql_users_website);



}



} else {



?>

 

 

 

the problame web_Link sql table is repeating Website_URL table value....

 

plz how can i solve this

 

am waiting for your reply..

 

Edited September 2, 2014 by mac_gyver
code tags please

[mentalist]

 mysql_real_escape_string($value), mysql_real_escape_string($value) );  

The first $value should be $key?

[jcbones]

Mentalist is right, you got a little confused about your structure and what is happening.  I added a little clarity in this for you.

 
//Loop through added fields
foreach ( $_POST['fields'] as $key=>$value ) {
//for clarity:
$url = $value;
$web_link = $_POST['code'][$key];
 
//Insert into websites table
$sql_website = sprintf("INSERT INTO websites (Website_URL, web_Link) VALUES ('%s', '%s')",
      mysql_real_escape_string($url), mysql_real_escape_string($web_link) );  
$result_website = $db->query($sql_website);
$inserted_website_id = $db->last_insert_id();
 
 
 
 
//Insert into users_websites_link table
$sql_users_website = sprintf("INSERT INTO users_websites_link (UserID, WebsiteID) VALUES ('%s','%s')",
      mysql_real_escape_string($inserted_user_id),
  mysql_real_escape_string($inserted_website_id) );  
$result_users_website = $db->query($sql_users_website);
 
 
}

Edited September 2, 2014 by jcbones