[Output Information from an array in to Tables]

<?php foreach ($option['option_value'] as $key => $option_value)

            {

               print ( '<pre>' )  ;

               print_r ($option_value[$key]['name'] .' '.$option_value[$key]['quantity']) ;    

               print ( '</pre>' )  ;

            }

         ?>

[Use Message Box in PHP]

one direction you could take is something like this:

have a select list of all users with the name as the select option and the value as the mobile:
<select id="names">
<option value="077451452584">Bob Bob</option>
<option value="077451452585">Frank Frank</option>
<option value="077451452586">Bertha Bertha</option>
</select>

<script>
$(document).ready(function(){

$('#names').on('change', function(){
   var val = $('option:selected', this).val();
   alert(val);
});
});
</script>

[Variable from one Function to another]

i think you have a bit of a misguided view of what oop is. I advise taking a step back and reading a little more into the concepts of object orientation. I dont think me re writing you attemplt at a class will really benifit you

[OOP - Passing Data/Variables Between Functions]

you beat me to it, the load only assigned the data to the parameters, if you wanted to test it you needed to add return true

[OOP - Passing Data/Variables Between Functions]

<?php

/* MySQL Columns & Types

Id - Primary Key (Index), Auto Increment - Int (11)

Title - Varchar (20)

FirstName - Varchar (60)

LastName - Varchar (60)

*/


class client

{

    private $_mysqli;

    private $_title;

    private $_firstName;

    private $_lastName;



    //Connect to MySQL

    public function __construct()

    {

        $this->_mysqli = new mysqli("localhost", "test", "test", "test");


        if ($this->_mysqli->error) {

            throw new Exception($this->_mysqli->error);

        }


    }


    //These functions build the insert query so they can be called one at a time or all at once

    public function setTitle($title)

    {

        $this->_title = $title;

    }


    public function getTitle()

    {

        echo $this->_title;

    }


    public function setFirstName($firstname)

    {

        $this->_firstName = $firstname;

    }


    public function getFirstName($te)

    {

        echo $this->_firstName;

    }


    public function setLastName($lastname)

    {

        $this->_lastName = $lastname;

    }


    public function getLastName()

    {

    echo $this->_lastName;


    }


    public function load($client_id)

    {


    $data = array();

    //the follwoing is on the principle of a single result

    $query = "SELECT * FROM mysql WHERE id = " . $client_id;

    $sql = $this->_mysqli ->query($query);

    if($sql->num_rows > 0) {

        while ($row = $sql->fetch_assoc()) {

        $this->_title = $row['title'];

        $this->_firstName = $row['firstname'];

        $this->_lastName = $row['lastname'];


            // now you have done this you will have a populated object. so the get the firstname you do $client->getFirstname()

        }

    } else {

        throw new Exception('client not found');

    }

    }


    // you should be able to figure the rest out

    /*public function save()

    {


    if ($check->Rows() > 0)	{

    //update

    $mysqli->query("UPDATE clients SET $cloumns");

    } else {

    //insert

    $query = "INSERT INTO mysql (".$columns.")VALUES (.".$values.".)";

    $mysqli->query($query);

    }

    $sql->close();


    }*/

}

[Appointment booking]

you need to post this in the freelance section

[mysql_fetch_array() expects parameter 1 to be resource, boolean is given]

do some error checking, the error you are getting is because the query could not successfully execute, hence no resource. try this:

$result = mysql_query("SELECT Cust_Num, Contact_Name, Contact_Phone from Customer order by Cust_Num") or die(mysql_error());

//that will tell you what is wrong with your query

[How to i create popup?]

annaharris:

 

this link is nearly a decade old. and as i stated in my previous post, is a redundant way of doing things. the post was posted APRIL 16, 2004

[hi i have code for example]

good bit of code there . what does it do?

[How to i create popup?]

Again, Irate, I am afraid that this is not really a popup, it is 2013, not 2003. people tend not to use secondary windows for popups nowadays. With the advancement in client side languages and the common use of ajax the need for this style of 'popup' is now defunct. you don't need to use onclick= within the elements any more, in fact the prefered method is not to have any javascipt in the html at all and bind an event listener to an element and inject what is needed into the DOM. below is a quick example of a jquery dialog ( popup ):

<html>
<head>
    <link href="http://code.jquery.com/ui/1.10.3/themes/smoothness/jquery-ui.css" rel="stylesheet" type="text/css"></link>
    <script src="http://code.jquery.com/jquery-1.9.1.min.js"></script>
    <script src="http://code.jquery.com/ui/1.10.3/jquery-ui.js"></script>
</head>
<body>
<button id="myButton">Click Me To Open Dialog</button>

<div id="dialog-message" title="Im the title" style="display:none">
    <div style="margin-left: 20px;">
        <p>
            Lorem Ipsum. Lorem Ipsum. Lorem Ipsum. Lorem Ipsum. Lorem Ipsum. Lorem Ipsum. Lorem Ipsum. 
            <br /><br />
            Lorem Ipsum. Lorem Ipsum. Lorem Ipsum. Lorem Ipsum. Lorem Ipsum. Lorem Ipsum. Lorem Ipsum. 
        </p></div>
</div>

<script>
    $(document).ready(function(){
        $('#myButton').on('click',function(){
            $("#dialog-message").dialog({
                modal: true,
                draggable: true,
                resizable: false,
                position: ['center', 'top'],
                show: 'blind',
                hide: 'blind',
                width: 400,
                buttons: {
                    "Click me to close dialog": function() {
                        $(this).dialog("close");
                    }
                }
            });

        });
    });
</script>
</body>
</html>

Hope this helps

[How to i create popup?]

irate: that is not a popup, that is a new window. if you want a popup you are more than likely referring to some form of modal dialog. Have a google for jquery modal dialog, or bootstrap dialog. that will give you a good starting point

[Php exec() command]

php comes with some helpful constants and methods that can help. the one you will be concerned with is :

DIRECTORY_SEPERATOR
// an example would be

$fileDir = 'dir1'.DIRECTORY_SEPERATOR.'dir2'.DIRECTORY_SEPERATOR.......... and so on

so the above would give you dir1/dir2/..... on a linux machine, and is clever enough to translate it to dir1\dir2 on windows

[to move up and down records in html table]

have a look at using jquery datables. it comes with multi column sorting and searching, pagination etc

[how can learn fast online php]

Sorry, i left my magic insta-learn pills in my other bag

[unexpected T_VATRIABLE]

$subject="Thank you for your order"

// should be

$subject="Thank you for your order";

[fetch and echo db content and its count]

turn on your error handling on the php page

[form help new to php]

ok, firstly, my bad. query should read:

$sql = "INSERT INTO emails(`player_name`,`email`) values ('{$_POST['playername']}','{$_POST['email']}')";

pay very close attention to the tick marks surrounding player_name and email. they have to be backticks --> ` <--- not single apostrophes -->'<--  so they should be `player_name` NOT 'player_name'

.a varchar and text field can both accept nubmers and characters. your sql error is telling you that you have a syntax error, which is what i have described above.

[form help new to php]

do 

$sql = "INSERT INTO emails(`player_name`,`email`)('{$_POST[playername]}','{$_POST[email]}')";

mysql_query($sql,$con) or die(mysql_error());

 

that should give you some inkling as to whats wrong.

Also make sure you have the primary key set to auto incriment

[form help new to php]

ok firstly, jugesh is wrong, when it comes to mixing html and php on a page, if the php is not outputting ( rendering anything then it is irrelevant where it is on the page ) the reason you are getting this error is because you are manyally killing the script:

$con=mysql_connect("localhost","dbs_dbs","password");
die("Can not connect: " . mysql_error());

needs to be 

 

$con=mysql_connect("localhost","dbs_dbs","password") or die("Can not connect: " . mysql_error());

[javascript function does not return true in firefox]

if your using a direct comparator against true is true then it needs to be === : 

if(checkEmpty===true && checkNum===true && checkStr===true)

[form help new to php]

2 things:

1: 

<input type="submit" name="submit"
// should be 
<input type="submit" name="submit" />

and:

die(Can not connect: " . mysql_error());
// should be
die("Can not connect: " . mysql_error());

[showing other peoples data]

$cust = $_GET["username"];

$sql = "select * from weight where `username` = '{$cust}'";

[Add post title in the end of url]

And I want a big house and fast car, but i want dosent get. You want help then give more information than just i want!!

 

What framework is the site built in? this would be a good start, or at least the section of code that deals with the routing

[hiding a div by clicking off it]

use the blur event in jquery

[[Symfony 2] creating combobox]

are you running the site from / or app_dev.php? sounds like your getting a fatal error,. have you cleared the cache and updated the schema?

php app/console cache:clear --env=dev
php app/console doctrine:schema:update --force

also look in the app/logs/dev log to see if there is any error being thrown