[Hide URL but still keep $_GET variables]

you could use a post request or mod_rewrite

[PHP coding help needed]

for starters, change these lines

<?php 
$row= mysql_fetch_array($rs);
?>



<table border="1" summary="Customer Details">
<tr>
<th>cID</th>
<th>Order number</th>
<th>Order Date</th>
<th>Shipped</th>
</tr>
<?php
if ($custid == $row)  { ?>
<tr>
<td><?php echo $row["customerID";] ?></td>
<td><?php echo $row["orderNumber"]; ?></td>
<td><?php echo $row["orderDate"]; ?></td>
<td><?php echo $row["shipped"]; ?></td>

</tr>
<?php }
mysql_close($conn); ?>
</table></body></html>

also, not sure why you are setting your post id equal to mysql_fetch_array()

[Multiple emails being sent]

okay glad you figured it out

[Validating using class - not working :(]

try to make name equal to a simple string...

$name = 'test';

[Database design question]

could make a table with category names as fields and insert each video in the correct field

[Multiple emails being sent]

you could try debugging your queries...

$getNEWid2 = mysql_query("SELECT ID FROM ".$conf['tbl']['users']." ORDER BY ID DESC LIMIT 1 ") or die(mysql_error());	
WHILE ($NEWid2 = mysql_fetch_array($getNEWid2)){
$send = mysql_query("SELECT name,user,email from ".$conf['tbl']['users']." WHERE ID=$NEWid2[iD]") or die(mysql_error());
   WHILE($newsiteuser = mysql_fetch_array($send)) {
//emails sent here//
}}

[Validating using class - not working :(]

try to keep your function var consistent with your post var. So if your post var is $name, then your function var will be $name

class validate
{

function check_input($name)
{
    $data = trim($name);
    $data = stripslashes($name);
    $data = htmlspecialchars($name);
    return $name;
}

}

[reauthenticate user]

then the admin shouldn't be so foolish as to walk away from his/her comp still logged into their account..that will always be an issue for all webpages

[reauthenticate user]

Why not just create another form for the admins

[Hello everyone]

welcome to the forums...hope we can help you out

[What I am doing Wrong? mysql error]

seems like your else statement is not getting triggered..therefore your mysql_fetch_array() function is trying to use an empty var

[MYSQL php error]

as project fear said above...this notice is being triggered because your form has not been submitted...what is the results that you receive when this script is ran?

[working with constants]

yes i would like to know why you need to use a constant here

[Variable association warning]

glad i could help, if you ever need further assistance we are here to help

[Date into Form Field with Button?]

you could also do something where if the user chooses to add todays date..the code will generate a hidden field with todays date, else it will process whatever date the user inserts into the field..is this data going to be entered into a database?

[need help in adding the content]

like i said, look at your insert statement, the query doesnt now where to insert the submitted data.

 

$sql = "INSERT INTO info  VALUES (null, '$title' , '$body')";

 

should be

 

$sql = "INSERT INTO info (title,body) VALUES ('$title' , '$body')";

 

also need to add a " = " to this line

<label for="title">Title:</label>

<input type="text" name"title" id="title" />

labrat, you do not need to specify where to put the values as long as the values match with the fields, if you have an auto-incrementing field that you are not inserting a value into, you will need to put empty quotations for that field in your insert clause...eminempk, where is the script that is calling the functions that you created?

[hey fellow hipsters]

Welcome to the forums. Hopefully you will learn alot from us

[working with constants]

You can also encase the var in curly brackets instead of concatenation.

[working with constants]

What exactly do you mean by you want the var to be constant without concatenation?

[generating a password without the letters 'oh' or 'el' or the numbers 1 or 0]

Sounds like simple field validation to me. Using if else statements to filter the user input with whatever stipulations that you would like.

[My Social Networking Website. In progress, looking for suggestions]

Looks pretty good. Nothing to do on it though. Will need to add a lot of functionality to it. Like the Ajax work you did on it thus far though.

[php require_once not working]

also, might be because you are not using a relative path...are you using a localhost server? try this

<?php require_once 'example/dir/footer.php'; ?>

using the full path to the file

[Validate a user name and password]

And also, put MySQL field names in backquote operators, so that it never conflicts with MySQL reserve word. E.g. "password" is a MySQL reserve word. Try this:

 

$user = mysql_real_escape_string($_POST['user_name']);
$pass = mysql_real_escape_string($_POST['password']);
$query = "SELECT * FROM `users` WHERE `user_name` = '$user' AND `password` = 'pass'";
$user_name_check = mysql_query($query);

 

Thanks!

actually, "password" is not a mysql reserved word...however always placing backticks around you field names will eliminate the risk of triggering an error due to using a mysql reserved word

[Hey all]

glad to have ya...hopefully you can learn from the forums

[checkbox array help]

that's correct, when you tested this did you not have any checkboxes checked?