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jamesmargolis

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  1. jamesmargolis
    Thank you ch0cu3r, your solution works for me. I noticed some posts in thid forum are marked with a green "ANSWERED" (indicating that they have been fully answered I presume :-) ) and I guess this is what I should mark this post now, but I fail to see an "answered" button anywhere
  2. jamesmargolis
    In the code below, I am trying to produce a google-like page where the user can type keywords and pages of search results are displayed. The main difficulty I am encountering is that when the browser changes pages, it forgets everything about current data. Perhaps I should include the display of pages inside the HTML form ? How can I fix this code ? Here is the contents of my searchpage.php file : <?php $keywords=''; $display_search_results=''; if(isset($_POST['search_submitted'])) { $keywords=$_POST['keywords']; $search_results=array(); $totalNbrOfItems=20; for($k=1;$k<=$totalNbrOfItems;$k++) { $search_results[$k]='Your keywords '$keyowrds.' have been found in item number '.$k; } $nbrOfItemsParPage = 5; $nbrOfPages = ceil($totalNbrOfItems / $nbrOfItemsParPage); // Compute current page $current_page = (isset($_GET['page']))?intval($_GET['page']):1; $display_pages=($nbrOfPages<2)?'<p>Page : ':'<p>Pages : '; for ($i = 1 ; $i <= $nbrOfPages ; $i++) { if ($i == $current_page) //No link to the current page { $display_pages=$display_pages.$i.' '; } else { $display_pages=$display_pages.'<a href="searchpage.php?'. 'page='.$i.'">'. $i . '</a> '; } } $display_pages=$display_pages.'</p>'; $display_items=''; $start=$nbrOfItemsPerPage*($current_page-1); for($k=1;$k<=$nbrOfItemsParPage;$k++) { $display_items=$display_items.($search_results[$start+$k]).'<br>'; } $display_search_results=$display_pages.$display_items; } echo '<form method="post" action="searchpage.php">'. ' Type your keywords here : <br><br>'. '<textarea cols="65" rows="1" '. 'id="keywords_id" name="keywords">'.$keywords.'</textarea>'. '<input type="submit" name="search_submitted" id="search_submitted_id" value="Search" /> '. '</fieldset>'. '</form>'; echo $display_search_results; ?>
  3. jamesmargolis
    From a dropbox or an online image repository, for example. If the user chooses to upload "from his computer", everything will work as with an ordinary "input type="file"". If the user chooses to upload "from the web", he is to be provided a text field in which he will type the URL of the image/audio/video. I know this is something already implemented in many sites ; for example, if you click on the image icon in the panel at http://math.stackexchange.com/questions/ask, you get exactly what I am looking for
  4. jamesmargolis
    I know about <input type="file" > which allows one to upload files from one’s computer. But now I need a pop-up window that allows the user to choose first if he uploads from his computer or from the internet. How may I achieve that ? This question is perhaps better suited for the "Javascript" or even "AJAX" forum ; if someone advises me to, I will move that question and put it in the appropriate forum.
  5. jamesmargolis
    It works. Thanks! There is no way to mark a topic as solved in this forum ?
  6. jamesmargolis
    I wish to display a text field with two buttons under it, and I want one of the button on the leftmost part (that’s very easy because that's the default), and the other on the rightmost part (this I don’t really know how to implement this). I am currently using something like this : <!DOCTYPE html> <html> <head> <title>Title</title> </head> <body> <fieldset> <input name="words" type="text" id="words" size="60" /><br><br> <input type="button" id="lb" name="leftbutton" value="leftbutton" /> <input type="button" id="rb" name="rightbutton" value="rightbutton" /> </fieldset> </body> </html> With this kind of code, I can adjust the number of to make the other button fit on the far right, but that’s obviously not the right way to do things. Perhaps I should use a table ? How ?
  7. jamesmargolis
    Thanks for your help hansford. Your solution makes the button write something, but the <span> tag is just output "as is" instead of being interpreted as HTML code. The reason I'm putting a <span> around the character is that, if I don't, the text area starts writing right-to-left as in Hebrew after the character has been inserted. And I don't want that behavior since this is meant for texts which short quotes in Hebrew, not texts entirely written in Hebrew.
  8. jamesmargolis
    I’m trying to construct a button that simply writes an "aleph" character into a text area, see below. My code does not work, can anyone tell me why ? How should I fix it ? <!DOCTYPE html> <html> <meta charset="UTF-8"> <head> <title>Example</title> <script type="text/javascript"> //JavaScript code goes here function insertAtEnd(text) { var theArea = document.getElementById("thisArea"); theArea.value += '' + text + '';; } </script> </head> <body> <input type="button" id="aleph" name="aleph" value="Write an aleph" onClick="javascript:insertAtEnd(\'<span>א</span>\');return(false)" /> <textarea id="thisArea"> </textarea> </body> </html>
  9. jamesmargolis
    Now, with the code below I get the correct output except that the preview field appears outside the table even though I declare it inside <?php $text=(isset($_POST['message']))?$_POST['message']:''; $formatted_text=nl2br(stripslashes(htmlspecialchars($text))); echo '<form method="post" action="proceedtopost.php?>'. '<table>'. '<td style width="50%">'. '<fieldset> Write your post here : <br> <textarea cols="50" rows="12" '. 'id="message" name="message">'.$text.'</textarea>'. '</fieldset> <p> '. '<input type="submit" name="submit" formaction="writepost.php" value="Preview" /> '. '<input type="submit" name="submit" value="Sent" /> '. '</p>'. '</td>'. '<td>'. '<fieldset> Your post will appear as follows :<br>'. $formatted_text. '</fieldset>'. '</td>'. '</table>'. '</form>';
  10. jamesmargolis
    As it can only validate html not php content, it would be quite complicated for me to use it in this situation, it seems.
  11. jamesmargolis
    I’m trying to write a post-panel where the user can see the preview of his post to the right of the text area he’s writing into. I tried the following into a file called writepost.php : <?php $text=(isset($_GET['message']))?$_GET['message']:''; $formatted_text=nl2br(stripslashes(htmlspecialchars($text))); echo '<form method="post" action="proceedtopost.php?>'. '<table>'. '<td style width="50%"><tr>'. '<fieldset> Write your post here : <br> <textarea cols="50" rows="12" '. 'id="message" name="message">'.$text.'</textarea>'. '</fieldset> <p> '. '<input type="submit" name="submit" formaction="writepost.php" value="Preview" /> '. '<input type="submit" name="submit" value="Sent" /> '. '</p>'. '</td>'. '<td>'. '<fieldset> Your post will appear as follows :<br><p> '. $formatted_text. '</fieldset>'. '</td></tr>'. '</table>'. '</form>'; There are several things wrong with this code : 1) When the user hits the "Preview" button, I expect writepost.php to be reloaded (this is what happens), and the current content of the textarea to be stored in $_GET['message'] (this is not what happens). 2) Why does my browser output the preview part under the text area (or in other words outputs the HTML table as a single column of two cells), when I insist in my HTML code for the table to be displayed as a single row ?
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