samowns
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Ok bro i create telegram bot and i want to response to connect or response the bot through php ..please find the solution
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sir any solution?
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how to get the value of each input of each data I bring from the db?
samowns replied to yami's topic in PHP Coding Help
use mysqli //your must include your database file $q="SELECT * FROM table_name "; $ok=mysqli_query($con,$q); while($raq=mysqli_fetch_array($ok)){ <td><?php echo $raq[0];?></td>//Here u want to echo any row <?php }?>//Loop Close here -
Hello member's please check my code i set weebhook aleady but bot didnt respond <?php $input= file_get_contents('php://input'); $update= json_decode($input); $message=$update->message; $chat_id=$message->chat->id; $text=$message->text; $token='key'; file_get_contents("https://api.telegram.org/bot$token/sendMessage?chat_id=$chat_id&text=$text"); ?>
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i figure out Thanx elseif (!$_POST["name"] or ["name"] == '0' ){ $sq1=mysqli_query($a,$sq); echo "Not Please Select Name Please"; }
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Please Tell me how am new to php
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Hello Guys My code runs fine but value null is inserting if some one dint select any list name . So wot i want if some one did not select any option query did not run $error shows Here is my code please check and figure it out <?php $error=""; include "db.php"; if(isset($_POST['bt'])){ $date=Date("Y-m-d H:i:s"); $b=$_POST['name']; $res=$_POST['res']; if(!$_POST["res"]){ } if(!$_POST["name"]){ } // Declare variable if(!$_POST["name"] or ["name"] == '' ) { $error .= "Must select the name.<br />";// If not selected, add string to error message } if(!$_POST["res"] ){ $error .= "Must Enter the Reason.<br />"; // If not Enter, add string to error message } else{ $sq="insert into att(name,date,res)values('$b','$date','$res')"; $sq1=mysqli_query($a,$sq); echo "Ok"; // } } ?> <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <meta http-equiv="X-UA-Compatible" content="IE=edge"> <title></title> <link rel="stylesheet" href=""> </head> <body> <form action="pres.php" method="post" accept-charset="utf-8"> <select name="name" > <option value="" >Choose...</option> <option value="mandeep" >Maneep</option> <option value="sahiba" >Sahiba</option> </select> </select> <input type="text" name="res"> <input type="submit" name="bt" value="Ok"> <br> <?php echo"". $error;?> </form> </body> </html>
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i want to embed Bann Script or user deactive or active <?php session_start(); $message=""; ?> <?php include "db.php"; $msg=''; if(isset($_POST['sb'])) { $time=time()-30; $ip_address=getIpAddr(); $name = mysqli_real_escape_string($a, $_POST['eml']); $pass = mysqli_real_escape_string($a, $_POST['pass']); $query=mysqli_query($a,"select count(*) as total_count from loginlogs where TryTime > $time and IpAddress='$ip_address'"); $check_login_row=mysqli_fetch_assoc($query); $total_count=$check_login_row['total_count']; //Checking if the attempt 3, or youcan set the no of attempt her. For now we taking only 3 fail attempted if($total_count==3){ $msg="To many failed login attempts. Please login after 30 sec"; }else{ //Getting Post Values $result=mysqli_query($a,"SELECT * FROM admin WHERE eml='$name' and pass= '$pass'"); $row = mysqli_fetch_assoc($result); $row=mysqli_num_rows($result); //ban user if($row==1) { $_SESSION['user_name'] =$name; header("location:wel.php?msg=Scuessfull eml"); mysqli_query($a,"delete from loginlogs where IpAddress='$ip_address'"); } else{ $total_count++; $rem_attm=4-$total_count; if($rem_attm==0){ $msg="To many failed login attempts. Please login after 40 sec"; }else{ $msg="<b>Please enter valid login details.<br/>$rem_attm attempts remaining <b>"; } $try_time=time(); mysqli_query($a,"insert into loginlogs(IpAddress,TryTime) values('$ip_address','$try_time')"); } }} if(isset($_SESSION['user_name']) ){ header("location:wel.php?msg=Scuessfull "); ?> <?php } ?> <form class="login-form" action="adminscure.php" method="post" > <div class="message"><?php if($message!="") { echo $message; } ?></div> <body id="LoginForm"> <div class="container"> <div class="main-div"> <div class="panel"> <h2>Admin Login</h2> <p>Please enter your email and passwords</p> </div> <form id="Login"> <div class="form-group"> <input type="name" name="eml" class="form-control" id="eml" placeholder="name"> </div> <div class="form-group"> <input type="password" name="pass" class="form-control" id="pass" placeholder="Password"> </div> <div> <input type="submit" name="sb" class="btn btn-primary"> <div id="result"><?php echo $msg?></div> </div> </form> <?php function getIpAddr(){ if (!empty($_SERVER['HTTP_CLIENT_IP'])){ $ipAddr=$_SERVER['HTTP_CLIENT_IP']; }elseif (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])){ $ipAddr=$_SERVER['HTTP_X_FORWARDED_FOR']; }else{ $ipAddr=$_SERVER['REMOTE_ADDR']; } return $ipAddr; }?>
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I want to know that if i login as admin wel.php open and if i want to login as mod so mod.php open programs runs fine but when i login as admin or mod same session work i want different page scure
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<!DOCTYPE html> <html> <head> <style type="text/css" media="screen"> .ss { border-width: 1px; border-style:solid; width: 100px; height: 100px; </style> <meta charset="utf-8"> <meta http-equiv="X-UA-Compatible" content="IE=edge"> <title></title> <link rel="stylesheet" href=""> </head> <body> <form action="index.php" method="post"> <table align="center" class="ss"> <tr> <td>Name<input type="text" name="name"> </td> </tr> <tr> <td>Pass :<input type="password" name="pass"> </td> </tr> <tr> <td>Email<input type="text" name="eml"> </td> <tr> <td><input type="submit" name="sb"> </td> </table> </form> </body> </html> <?php include "db.php"; session_start(); if(isset($_POST['sb'])) { $name=mysqli_real_escape_string($con, $_POST['eml']); $pass=mysqli_real_escape_string($con, $_POST['pass']); $usr=mysqli_real_escape_string($con,'user'); $std='std'; $type='admin'; $qer="select * from users where eml='$name' AND pass='$pass' AND type='$type'"; $sql=mysqli_query($con,$qer); $qer=" select * from users where eml='$name' AND pass='$pass' AND type='$std'"; $sql1=mysqli_query($con,$qer); $qer=" select * from users where eml='$name' AND pass='$pass' AND type='$usr'"; $sql3=mysqli_query($con,$qer); $fe=mysqli_fetch_array($sql); if(is_array($fe)) { $name=$name; $pass=$pass; { header("location:wel.php?msg=Scuessfull login"); } echo "Admin of this site"; } else if($fe=mysqli_fetch_array($sql1)){ if(is_array($fe)) $name=$name; $pass=$pass; echo "Moderator of the site"; { header("location:mod.php?msg=Scuessfull login"); } } else if($fe=mysqli_fetch_array($sql3)){ if(is_array($fe)) $name=$name; $pass=$pass; $_SESSION['eml'] =true; header("location:sim.php?msg=Scuessfull login"); echo "Simple user this site"; } else { echo "invalid pass"; } } ?>
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Hello guys am using mysql . login admin panel works fine .but when i use password=1' or '1' = '1 its also working some one please help me i want to safe admin panel here is my code if(isset($_POST['sb'])) { $result = mysql_query("SELECT * FROM admin WHERE eml='" . $_POST["eml"] . "' and pass= '". $_POST["pass"]."'"); $row = mysql_fetch_array($result); if(is_array($row)) { $_SESSION["eml"] = $row['eml']; hash($_SESSION["pass"] = $row['pass']; } else { $message = "<font color='#FF0000'>"."Invalid Username or Password!"."</font>"; } } if(isset($_SESSION["eml"])) { header("Location:./useradmin.php"); }
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ok
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query runs f9 but sir instead of 1 n 0. i want if 1 fees pending .if 0 no fees pending
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here is loginact.php i just want if user login see the profile restriction means if admin login they can change ..i think i need to put one field 'type' admin or user..plz somone figure out..am new to sql this code is running <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <link href="css/style.css" rel="stylesheet"> <head> <style> .red { color:#F00; font-size:15px; } </style> <?php include "header.php";?> <?php include ("db.php"); $error=""; ?> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head><?php session_start(); ?> <?php if(isset($_POST['sb'])) { $a=$_POST ['eml']; $b=$_POST['pass']; $c="select * from users where eml='$a' && pass='$b'"; $s=mysql_query ($c); $row=mysql_num_rows($s); if($row==1 ) { $_SESSION['eml']=$a; header("location:fetch.php?msg=Scuessfull login"); } else{ $error= "Invalid Email or Password *"; } } ?> </head> <body><?php if(isset($_GET['logout'])) { session_unregister('eml'); } ?> <h3>Admin Login </h3> <div class="usr"> <form action="loginact.php" method="post" required="required"> <div class="col-lg-6"><div class="input-group"> Email id<input type="text" class="form-control" name="eml" required="required"/> <br /> <div class="red"><?php if($error!="") { echo $error; } ?></div> Password<input type="password" class="form-control" name="pass" required="required"/><br /> <input style="width:100px;" class="btn-success k" type="submit" name="sb" value="Login"/> </form> </div> </body> </html>
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if you r using skype so logout skype n hide then ur server ill show green light .i was having same problem
