trq

Or, check out: http://proemframework.org/docs/signal-component.html Yes, I'm pimping my own framework, but it is a decent example of the concept.

You would likely want to validate this with JavaScript and PHP.

Sending email from one server and making it look like it has come from another mail server will usually end up with the email either going to trash, or not being excepted at all.

Have a look above the Post / Preview buttons.

Your going to need to post your current code. In tags please.

You don't select any field from the database called "filename".

This topic has been moved to Other Libraries and Frameworks. http://www.phpfreaks.com/forums/index.php?topic=359340.0

Makes no sense any other way.

Your form element names are different to that used in the php code.

This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=359389.0

And where exactly is that code is relation to the javascript?

finished = <?php echo $somephpvar; ?>;

Can you post your php code?

It helps if you describe your problem.

This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=359385.0

See preg_match.

You should use jQuery's ajax() method instead. It has a statusCode event which is prefect for this situation. See http://api.jquery.com/jQuery.ajax/

From memory IIS6 does not support url rewriting. You need at least IIS7.

Did you read my last two replies?

Cool. What is the problem?

Actually, looking at it again, there would be an unclosed <font> tag. Fix that and you should be golden. Better still, don't use font tags, they are pretty 1995.

My code should work fine. What do you see when you view the source of the page?

This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=359282.0

$body .= '<b><font color="#006699"><img src="' . $num . '">: ' . $user_name . ':

There is a know bug in php's cgi implementation that allows a client to view the source of a page by supplying a query string without any = sign in it. eg; /?-s is enough to trigger it. At least the first part of looks like this issue.