.josh

ah okay I know what's going on. Since it's a text file, each line ends with '\n' which signifies the end of for editors it needs to be trimmed off in order for the preg_replace to work: <?php // names that you got from a flatfile $textfile = 'data.txt'; if (file_exists($textfile) && is_readable($textfile)) { // read the file into an array called $users $users = file($textfile); } // trim '\n' from each user foreach($users as $key => $val) { $users[$key] = trim($val); } // example string $content = "Here are a few names in my text file ben ryan and dave!"; // for each user in the array, make a new array with a linked version of the user foreach($users as $name) { $linkednames[] = "<a href='path/to/$name'>$name</a>"; } // in order to use preg_replace down there, you have to add / / around the name // to specify the start and end of the search string. so we're going to make an array // named pattern with the names like that. foreach($users as $name) { $pattern[] = "/$name/"; } // preg_replace accepts arrays as arguments. Basically it does all the hard work for you // internally it makes a loop to search through $content for each item in the $pattern array // and when it finds it, it replaces it with the item in the same key position as $linkednames // array. pretty nifty, huh? You can of course assign the results of preg_replace to a variable // instead of echoing it. echo preg_replace($pattern, $linkednames, $content); print_r($users); ?>

can you post the full relevant code? maybe you made a clerical error somewhere..

yes you can use php to generate an actual blah.jpg http://us2.php.net/gd

umm...do print_r($users); see if you really do have an array there...

minor bitch, but do..while loops are meant for conditions that don't have a set amount of iterations to them, or for when you don't know how many iterations there will be. If you know how many iterations there will be, use a for loop instead. It's a minor detail and having an outside $i var increment like that works too, but I mean, that's the point of a for loop for ($i = 1; $i < 135; $i++) { // code here } Just FYI, regardless of how you loop it, understand that php is a server side language. It will completely run its course before spitting things out to your browser. Depending on how much content is on those target pages, it may take a while to see some results, and your script may even time out. In a case like this, I would probably suggest using javascript to make a loop and send requests individually, instead.

well, using a regular flatfile with names on separate lines vs. a xml file is more a matter of preference. To be honest, since all you're wanting to do is take a chunk of text and search through it for a name, xml is probably overkill. I mean, you don't really need all the extra bells and whistles associated with using a xml file. Finding occurrences of the user's name in the chunk of text is the main trick here. It really depends on what's in that chunk of text, vs. how accurate you want it to be. Are you only wanting to link "valid" names? That is: You would of course want this: 1. I know this girl named Jane who... but, do you want it to link this? 2. I know this girl namedJanewho... Well anyways, here is an example. It does include making links like in #2... // example array of names that you got from a flatfile $users = array("Jane","John","Mike"); // example string $content = "I know this girl named Jane who likes this guy named John but John likes this guy Mike!"; // for each user in the array, make a new array with a linked version of the user foreach($users as $name) { $linkednames[] = "<a href='path/to/$name'>$name</a>"; } // in order to use preg_replace down there, you have to add / / around the name // to specify the start and end of the search string. so we're going to make an array // named pattern with the names like that. foreach($users as $name) { $pattern[] = "/$name/"; } // preg_replace accepts arrays as arguments. Basically it does all the hard work for you // internally it makes a loop to search through $content for each item in the $pattern array // and when it finds it, it replaces it with the item in the same key position as $linkednames // array. pretty nifty, huh? You can of course assign the results of preg_replace to a variable // instead of echoing it. echo preg_replace($pattern,$linkednames, $content);

1) this is 2 fold. If user is using correct username but wrong password, you can add an int type column to your user account table that increments each failed login attempt and then in your login processing script, add a condition to check that column and spit out a denial message if max attempts is reached. This doesn't really help if the username is wrong though, so part 2 would be to have another table called "failed_login_attempts" or something, in which you would pretty much do the same thing as before, except by ip address instead of username. That's about as best you can do, because even that would fail to implement a "3 strikes and you're out" policy, if they are using a proxy server or something (changing ip address). You would, of course, need to add some sort of way to have that column reset to 0. You could make the user contact someone who could manually do it if they can prove it's them. You could have it automatically reset after x amount of time. 2) This is also somewhat tricky. sessions are governed on the client, via a cookie. You don't really have control over what goes on with that, unless the user is making requests to the server, so if they login and then walk away from the computer, there's no way for you to automatically end that session on their end. However, if you're talking about having them being shown as "offline" like on a forum or something, you add a time type column in your user account table called "last_active" and another column type int called "status". When user logs in, change status to 1 (signifying they are "online.") "Users online: " query would be based on status being set to 1. Each time the user makes a request to the server, update it Setup a cron job to run every x time to check the current time vs. last_active and set status to 0 if it's more than x minutes and x seconds. 3) have a column in your user account table that holds their ip address. Each time a user logs in, update the ip address(using $_SERVER['REMOTE_ADDRESS']) . As long as they are considered "online (see #2), if another login attempt is made, check the status and ip and if it's set to 1 and ip don't match, then deny it.

If you don't have a database, you're going to have to use a flatfile, or make a really long array of usernames and have that array included on all your pages. You're basically going to take the content where a name may appear, and make a loop, looping through each name, and do some regex to search for that name and replace it with anchor tag wrapped around it. -make a list using a file/array (since no db) -make a loop -use regex to find and replace in the content. there's your battleplan. If you get stuck on some code, post it and we'll try to help.

well basically you would first run a basic query using the id like "select status from table where id = '$id'" then do a condition based on that. assuming you retrieve it and put the status in $status: if ($status == 'active') { // it's valid, do your code here } else { // it's not valid. do something here. Log it, throw out an error, w/e }

well I don't really know a whole lot of js myself, but I think if you assign an id or name to an element, you can use js to onclick, add content to that element block (your extra input field for your form). As far as letting php know that there's a new input element in your form..I think the most efficient method for that is to use an array as your name in your input element. Example: <script = 'javascript'> function addanotherelement () { <!-- js code here --> } </script> <form id='myform' name = 'myform' action = 'target.php' method = 'post'> <input type = 'text' name = 'blah[]'><br /> <button onclick='addanotherelement();'>add another</button> <input type = 'submit' value = 'submit'> </form> The key there is name = 'blah[]' makes an array. Each time you add a new input element to your form, it will simply say name = 'blah[]' and when the form is submitted, all of the information can be accessed by $_POST['blah'][0] // first text field $_POST['blah'][1] // 2nd text field etc... Obviously that is not how to really code the javascript. I'm going to move your thread to the javascript section so someone can help you on that part....

okay well then yes, go for some ajax. Virtually every beginner ajax tutorial shows you how to do what you wanna do, so doing a "ajax tutorial" google search will yield lots of results.

an example of this would be: index.php <form action = 'test.php' method='post'> <input type="text" name="wall"> <input type="submit" value="Post Comment!"> </form> test.php <?php if ($_POST['wall']) { echo $_POST['wall']; } ?> Yes, you can use ajax to make a request and update an element on the page without refreshing the whole page.

if you want php to know what the user put in the form, a request has to be sent to the server, via the get or post method, and it would be accessed via the get or post array. That's your only option with php.

use $_POST['wall'] instead of $wall

What you are wanting to do is a very basic ajax method. Virtually all beginner ajax tutorials explain how to do what you are wanting to do. To be honest though, you don't really need to do ajax. All you're wanting to do is add an extra element to your form... just do it with javascript. The point to ajax is needing to get more information from the server without refreshing the page. This is useful for instance with multiple dropdown selections, where dropdown #2 data is based on dropdown #1 selection sort of thing. But you're just wanting to add a basic form element. No need to bother the server for that. Just use a javascript onclick call.

If you want to do this only with php, you're going to have to have page reloads. You can use a session variable for data persistence. Your other options include using a clientside language like javascript, or a mix between php and javascript, using ajax. ^ ajax still involves sending requests to the server, just not a full page reload. edit: Only thing you got to consider though is that using javascript or ajax can cripple your site, as people can turn it off. If you wish to go that route, I suggest first doing it the strict php method and then doing it the js or ajax method on top of that, so that your script has something to fall back on if js is disabled.

if everything works when you hardcode it but not when you use the variable, then the problem is the variable. Did you name your input 'dropdownbox' (spelled right?) in your form? did you use method = 'post' in your form tag?

After making sure the id value is the correct format (if using integers, check to make sure it's an integer, use mysql_real_escape_string on the variable, etc...), since you are expecting to only show/alter/whatever active clients, do a query check on the passed variable to see if that client is active. If not, then kick an error message or whatever.

okay, so what are you intentions here? You want a user to enter in something in a form, then take that value, search your database for it, and return a thumbs up if it finds it, thumbs down, if not?

unless your doSelectAndGetRow is taking your post array and selecting info based on it and returning results into the same post array...which I don't really see why it would be (I'm not psychic, but honestly I've never seen anybody do something like that, lol) your post array is being assigned whatever is in that method call. Maybe nothing at all and it's returning true or false. In any case, by the time it gets to $w9status = $_POST['w9'] it's more than likely not assigning anything at all. Or at best, a boolean value (true/false). But again, I'm not psychic.

so then just add some css or html like in my example, before the include.

oh and I forgot to increment $x : $ribbon_select = 'select * from phpbb_medal_user'; $ribbon_result = mysql_query($ribbon_select) or die("$ribbon_select does not make any sence;<br>" . mysql_error()); $x = 0; while ($list = mysql_fetch_assoc($ribbon_result)) { echo $list['medal_id']; echo (($x % 9) == 0) ? "<br />" : " "; $x++; }

you're trying to run a query on a result source from another query. remove the mysql_query from $ribbon_select, just put it in quotes as a query string: $ribbon_select = 'select * from phpbb_medal_user'; $ribbon_result = mysql_query($ribbon_select) or die("$ribbon_select does not make any sence;<br>" . mysql_error()); $x = 0; while ($list = mysql_fetch_assoc($ribbon_result)) { echo $list['medal_id']; echo (($x % 9) == 0) ? "<br />" : " "; }

ermm...what exactly do you mean? PHP is not in charge of colors/fonts. That's straight html/css. are you wanting the user to be able to pick from a list? make a form with a dropdown or something, and have php echo out the html/css with the color/font choice. But if you're looking to just have it output white in general..that's straight html/css <style = 'text/css'> #somestyle { color: #ffffff; } </style> <p id='somestyle'>example using css</p> <font color = 'white'>example using html</font>

example: $sql = "select medal_id from table"; $result = mysql_query($sql); $x = 0; while ($list = mysql_fetch_assoc($result)) { echo $list['medal_id']; echo (($x % 9) == 0) ? "<br />" : " "; }