corbin

God I hate Mac's advertising. I wish Windows would advertise more harhsly back lol. The thing that bugs me is that the public is dumb enough to believe the Apple ads. Now to go find the 3 new ones....

So I guess that's why the difference quotient works since it's a limit approaching 0. Nifty.

Hrmmm, I guess that makes sense since you're trying to find the change at one specific point, hence the smaller the bottom is, the more accurate the top would be. I think? I guess I shouldn't have assumed they were the same. It seems like they are in some situations though, but I guess not always hehe.

I am grieved by your opinion on Runescapes graphics. Recently (Year ago) they did an overhaul, making runescape considerably better than WoW and in my opinion, Silkroad as well. Is this opinion based on the idea before Runescapes new graphics or after its new graphics? It even uses a /video card/ now. Unfortunately for all those laptop users who have on-board can't run runescape anymore. (Not HD at least.) Errr.... You have looked at RS HD, right? In my opinion the graphics are still pretty lame. Just of curiosity, do you play RuneScape? I've basically quit it, but every now and then I'll play it for like 2 weeks, then quit it again. lol. I currently happen to be in a playing-it rut. I really don't remember grinding being too bad in SRO, but I only played it till like level 18 before I got busy in real life and never returned to it. Well, since I've never played retail Lineage 2 (by which I mean the servers run by NCSoft), I've never really cared about a story line. I'll be the first to say that I could never play retail servers because they're only 1x exp, and I like to play on 30-50x experience servers. (If NCSoft ever opened high rate servers, I would <3 it.) Also, in MMORPGs, I prefer killing people and collecting items over storyline. There's never been a game I've played in which I actually enjoyed quests.

We really haven't gone through much. Finding out if something is differentialable at points, finding derivatives with the difference quotient, the power rule, chain rule, multiplication rule (I don't think it's called "multiplication rule": f(x) = ab; f'(x) = ab' + a'b) and a few other things. Oh, and we have not done any integration yet (although we have gotten very slightly into it in chemistry). I typically try to think of it in different ways. The first thing I always think of is the slope of a tangent line, then I think of the change of something compared to the change of something else. When ever I come across word problems like those, I try to think of it as the change of something compared to the change of something else, (for example, when the time changes 1 minute in that problem, the volume changes 10 cubic ft). Chemistry is what made the rate of change thing really set in. It didn't occur to me until about a week ago that delta A/delta B in chemistry is the same as dA/dB in math... So then I realized (although I already knew to some extent) that taking the derivative of something in respect to x is just finding the change in something as compared to the change in x. I think I have a fairly good grasp of everything that we've done so far in calculus. It was just these word problems threw me I guess since there were so many steps, and I'm terrible at finding relations between two things.

Make sure the charset on the table is UTF-8, and make sure the browser knows the page being output is UTF-8. Telling the browser that the page is UTF-8 is pretty easy: header("Content-Type: text/html; charset=UTF-8"); before any content is output

The game I've played the most over the past few years is Lineage 2. It's not very big in North America, but in Europe and Asia it's quite large (especially Asia, probably since the company that makes it is Korean). I think the PvP in it is quite good, but as far as grinding goes, I can't speak for that. I always played private servers (a euphemism for servers that illegally run files stolen from NCSoft) that had modified rates so that leveling was much faster. (So, yeah L2 can technically be free, but not without violating multiple laws.) The only other MMORPG that I've played for a decent amount of time was Runescape. I must suggest that you don't play RuneScape though. As far as free MMORPGs go, I must praise RS. It's free content is quite extensive, and the monthly subscription cost for members (in the sense of paying members) is fairly cheap. The upsides are that it has a huge community, lots of active people/clans/trade/combat and so on. It's kind of cool that you can go any place in the game and see people. Last I checked, usually around 50,000-200,000 people are playing at any given time, distributed over 150 or so servers. The game play is quite addictive, and you can waste hours without realizing it. The downsides are that it's not really aimed at older people. I played RS from about 6th till 9th grade. Most of the people on there are anywhere from 10-20 years old, but the distribution of people definitely leans towards the bottom of that range, most people probably being 13-16. Also, if you like graphics, the graphics are quite terrible. Considering that it's a Java Applet, the graphics are amazing, but compared to other current games they're horrible. Overall, I would not recommend playing RuneScape, just thought I would say it since as far as free MMORPGs go, you're pretty limited. Silk Road Online is also worth mention. It seems to have gone downhill, but at its release I played it a bit, and it was decent. It's basically a ripoff of all the big MMORPGs. Then there's the non-free ones: Personally I tried World of Warcraft for 2 weeks and couldn't stand it. It was too grind based, the quests were pretty lame and the graphics (in my opinion) look like children's drawings. I played the Korean open beta of Aion, and it was pretty awesome. (The same company that makes Lineage ][ makes Aion, so I'm biased due to my weird love of Lineage 2.) I never got around to buying the North American release of it (it's 50$ + 15$/month by the way, a quite high price), and I've heard mixed feelings from old Lineage 2 friends about it. Some say the PvP is retarded and the game gets old quickly, but some love everything about the game. Blah! Wish I could think of more games off the top of my head lol.

Ahhh, I guess that would be where I was getting confused this morning (well, yesterday morning now). Your math does make sense, and I checked a second ago, and that's what the book says is the answer. I think my class probably would have worked it a little differently though (although really you way seems like it would be easier down the road if problems grow more complex). We haven't had to find a rate based off of a rate yet. To be honest, I was actually reviewing for a test* last night. I had 90% of the chapter down, but the last section threw me off a bit. I randomly picked questions to see if I could work them, and I'm wondering now if I picked one she didn't expect us to know how to do. On the test there was a related rate problem, but it was much simpler (it was like the planes one). *Hopefully it doesn't bug you that it was technically test review and not homework. In a way I would think it's better since it wasn't work we technically had to do. Anyway, thanks for your help! It seems like the farther I get in math classes, the worse I realize I am at math. I think I get this problem now, but now I need to do a few others to make sure I really get it hehe.

Yeah, but that binds you to 2 payment processors.

Loading it into the database would probably be more efficient.

Hrmmm, how would I solve that last equation? Or is that not the one to be solved? IT doesn't seem like there's a way to plug stuff in without just getting dh/dt = dh/dt. (Also, I see where I should have been plugging in for r earlier instead of h.) As for the step before that: h = (4V/3pi)^(1/3) dh/dt = (1/3)((4/3pi)V)^(-2/3)(4/3pi)(dV/dt) dh/dt = ((4/3pi)V)^(-2/3)(4/9pi)(10) But then I don't know V? Bleh, got to head to school now, but I do plan on actually figuring the rest of this out later (I think later I'll try finding the derivative at the V = (3pi/4)h^3 step). (In other words, ignore this post until later ;p.) I actually have never checked the rules in regards to homework x.x. But I lucked out:

Hrmmm, I hate posting about math homework, partly because it's homework, and partly because I hate whenever I can't figure out math myself. Yes, I realize this is an extremely long post. Feel free to just tell me how to do it instead of reading my rambling for 3 pages about what I've tried. Anyway, in class we've been doing stuff with related rates... In most cases it's fairly simple, but there are a couple of things that have me stumped. (By a couple I mean two.) The first one: "An air traffic controller spots two planes at the same altitude converging on a point as they fly at right angles to each other. One plane is 150 miles from the point moving at 450 miles per hour, and the other plane is 200 miles from the point moving at 600 miles per hour. At what rate is the distance between the planes decreasing?" (See attachment for a drawing.) Proof that I have tried: So, I'll call the distance between the plane 150 miles away a, and the other distance b. The position of the plane 1 (in other words a): a = 150 - 450t For plane 2: b = 200 - 600t (One of the other questions was how long until they collide. That was easy since it was just 200-600h = 150-450h then h = 1/3 [or you could set one of them equal to 0 since the collision is when the distance from the point is 0, but they would have to be equal to prove that anyway].) So, the distance (I'll call that c) between the planes should be c = a^2 + b^2. Simple enough... So the change in distance with respect to time should be: (Edit: I must be tired... Just realized that I got the freakin' distance formula wrong earlier... Wonder if it would've worked out if I hadn't.) (d/dt)© = (d/dt)(a^2) + (d/dt)(b^2) dc/dt) = (d/dt)(a^2 + b^2) dc/dt = (d/dt)(150^2 - 300(450t) + 450^2t^2 + 200^2 - 400(600t) + 600^2t^2) Then distribute the d/dt: dc/dt = 0 - (300)(450)(dt/dt) + 2(450^2)(t)(dt/dt) + 0 - 400(600)(dt/dt) + 2(600^2)(t)(dt/dt) dc/dt = 135000 + 405000t - 240000 + 720000t dc/dt = 1125000t - 105000 The reason I know that is wrong is because the book says -750 mph and that is definitely not equal... But, I also know that the units won't be correct. I should end up with miles/hours. It has hours, but it's just miles, not miles/hours.... So at some point I managed to take out a <something>/hours that I should not have. Which makes me wonder what information I was given or can figure out (and it be a constant) that would relate <something> to hours with hours dividing it.... I guess I know that the derivative of a is 450 miles/hour, and I know that b' is 600 miles/hour. Oh wow! I think I just figured it out! No, just worked it out on paper, and I get some weird answer. Well, that means that going back to c = sqrt(a^2 + b^2) when taking the derivative of a and b, those can be substituted (I think?). But that still leaves a problem, since it comes up with: c = .5(a^2 + b^2)^-.5(2a + 2b) That doesn't make sense though. I don't think the chain rule would be correct there. Anyway, I keep running in circles with that problem. Edit: Wow... Apparently I should've googled. http://www.cliffsnotes.com/WileyCDA/CliffsReviewTopic/Related-Rates-of-Change.topicArticleId-39909,articleId-39897.html deals with a different problem, but it did make me realize that I was going about it wrong. Apparently I need to take the derivative and then substitute (which makes more sense actually). (Also, I got the distance forumla wrong earlier, so not sure if it would have worked out had I not. Guessing it would've still been wrong because I didn't need to find the position dynamically since the derivative of the distance would be the same at any two positions.) Answer: c^2 = a^2 + b^c 2c(dc/dt) = 2a(da/dt) + 2b(db/dt) Then just plug in c (250), a (150), b (200) and da/dt (450) and db/dt (600) and solve for dc/dt.... And 750 The other problem (well type of problem) that confuses me is as follows: "At a sand and gravel plant, sand is falling off of a conveyor and onto a conical pile at a rate of 10 cubic feet per minute. The diameter of the base of the cone is approximately 3 times the altitude. At what rate is the height of the pile changing when the pile is 15 feet high?" What I know: V = (3pi/4) * hr^2 dV/dt = 10 ft^3/minute d = 3h r = 3h/2 What I'm trying to find: dh/dt when h = 15 So, what I've gotten so far: V = (3pi/4) * hr^2 dV/dt = (6/4)pi * r (dr/dt)(dh/dt) That's all fine and good, but I don't know dr/dt and have no way to find it, so I must go back and substitute something. I've noticed (and the teacher probably told us at some point) that usually it's a good idea to replace in something that gives you the variable that you're solving for the derivative of (or maybe that's just because usually the value of that variable is given hence a constant). V = (3pi/4) * hr^2 V = (3pi/4) * h(3h/2)^2 V = (3pi/4) * h(9h^2/4) V = (3pi/4) * (9h^3/4) V = (27pi/16) * (h^3) dV/dt = ((3*27pi)/16) * h^2 * dh/dt 10 ft^3/minute = ((3*27pi)/16) * h^2 * dh/dt Then the craziness: dh/dt = 10/(((3*27pi)/16) * h^2) dh/dt = 10/(((3*27pi)/16) * (15)^2) I thought that maybe I shouldn't use the chain rule when derivating (don't think that's a word) h^3, but using the power rule ends up in a wrong answer as well. Also, I thought maybe I'm replacing r too early, but I'm not.... If someone will explain to me where I'm going wrong (I've even tried things I know won't work), that would be wonderful! Also, tl;dr: Find the problems and explain to me how to do them please . Basically I think what my problem is is determining what is constant and what is not and at what stage in a problem to replace something.

You can't define a function inside of a function (well technically you can, but it's not suggested). The first time the function is run, the variable will be empty hence no call back being executed. As for the slowness.... The date string generating could probably be handled better (using DATE_SUB instead), but besides that, nothing seems inherently wrong SQL-wise. Have you done an EXPLAIN on all of the queries that you're using to make sure indexes are probably being used?

The ::1 is the IPv6 address for localhost. It looks like something is causing a fault in Apache. (Could be a memory error or just an extension is exiting on an error.) I would guess it's PHP related since that's all that you've changed. Try changing the settings back and see if that fixes it. If it does fix it, then I would guess that something is wrong with the PHP install in regards to the SMTP stuff.

We will need to see code to know. I would guess either your DB needs indexes or some other optimizations or your PHP coding is bad.

Oh wow.... Never knew that PDO cared how big the MySQL buffer size was lol.

(Ignore nosy post if you want.) Your girlfriend put a keylogger on your computer? Is she crazy or paranoid or what?

Eh, kind of, but it's not limited to web applications (in the sense of inside a browser). It's basically the concept of storing stuff on a server instead of local workstations.

Hmmmm, you're representing the blob value as a string which means that it could be getting messed up with that. (Although really I think it's something else since that wouldn't explain why it would cut off at exactly 1MB.) It might be worth a try to try using the bind method of PDO to make a prepared statement. Something like: $q = $db->prepare("INSERT INTO someTable VALUES(?)"); $q->bind($content, PDO::PARAM_LOB); Other than that, max_allowed_packet has been set to something above 1MB, right? (To make sure the change is registering, you could do "SHOW VARIABLES WHERE Variable_name = 'max_allowed_packet'".)

..... Most people?

The short answer is no. The medium answer is: Technically maybe yes with JS also. The long answer: Feasibly? No. PHP is not the only thing that controls buffering. Apache can buffer, and the web browser can buffer. Also, I would imagine most browsers don't render as HTML is received.

Are you sure that the CD drive isn't burned out? Does it spin at all?

(There's probably one aimed at non-developers too, but that's the one that I had favorited.)

I love method chaining. I hardly ever use it personally, but it's very convenient when it is usable. (jQuery without method chaining would be a lot more typing for example.)

Hmmm, sounds like you should maybe look into AJAX instead.