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Everything posted by Barand
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No one that understands the sanity in adding two dates.
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Foreach () takes an array and loops through it. You have the array, $dpts, from which you created the comma-delimited string $departmento.
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Use code tags ( <> button in toolbar) when posting code. lol
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You are getting an error on $_REQUEST['step'] So perhaps that is is the one you should be checking with isset() ?
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If you can't remember the manual is there to jog your memory
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Change 'options' => array_values($category_str) to 'options' => $category_str;
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for ($i=$y+1; $i >= $y-11; $i--)
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There are several things in this job that can lead to insanity. One of them is accepting free-form text as input. It only takes a small spelling mistake (like your "strops" above) and the whole thing collapses like a house of cards.
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It could be they have an ancient version of PHP that doesn't support [..] array definition syntax. To verify try array( 'id' => $_GET['id']) instead of [ 'id' => $_GET['id'] ]
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Rerunning #3, #4, #5 is a definite no-no. You could end up with completely different set of ids. That was, as previously stated, a one-off exercise. How do you create the csv at present? How many test_db records do you typically add at a time? How often do you have new whiskies?
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You could try reading thara's post again and use the function he gave you. edit - alternatively you can do it in PHP $dtobj = new DateTime($row['date']); echo $dtobj->format('d/m/Y'); //--> 23/01/2017, for example
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That is what that query was designed to do - just the latest record with price and date plus the average price. When you list all the results for a whisky, what do you want to show?
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How to check if two columns match from joined tables?
Barand replied to robatojazzo's topic in PHP Coding Help
Sorry, I forgot to change it to INNER JOIN in that last version of the query. -
How to check if two columns match from joined tables?
Barand replied to robatojazzo's topic in PHP Coding Help
There is a "Donate to me" link underneath my avatar on the left. Thanks. -
url_img and whsky_id are not in the fields selected in the query.
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You have left the id hard coded instead of " = :id ". This version below may also be more efficient SELECT w.whisky_name , price , date , avprice FROM test_db t JOIN whisky w USING (whisky_id) JOIN ( SELECT whisky_id , AVG(price) as avprice FROM test_db WHERE whisky_id = :id GROUP BY whisky_id ) avcalc USING (whisky_id) ORDER BY date DESC LIMIT 1;
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Then SELECT w.whisky_name , price , date , avprice FROM test_db t JOIN whisky w USING (whisky_id) JOIN ( SELECT whisky_id , AVG(price) as avprice FROM test_db GROUP BY whisky_id ) avcalc USING (whisky_id) WHERE w.whisky_id = 1 ORDER BY date DESC LIMIT 1;
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Is the average price the only thing you want to show as a result of the query on that page?
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In records.php, for example, if you want the whisky name then you need to join the test_db table to the whisky table SELECT whisky_id , date , whisky_name as name , price FROM test_db INNER JOIN whisky USING (whisky_id) -- required to get the name WHERE t.whisky_id = :id ORDER BY date DESC
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How to check if two columns match from joined tables?
Barand replied to robatojazzo's topic in PHP Coding Help
Change query to SELECT rEmail , eMail , c.fullname FROM realtors r LEFT JOIN customers c ON pow(clatitude-rlatitude, 2) + pow((clongitude-rlongitude)*cos(radians(rlatitude)), 2) < pow(willtotravel/69.13, 2) ORDER BY rid, id -
If you haven't already, add an index to test_db on the whisky_id column. CREATE INDEX `idx_test_db_whisky_id` ON `test_db` (whisky_id);
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How to check if two columns match from joined tables?
Barand replied to robatojazzo's topic in PHP Coding Help
Change LEFT JOIN to INNER JOIN. That way only realtors with customers will be found. -
It's a one-off operation so slowness isn't a real issue.
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Better eyes than me. I could barely make out the last line of that screenshot.
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works for me mysql> INSERT INTO whisky (whisky_name) -> SELECT DISTINCT name -> FROM test_db -> ORDER BY name; Query OK, 2 rows affected (0.04 sec) Records: 2 Duplicates: 0 Warnings: 0