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pocobueno1388

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Everything posted by pocobueno1388

  1. pocobueno1388
    Laptop, just because you can bring it on the go Eyesight or Hearing
  2. pocobueno1388
    Coke. I'm not sure what you mean by that, because isn't Pop and Coke the same thing? Coke is also a brand name, but some people interchange the words pop, coke, and soda. I will just go with coke...hah. Hamburger or Hot dog
  3. pocobueno1388
    Here is my info - Screen Resolution: 1024 x 768 Firefox Version: 2.0.0.11 I attached a screen shot of what the table looks like to me. [attachment deleted by admin]
  4. pocobueno1388
    Cola. I don't like the strong taste of coffee. If I do ever drink it, you would never know it was coffee because I completely drown it out with sugar and cream Dog or Cat
  5. pocobueno1388
    Paypal?
  6. pocobueno1388
    In Firefox your fiction/about table aren't coming together right, the images are going on different lines and it's all messed up. Other than that, it looks great, IMO =]
  7. pocobueno1388
    It's not even the height that keeps changing...its the font size, the size of the logo, and the height (which I am sure is caused by the other two). As mentioned before, I would do something else with the navigation. Overall the site doesn't "wow" me at all...but I guess it passes for descent.
  8. pocobueno1388
    What are the errors? Also, you aren't defining your variables <?php class user_traits { var $id; var $password; //...etc
  9. pocobueno1388
    Well, if there are no results, then your while loop isn't going to execute any code in between. So I'm assuming no results are being returned.
  10. pocobueno1388
    Change include('functions.php); To include('functions.php');
  11. pocobueno1388
    But if you change $limit to "10" it works? That doesn't make sense...
  12. pocobueno1388
    <?php $sql = "SELECT * FROM beepbopboop WHERE entry_id = '$entryid' ORDER BY id DESC"; $result = mysql_query($sql, $conn) or die(mysql_error()); if (mysql_num_rows($result) < 1){ //no results returned } else { //results found } ?>
  13. pocobueno1388
    Did you change this line $query = "SELECT * FROM goldies WHERE Sender='$username' LIMIT $offset,10"; To $query = "SELECT * FROM goldies WHERE Sender='$username' LIMIT $offset, $limit";
  14. pocobueno1388
    Here is a solution <?php $date = explode('/', $_POST['release_date']); $release_date = $date[2].'-'.$date[1].'-'.$date[0]; $release_date = date("Y-m-d", strtotime($release_date)); mysql_query("INSERT INTO ratings_software (release_date) VALUES('$release_date')")or die("You have an error because:<br />" . mysql_error()); ?>
  15. pocobueno1388
    I tested it, and it worked fine for me 0_o EDIT: Nevermind, I was doing the wrong format >.>
  16. pocobueno1388
    you are passing it a posted date (such as 29 september 2007) when it needs a timestamp instead try $tstamp = strtotime($_POST['release_date']); mysql_query(" INSERT INTO ratings_software (release_date) VALUES('$tstamp)")or die("You have an error because:<br />" . mysql_error()); The date needs to also be converted to the correct format, the code I supplied will do that.
  17. pocobueno1388
    As said above, you should always store date formats in the DB like yyyy-mm-dd. So your code should look like this <?php $release_date=date("Y-m-d", strtotime($_POST['release_date'])); mysql_query(" INSERT INTO ratings_software (release_date) VALUES('$release_date')")or die("You have an error because:<br />" . mysql_error()); ?>
  18. pocobueno1388
    No problem Don't forget to press "Topic Solved".
  19. pocobueno1388
    Yes, that is exactly what it does. You can use the same method for an edit button or whatever else =]
  20. pocobueno1388
    Hmmm...did you try changing what I told you to?
  21. pocobueno1388
    Try <?php $curentPage = basename($_SERVER['SCRIPT_NAME']); if (($currentPage != 'index.php')&&($currentPage != 'checkout.php')) { //do something }else{ //do something else } ?>
  22. pocobueno1388
    Try changing this line $query="INSERT INTO Books (Title,Author,Publisher,ISBN,Year,Price) VALUES ($title,$author,$publisher,$isbn,$year,$price);"; To $query="INSERT INTO Books (Title,Author,Publisher,ISBN,Year,Price) VALUES ('$title','$author','$publisher','$isbn','$year','$price')"; So it's adding numbers to the database instead of what you typed in?
  23. pocobueno1388
    Do this <BODY> <h1>Insert Book into Table</h1> <form name="form1" method="Post" action="AddBook.php"> Title:<INPUT TYPE="text" NAME="title"> Author:<INPUT TYPE="text" NAME="author"> Publisher:<INPUT TYPE="text" NAME="publisher"> ISBN:<INPUT TYPE="text" NAME="isbn"> Year:<INPUT TYPE="text" NAME="year"> Price:<INPUT TYPE="text" NAME="price"> <INPUT TYPE="submit" name="submit" Value="Insert"> <INPUT TYPE="reset"> </form> <?php //Set Variables for the database access: $host="***"; $user="***"; $password="***"; $DBname="***"; $TableName="Books"; $Link = mysql_connect($host,$user,$password); @mysql_select_db($DBname) or die( "Unable to select database"); if (isset($_POST['submit'])){ $query="INSERT INTO Books (Title,Author,Publisher,ISBN,Year,Price) VALUES ($title,$author,$publisher,$isbn,$year,$price);"; if(mysql_db_query($DBname,$query,$Link)){ print("The book was added successfully! \n"); } else{ print("The book was not added! \n"); } print($query); mysql_close($Link); } ?> </BODY>
  24. pocobueno1388
    mysql_db_query() sends the query, so yes...that is enough.
  25. pocobueno1388
    The syntax in the query is still wrong. You have the end quote in the wrong place, and also missing a parenthesis. Try my code and see if it works.
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