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ayok

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Posts posted by ayok

    Edit Image

    in PHP Coding Help

    Posted

    Hi Barand,

     

    No.. with $_GET, the table is updated (except the image -> becomes blank), with $_POST nothing's happened.

    What doesn't work is the image isnot uploaded. And I have "enctype='multipart/form-data'" in the form tag. perhaps I need to change $_file?

     

    Thanks,

    ayok

    Edit Image

    in PHP Coding Help

    Posted

    Hi,

    I have scripts that are used to update datas from database. So it shows the datas on the browser, change, and update it. But I have problem with updating the image.

     

    Here is my update.php:

    <?php
$fupload = $_FILES['fupload']['tmp_name'];
$fupload_name = $_FILES['fupload']['name'];
$category = $_GET['category'];
$title = $_GET['title'];
$descript = $_GET['descript'];
$price = $_GET['price'];
$id = $_GET['id'];
include "../../connection/db.php";

$input=mysql_query("UPDATE products SET title='$title', category='$category', descript='$descript', price='$price', image='$fupload_name' WHERE prod_id='$id'") or die(mysql_error());

$direktori_file = "../../images/products/original/$fupload_name";

if (!move_uploaded_file($fupload, "$direktori_file"))
{
    echo "Upload failed!<br>";
    echo "<a href=add_pic.php>Upload again!</a><br>";
}

elseif ($input)
{
    echo "input data success!<BR>";
    echo "<a href=add_pic.php>Add again</a><br>";
    echo "<a href=../logout.php>Logout</a><BR>";
    echo "<a href=index.php>Cek Products</a><BR>";
}
else
{
    echo "Input process failed!";
}
.........
?>

     

    With this script, I can update the data's, except the image. Is there anyway i can update the image?

     

    Thank you.

    ayok

    [SOLVED] can't make the simplest PHP work!!!

    in PHP Coding Help

    Posted

    i tried the hello world and it displays blank!! it is seriously driving me nuts, no sorts of white text, just plain blank!

     

    First, take something that makes you relax. A cup of tea or a joint. I had a same experince. ;)

     

    Then, you need to know what is required to see your test.php on your browser. You can download WAMP to set up your computer ready for php. I use Apache2Triad. If you work on webserver, see if it's support php. If you really have started 3 days ago, then you need to prepare some basic stuff.

     

    Good luck

     

    ayok

    [SOLVED] Register Global problem (image upload)

    in PHP Coding Help

    Posted

    Hi,

     

    I have a problem working with register global = Off. I used to set it "on" when I worked on my scripts in my local server. However, i heard that it's not recommended. So now I add some $_GET, $_POST, etc. Mostly I can do, but now I have a problem with uploading script. Especially, on admin pages.

     

    I upload the image with a simple script:

    <?php
include "../../connection/db.php";
echo "<FORM enctype=MULTIPART/FORM-DATA METHOD=POST ACTION=input_pic.php>";
echo "Upload picture:<input type=file name=[u]fupload[/u]> ";
echo "<INPUT TYPE=SUBMIT VALUE=add>";
}?>

    With register global = On, I can just write the input_pic.php like this:

    <?php
include "../../connection/db.php";
$input=mysql_query("INSERT INTO gallery(image) VALUES('$fupload_name')") or die(mysql_error());
$direktori_file = "../../gallery/images/original/$fupload_name";
if ($fupload_type != "image/pjpeg" AND 
$fupload_type != "image/jpeg")
{
    echo "Type file <b>$fupload_name</b> is $fupload_type<br>";
    echo "Insert image is failed<br>";
}
elseif (!move_uploaded_file($fupload, "$direktori_file"))
{
    echo "Upload process failed!<br>";
    echo "<a href=add_pic.php>Upload again</a><br>";
}

    The name fupload can be $fupload, $fupload_name, or $fupload_type.

     

    However, with register global = off, the script doesn't work. I've tried to insert 

    $fupload=$_GET[fupload]

    , but it doesn't work either.

     

    Could anybody help me out here?

     

    Thank you,

    ayok

    [SOLVED] Help Photo Gallery

    in PHP Coding Help

    Posted

    Thanks for the reply, guys.

    The script is ok. It works properly. The picture shows up everytime I clicked on one of the thumbnail.

     

    My problem is, everytime I open the gallery, there is no displayed picture (because I haven't click on a thumbnail). The default image is blank. What I want to do is to display the last picture for the default (when I haven't clicked on any thumbnail). I hope it's clear.

     

    Thank you,

    ayok

    [SOLVED] Help Photo Gallery

    in PHP Coding Help

    Posted

    Hi, I need help for my simple photo gallery.

     

    I have 3 php file for my photo gallery. In index.php I use 2 iframes, one for thumbs.php (thumbnails) and one is for displaying the bigger picture (image.php). The picture is displayed when we clicked on one of the thumbnail.

     

    The problem is when I open my photo gallery, the default picture on iframe image (image.php) is blank. This is my image.php:

    <?php
include "../connection/db.php";

$result = mysql_query("SELECT * FROM gallery WHERE pic_id='$id'") or DIE(mysql_error());
echo "<TABLE bgcolor=#EBC0A0 border=0 cellpadding=5 cellspacing=5 align=center>";
while ($data=mysql_fetch_array($result))
{
echo "<TR>";
echo "<td align='right'>$data[descript]</td></tr>";
echo "<tr><TD><img src='images/$data[image]'></a></TD></tr>";
}
echo "</table>";
?>

    I know that I need to make an if statement, but after several tries, I gave up. Could someone help me out here? Any help will be appriciated. ;)

     

    Thank you,

    ayok

    Help Admin Login

    in PHP Coding Help

    Posted

    Thank you for the reply, guys.

    I've tried to put those POST codes, but I got the same result which go back to the login page.

     

    I've tried to add this:

    <?php
session_start();
$namauser = $_GET['nameuser'];<--
$passuser = $_GET['passuser'];<--
if(!empty($nameuser) AND !empty ($passuser))
{ do things }else{
echo "You have to login before adding new items<BR>";
echo "<a href=form_login.php>Login</a>";
}

    on index.php.

    But still.. doesn't work.

    Help Admin Login

    in PHP Coding Help

    Posted

    Hi, got another problem  ;D

     

    I've created simple login scripts for my webpage, but I cannot use it on my webserver.

    Here is the codes for check_login.php:

    <?php
include "connect_db.php";
$login=mysql_query("SELECT * FROM users WHERE username= '$username' AND password='$password'") or die (mysql_error());
$data=mysql_fetch_array($login);

if($data[username]==$username AND $data[password]==$password)
{
session_start();
session_register("nameuser");
session_register("passuser");
$nameuser=$data[username];
$passuser=$data[password];
header("location:index.php");
}
else
{
echo "Failed! you give wrong username and password<BR>";
echo "<a href=form_login.php>try again</a>";
}

?>

     

    And ini every page, there are codes:

    <?php
session_start();
if(!empty($nameuser) AND !empty ($passuser))
{ do things }else{
echo "You have to login before adding new items<BR>";
echo "<a href=form_login.php>Login</a>";
}

    The scripts worked on my local server but not on web server. From the information I've got, it doesn't work because use the register_globals.

     

    Would anybody help me how I solve this?

     

    Thank you,

    ayok

    [SOLVED] Cannot Select Table

    in PHP Coding Help

    Posted

    Hi,

    I've got a different result on my local server and web server.???

     

    I created this page. On this page, you can find some company projects which are taken from mysql database. But I cannot get the data when I clicked on one of the project. No data is selected in the next page. However, the script is working properly if I tested it on my localhost.

     

    Here is the php script on index.php

    <?php
include "../../dbconnect/koneksi_db.php";
$result=mysql_query("SELECT * FROM project");
while ($data=mysql_fetch_array($result))
{
echo "<a href=detail.php?id=$data[proj_no]>$data[title] - $data[company]</A><BR>";
}

     

    From this index page, we can click on one of the links to the project detail which goes to detail.php.

     

    <?php

include "../../dbconnect/koneksi_db.php";
$result = mysql_query("SELECT * FROM project WHERE proj_no='$id'") or DIE(mysql_error());
$data = mysql_fetch_array($result);
$body_project = nl2br($data[body]);

echo "<h1 align='center'>$data[title]</h1>";
echo "Begin: $data[year]<br>Status: $data[status]<br>Bedrijf: $data[company]<br>";
echo "<p>$body_project</p>";
echo "<a href='file/$data[file]'>dossier downloaden<br>";
echo "<a href='index.php'>terug naar projecten</a>";
?>

    In this page, the information cannot be shown in the browser.

     

    Could anybody help me to find out what's wrong?

     

    Thanks,

    ayok

    [SOLVED] If empty? (code help)

    in PHP Coding Help

    Posted

    Hi, I have a question with php script for "if" statement.

     

    I have this php code for a news with image in it:

    <?php
echo "$data[day_news], $data[date_news], $data[time_news]<br><b>$data[by]</font></b><br><br>";
echo "<h1>$data[title]</h1>";
echo "<a href=detail_news.php?id=$data[news_id]><img align='left' src='images/$data[image]'></a>";
echo "$data[body]";

     

    But if there is no image uploaded, it has a cross box where the image should be there.

    What should I write if I don't want any image if I didn't upload the image?

     

    Thank you,

     

    ayok

    Delete Image from Folder

    in PHP Coding Help

    Posted

    But it's kind of weird, because i made an upload script where I can put an original image, then create two smaller images in different folders, and then in the same script, I am able to unlink the original image from the folder. So how come I couldn't unlink those two smaller images?

     

    thanks,

    ayok

    Delete Image from Folder

    in PHP Coding Help

    Posted

    All right,

    I can now unlink the image files from the image folder in localhost. But when I test it on web server, i keep getting this error:

    Warning: unlink() [function.unlink]: http does not allow unlinking in /home/mywebcom/HTML/products/admin/delete.php on line 8

    I even set the permission to 777, but i still get this error. How can I solve this?

     

    Thank you,

    ayok

    Delete Image from Folder

    in PHP Coding Help

    Posted

    Hi,

    I have difficulty to set up the code.

    What I try to do is to unlink 2 images (same name) in different folder.

    This is my delete.php

    <?php

include "../dbconnect.php";
$delete="DELETE from product WHERE id='$id'";
$result=mysql_query($delete);

if($result)
{
header("location:index.php");
}
else
{
echo "Delete process failed";
    echo "<a href=index.php>Try again</a><br>";
    echo "<a href=logout.php>Logout</a><BR>";
}

?>

     

    I've tried to add this code:

    $image = "SELECT image FROM products WHERE id = '$id'";
unlink('images/$image);
unlink('images/thumbnail/$image);

     

    But it doesn't work.

     

    Could anybody help me?

     

    Thanks,

    ayok

    But

    Delete Image from Folder

    in PHP Coding Help

    Posted

    Hi,

    I have a question. I have some php scripts to upload images and delete it. But if I delete the image I only delete the image's data in the database, and the image still remains in the folder.

     

    My question is, how can I remove the image from the image folder?

     

    Thank you,

    ayok

    [SOLVED] Confirm Box?

    in Javascript Help

    Posted

    In the interest of getting this solved:

     

    <?php
$show = mysql_query("SELECT service.*,category.name FROM service LEFT JOIN category on service.category=category.id_cat WHERE category='$id'") or die(mysql_error());
echo "<table border=0><tr bgcolor='#D0DCE0'><th>Service</th><th>Description</th><th>Duration (minutes)</th><th>Prices</th></tr>";


    while (($data = mysql_fetch_array($tampil)) && (mysql_num_rows($tampil) > 0))
    {
        echo "<tr>";
        echo "<td bgcolor='#D47FFF'>$data[name_serv]</td>";
        echo "<td bgcolor='#FF55FF'>$data[desc_serv]</td>";
        echo "<td bgcolor='#D47FFF'>$data[minutes]</td>";
        echo "<td bgcolor='#FF55FF'>$data[price]</td>";
        echo "<td><a href='' onclick='return disp_confirm()'>delete</a><br><a href=edit_service.php?id=$data[id_serv]>edit</a></td></tr>";
    }
    echo "</table>";
}?>

<script type="text/javascript">
function disp_confirm(){
    var msg = "Do you really want to delete this?";
    if (confirm(msg)){
        window.location.href = "delete.php?id=<?php echo $datakategori['id_cat']; ?>";
    }
    return false;
}
</script>

     

    Hi roopurt,

     

    Thank you for being so patient to help me to solve my problem ;). This is what I found.

    the links should be "delete.php?id=<?php echo $data['id_serv']; ?>"; I want to delete the service item, not the category. I don't know why I used that $datakategori variable. Anyway, I've changed the links to "$data['id_serve]".

     

    However, it keeps getting the links of $datakategori variable. Its probably getting confused because the link is outside the php code. So, nogray is right. Thanks for your code. It's working now.

     

    Thank you,

    ayok

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