phpretard

Believe me I know about the headers. I think I'll just try to deal with the permissions issue and upload it to a folder. Thanks

I can't modify the headers without error...

I can't really modify the headers... I would like to display it as an <img src="DBInfo"> tag instead. Is this even possible? The code below displays it fine but I am trying to display it as the website header and it give header errors <? ...connect header("Content-length: $size"); header("Content-type: $type"); header("Content-Disposition: attachment; filename=$name"); echo $content; ?> I would upload it straight to a file but... I have permission to Temp folder problems

Thank the human works great! Although I am actually from Gallgamar.

If there are no errors on the form submitted I get PHP errors. How can I change this to first check if the array is set before running this code? foreach ($errormessage as $error){ echo $error; } Thanks!

Thank you for your help!

look at that link anyways for some ideas How I assign "False" to a cookie named "pi"?

I set this cookie and need to later destoy it. <? I SET IT WITH THIS... $expire=time()+60*60*24*30; setcookie("pi", "PI-1234456832", "$expire"); // Works great I AM TRYING TO KILL IT WITH THIS... setcookie("pi", "", time()-3600); // Doesn't work ?> Please help me cookie monster!

Thank you!

I have a text field that is allowed numbers and text but it should contain at least 7 numbers. This is how I would validate for 7 number only but I need at least 7 numbers and text optional. <? if (($var=='')||(strlen($var) < 7)||(!is_numeric($var))){ $message="Missing Numbers"; } ?> Thank you!

<?php $con = mysql_connect("localhost","root","b123dw9WHT3"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("company", $con); $result = mysql_query("SELECT coName FROM contact WHERE coID='1' "); while($row = mysql_fetch_array($result)) { $info=$row['coName']; echo "<input tpe="text" value="$info" /> } mysql_close($con); ?>

how can turn this into dynamic code without typing all the options? I would like: $start_year = date('Y'); $end_year = $start_year -80 years <select name="DateOfBirth_Year"> <option> - Year - </option> <option value="2004">2004</option> <option value="2003">2003</option> <option value="2002">2002</option> <option value="2001">2001</option> <option value="2000">2000</option> <option value="1999">1999</option> <option value="1998">1998</option> <option value="1997">1997</option> <option value="1996">1996</option> <option value="1995">1995</option> <option value="1994">1994</option> <option value="1993">1993</option> <option value="1992">1992</option> <option value="1991">1991</option> <option value="1990">1990</option> <option value="1989">1989</option> <option value="1988">1988</option> <option value="1987">1987</option> <option value="1986">1986</option> </select>

I am trying to display links on a page read from my DB. I would like them to display: CAT 1 Link 1 Link 2 Link 3 etc... CAT 2 Link 1 Link 2 Link 3 etc... I know the code below is silly but it's to illustrate my needs. The DB rows are setup as is in the code...the echo is silly <? $result_links = mysql_query("SELECT * FROM links ORDER by cat"); while($row = mysql_fetch_array($result_links)) { $id=$row['id']; $cat=$row['cat']; $url=$row['url']; $display=$row['display']; echo"<h4>Category 1</h4>"; echo"all the links assc. with category 1"; echo"<h4>Category 2</h4>"; echo"all the links assc. with category 2"; echo"<h4>Category 3</h4>"; echo"all the links assc. with category 3"; echo"<h4>Category 4</h4>"; echo"all the links assc. with category 4"; } ?> Thanks PHP FREAKS!

$find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); $find = explode(" ", $find); //Now we search for our search term, in the field the user specified foreach ($find as $term){ $data = mysql_query("SELECT * FROM cases WHERE (casetype LIKE '%$term%') OR (caseinfo LIKE '%$term%') "); } $matchescount=mysql_num_rows($data); $find = implode(" ", $find);

I have put this question on 3 forums with no answer. Is the question confusing or the code?

SCENARIO 1: "I need to Find Two words" IS IN THE DB TABLES --|casetype|-- AND --|caseinfo|--. If I search for "Find" result returned If I search for "Two" result returned Problem: If I search for "Find Two" no result. SCENARIO 2: "I need to Find" IS IN THE DB TABLE --|casetype|-- "Two words" IS IN THE DB TABLE --|caseinfo|-- If I search for "Find" result returned If I search for "Two" result returned Problem: If I search for "Find Two" no result.

I have a site search but for somes reason it is limited to a one word search. Search1: If I search for "Find" or "Two" it works great. Search2: If I were to search for "Find Two" It returns nothing yet I know both are in the DB (based on Search1). $find="ONEWORD" //the search return results $find="TWO WORDS" //the search return nothing and I know the info is there. $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); $data = mysql_query("SELECT * FROM cases WHERE (casetype LIKE '%$find%') OR (caseinfo LIKE '%$find%') "); while($result = mysql_fetch_array($data)) { $id=$result['id']; echo "<h1>".$result['casetype']."</h1>"; echo "<hr />"; $caseinfo=$result['caseinfo']; $caseinfofull=$result['caseinfo']; echo "$caseinfofull"; echo $shortdesc = substr_replace($caseinfo, '', 400, -1) . "..."; echo "<br>"; }

help?

help?

Basically the same as my first question but I noticed if I search with more than one word it returns nothing. $find="ONE"; // WORKS GREAT $find="TWO WORDS"; // NO RESULTS ... I KNOW THERE IN THE DB THOUGH $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); $data = mysql_query("SELECT * FROM cases WHERE (casetype LIKE '%$find%') OR (caseinfo LIKE '%$find%') "); while($result = mysql_fetch_array($data)) { echo "<h1>".$result['casetype']."</h1>"; echo "<hr />"; $caseinfo=$result['caseinfo']; $caseinfofull=$result['caseinfo']; echo $caseinfofull; echo $shortdesc = substr_replace($caseinfo, '', 400, -1) . "; echo "<br>"; echo "<br>"; }

Bouya!

This only displays one result and I can't figure out why... There are 2 fields in the DB I am trying to search through and look for the keyword typed in the search field: FIELD 1:casetype VARCHAR FIELD 2:caseinfo TEXT I can get it search and display all when search one field at a time but it only dispalys one result if I try to search both fields. $find=$_POST['find']; $data = mysql_query("SELECT * FROM cases WHERE (casetype or caseinfo LIKE'%$find%') "); while($result = mysql_fetch_array($data)) { $id=$result['id']; echo "<h1>".$result['casetype']."</h1>"; echo "<hr />"; $caseinfo=$result['caseinfo']; $caseinfofull=$result['caseinfo']; echo"<div id='$id' style='display:none'>$caseinfofull [<a href='javascript:void(0)' onclick=\"Hide('$id'), Show('partial$id')\">close</a>]</div>"; echo "<div id='partial$id' style='display:block'>".$shortdesc = substr_replace($caseinfo, '', 400, -1) . "... <a href='javascript:void(0)' onclick=\"Show('$id'), Hide('partial$id')\">read more</a></div>"; echo "<br>"; echo "<br>"; }

Thank you...!

Thank you for the response. I understand wht you did there. what I need is the results of what you did to go through the databse and send an email for each query match. while($row = mysql_fetch_array($result)) { $email=$row['email']; $billto=$row['bill_to']; $phone=$row['phone']; echo "$email<br />"; echo "$billto<br />"; echo "$phone<br />"; echo "<hr />"; } foreach (($email $billto $phone) as $mailto){ email script } } Am I making any sense?

Each row in my DB contains -- email | phone | bill_to --- I would like to send an email to each person with the information specific to them. The code below does display the information but I don't believe it associates them. So each email would read: ------------------------------------------- Dear Person I am emailing, Here is the information we have on file: Email Address: email[at]email.com Bill-To Number: 123456 Phone Number: 123-456-7890 I hope you got this, Anthony ps. if you did get this thank you phpfreaks. ------------------------------------------- while($row = mysql_fetch_array($result)) { $email[]=$row['email']; $billto[]=$row['bill_to']; $phone[]=$row['phone']; } foreach($email as $mailto){ echo "$mailto<br />"; } foreach($billto as $billnumber){ echo "$billnumber<br />"; } foreach($phone as $telephone){ echo "$telephone<br />"; }