RussellReal

uhm.. go to the top, pick 'insert' then where it says 'word' insert the new bad word... then where it says replacement.. doesn't matter what you put, you don't use that field, hit save, and you're done, BINGO new word added..

link to the page that currently works please.. Aswell as a better description of what it is you want top to bottom, single collumn, multiple collumns? you needa be more specific.

basically all I did was I took YOUR code, threw a loop around it, and presto

foreach ($prices as $k => $v) { if (preg_match(yada,$v)) continue; $errors[] = 'price is invalid!'; break; }

just add a new word to the table

Yeah, MrAdam is right, I mean people here help out, but we don't code things for people

I don't believe this is an easy fix, its more or less, a photo with where the floor would be, its transparent, they edit in the shadows etc from the furniture, and then a php script mixes the background image (the floor) AND the chairs and stuff ontop.. its done in layers.. I could probably do this if you're looking to hire somebody, but its not a quick thing to do

you don't need javascript for drop down menus, there are a bunch that are purely css, if you don't understand javascript that well, you may just look into a css solution.

you don't need regex try this.. function cookies() { var x = document.cookie.split(';'), ret = new Object(); for (i in x) { ret[x[i].split('=')[0]] x[i].split('=')[1]; } return ret; } // untested now you can use that like this: cookies().NEW_LIST;

don't understand what you want then

the MySQL Query I have given you.. there are 3 parts to it.. table a: your Cars table.. table b: your Colors table.. table c: your MFG table.. yes it will still pull a.color (cars.color) which will be an integer, but b.shade should be the name of that color? if in the database that isn't how this will work, than you need to change the field names, to reflect what you want to happen...

you could probably try a pattern like this:) /^(:.*?\n){numOfLinesToSkip}(?.*)\n)+/

Glad to have helped

$mfg = mysql_query("SELECT a.*, b.shade, c.make FROM cars a JOIN color b ON (b.id = a.color) JOIN mfg c ON c.id = a.make WHERE a.make = '1'") or die(mysql_error()); try this, and if I misnamed a field please try to correct it, but this should tell you where the problem is should you encounter one

you aren't changing the query I've given you much... mysql_query("SELECT id, shade As (SELECT shade FROM color WHERE color.id = cars.color), carMake As (SELECT make FROM mfg WHERE make.id = cars.make) FROM cars WHERE make = '1'");

see my reply

onload you should read the hash and handle it the same way you would handle it when sum1 clicks that link document.onload = function() { var option = location.hash.replace('#',''); ajaxObject.loadPage(option); }

You could pull it off like this.. SELECT id, color As (SELECT colorName FROM colors WHERE colors.id = colorId), manufacturer As (SELECT manuName FROM mfg WHERE mfg.id = manufacturerId) FROM cars WHERE id = '1'

try making the class="various1" and then using the jQuery selector to catch all elements with the className = 'various1' You cannot have more than 1 element with the same id

use simple_xml it makes it super easy..

does the folder /imgs/ exist?

anytime bro, please click "Mark as Solved"

this is most definitely not a PHP problem, its an HTML problem.. That and possibly a JavaScript problem aswell, considering in IE there are two errors that occur syntax errors. My guess would be that you did not properly close an <a> tag somewhere.. For the most part modern browsers sometimes fix simple errors, where as IE doesn't try, it just makes the page however you tell it to be made also note: IE doesn't support CSS properties like min-height max-height, and all of the CSS3 properties.

echo "<a href='". $row['img_path']."'><img border=0 src='". $row['thumb_bw_path']."' onmouseover='this.src=\"". $row['thumb_path']."\"' onmouseout='this.src=\"". $row['thumb_bw_path']."\"' />". "</a></td> \n"; you can escape quotes to mean literal quotes instead of a string terminator.. using \

I'm sorry, I don't understand what you mean at all.. could you maybe try and explain expected output, as your explanation doesn't make any sense, sorry.