Bman900

Which is a better language? I just got a book on Java and it seems cool but then I discovered that there was JavaScript. I work with PHP a lot and want to embed some java (as I thought of course) but realized I might need javascript instead. Is it worth learning java or should I just go to javascript?

Am no exper here but this might be wrong: ('$_POST[comment]','$username',')"); Shouldn't there be another value there as ur inserting into 3 collumns.

Once I did that I got this : http://shadowsofalcatraz.com/pandora/admin/image/default.jpeg as the image, the url itself. instead of the image.

here is my code: <?php $target_path = "videos/"; $imgtarget_path = "image/"; /* Add the original filename to our target path. Result is "uploads/filename.extension" */ $movielink = basename( $_FILES['uploadedfile']['name']); $imagelink = basename( $_FILES['imagefile']['name']); $target_path = $target_path . basename( $_FILES['uploadedfile']['name']); $imgtarget_path = $imgtarget_path . basename( $_FILES['imagefile']['name']); if((move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)) || (move_uploaded_file($_FILES['imagefile']['tmp_name'], $imgtarget_path))) { echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded"; echo "The file ". basename( $_FILES['imagefile']['name']). " has been uploaded"; mysql_query("INSERT INTO video (title, descript, link, image) VALUES('$formtitle', '$descrip', '$movielink', '$imagelink') ") or die(mysql_error()); } else{ echo "There was an error uploading the file, please try again!"; } ?> The video file gets uploaded correctly but the image file doesn't go any where. It gives me the messages that they both have been uploaded fine which obviously is wrong. Any help is appreciated.

Ye that is exactly what I was going to do. And I was going to get more specific with that query where it checks for one user like u just said above.

Correct me if am wrong. I will put that in an query and run it. Then it should return a value if there is something in there. If not that obviously they don't have a subscription or it was expired. So after the query I can run an if (something got returend) { do thid} else { you don't have a subscription}

Alright, so I store the date till they paid for in a column but how would I do a check if they still have access to their subscription and than drop the value after the time is up so they can order again?

So lets say I want to make a site where people can buy memberships for 30 days or for a whole year. I have a user system but I have no clue on how to do this. I was thinking after the payment is made I can enter a code in the database that get checked when the user is logged in. The problem that I am running into is how to I change that code in the database after 30 days or 12 months after they signed up so they wont have a subscription any more?

Alright I fixed most of my code but I am running into one hell of a mountain. Something get royaly messed up as soon as I enter into a folder that links back to my include file like. (../include.php) Am thinking it is a connection issue because my code and database is fine in the include file. I do connect to a databse in the include file by getting variables out of config.php in my include.php file. Should I be making a connection before I include a file from outside of a folder. The weird thing is that it works perfectly in my root directory. Anything will help me. Alright I found out that if I make the connection inside my include file and not use variables stored in config.php it works but that still doesn't make sense. include.php include config.php from the same directory. Than admin.php includes include.php from ../ WHat am I missing?

Alright, but i still need to fix me code. So am going to do a check to make sure there are 20 rows than dumb everything into an array and use that to put information into variables for me to use. Does that sound like a good plan?

can I jusr create a function to check my query?

So would this work? <? if($content20Res) { $content20 = mysql_result($content1Res, 19, 0) } ?>

But there are. Thats what I don't understand. As soon as I switch back to PHP 4.4 it works just like a designed it but as soon as I do PHP5 errors come up all over the place.

Ok here is the error I get: Warning: mysql_result() [function.mysql-result]: Unable to jump to row 19 on MySQL result index 62 in /homepages/44/d272374679/htdocs/draft/includepages.php on line 80 This doesn't make sense since it worked with Php 4.4 Here is the exact code I have on that line: <?php $content20 = mysql_result($content1Res, 19, 0) or die (mysql_error()); ?>

ye it sucks that am on shared hosting, there are not alternatives?

I want to make a script that allows a user to upload a video (know this part) but then covert it to flash and put it in a flash player to display. I have no clue where to start this process. What is a good way of going about this?

Here is part of my code. <?php include("config.php"); mysql_connect("$dbhost", "$dbusername", "$dbpassword") or die(mysql_error()); mysql_select_db("$databasename") or die(mysql_error()); $surveyRes = mysql_query("SELECT surveyinput FROM surveylink"); $surveylink = mysql_result($surveyRes, 0, 0); $emailRes = mysql_query("SELECT emailinput FROM email"); $email = mysql_result($emailRes, 0, 0); $descRes = mysql_query("SELECT mdescription FROM meta_desc"); $description = mysql_result($descRes, 0, 0); $mkeyRes = mysql_query("SELECT mkeywords FROM meta_keys"); $metakeywords = mysql_result($mkeyRes, 0, 0); $acheckRes = mysql_query("SELECT acheck FROM awebercheck"); $webcheck = mysql_result($acheckRes, 0, 0); ?>

I was working on a script that need PHP 5 so I did the upgrade but a major script I was working on before displays more errors than there are codes of lines! Here is a little taste: Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /homepages/44/d272374679/htdocs/demo/include.php on line 8 Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /homepages/44/d272374679/htdocs/demo/include.php on line 11 Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /homepages/44/d272374679/htdocs/demo/include.php on line 14 Warning: mysql_result(): supplied argument is not a valid MySQL result resource in /homepages/44/d272374679/htdocs/demo/include.php on line 17 I noticed if I use msqli it works to a point but it doesn't pick up mysqli_result plus I don't want mysqli. Any one?

Ok, so I followed a tutorial on creating a subscribe list without using a databse. I got everything to work but I can not send out HTML correctly. Here is the code: <? error_reporting(0); //############################################################# //################# CONFIGURATION ########################## // choose a password $my_password="testing"; // the email from which emails are send // mydomain.com must be your real domain, otherways, // the server will not send any emails $from_email="Balint <[email protected]>"; // Your replay to email (whatever you want). $replayto="[email protected]"; // A message to be attached to the bottom of the message // We recommend to add a link to subscription page $message_at_bottom=" ------------------------------------------------------------ P.D.: To remove from this list go to... http://www.mydomain.com/emaillist/ "; // The file where emails are stored $emails_file="emaillist-9A67o95B1O.txt"; //############### END CONFIGURATION ######################## //############################################################# // IF INFO IS NOT POSTED, PRINT THE FORM AND DIE if (!$_POST["mensaje"]){ print_form(); die(); } // IF INFO IS POSTED YOU WILL BE HERE // Check whether the password is correct // (only webmaster is supposed to know the password, which has been specified above) if ($_POST["p"]!=$my_password){die("Incorrect password");} // Get the subject of message $subject =$_POST["subject"]; // Get the body of message $message=$_POST["mensaje"]; // Add to body of message the bottom $message.=$message_at_bottom; // Read the file with emails to variable $emails_file $emails_file=file_get_contents($emails_file); // Extract list of emails to array $emails_array preg_match_all("/<.{0,100}?>/",$emails_file,$emails_array); // Start output print "<b>Sending messages...</b>"; // Send email to each email foreach ($emails_array[0] as $email){ // remove "<" and ">" from each email $email=substr($email,1,strlen($email)-2); // Next line is the one sending the email: the key command of this script mail($email, $subject, $message,"From: $from_email\n" . "MIME-Version: 1.0\n" . "Content-type: text/html; charset=iso-8859-1"); // Each time an email is send, output it print "<br>$email\n"; // After sending each email, send previous line (the email) to the browser flush(); } ?> <?php // THIS FUNCTION WILL SHOW THE FORM // MODIFY IT AS REQUIRED function print_form(){ ?> <center> <h2>Form to send email to the mailing list</h2> <table> <tr><td> <form method=POST action="<? $PHP_SELF; ?>".php> Subject <br><input type=text name=subject size=40> <br>Message <br><textarea name=mensaje cols=50 rows=8></textarea> <br>Password <input type=password name=p size=10> <br><input type=submit value=Send> </form> </td> </tr> </table> </center> <? } ?> As you can see I have the correct protocols for HTML but it is still not working. I have done this in a different script before so I know it is not my email provider. Can any one spot anything that would cause HTML not to send properly?

Is there a way to basically get the location of a file minus the file name? Basically I want a code that will spit back the root of my files. For example if my files would be in root the code above: $_SERVER['SERVER_NAME']; would work just fine for a link, but what if some one puts those files in a folder like root>backup the link would not work.

Is there a function that gets the root domain of a website? And then store it in variable?

THANK YOU! I don't know what I was thinking but my table was wrong.

You mean like this: <?php $ipchecker = $_SERVER['REMOTE_ADDR']; $ipsql = mysql_query("select iptable from ipcheck where iptable = '$ipchecker'"); $row_number = mysql_num_rows($ipsql); if ($row_number > 0) { ?> <form id="form1" method="post" action="redirect.php"> <textarea name="question" cols="52" rows="8"></textarea><br /> <input name="firstname" type="text" /><br /> <input name="email" type="text" /><br /> <input name="submit" type="submit" /> </form> <?php } else { ?> <script type="text/javascript" src="http://forms.aweber.com/form/40/1675361340.js"></script> <?php } ?> That doesn't work either...

Would this be correct? <?php $ipchecker = $_SERVER['REMOTE_ADDR']; mysql_query("select iptable from ipcheck where iptable = '$ipchecker'"); if (mysql_num_rows > 0) { ?> <form id="form1" method="post" action="redirect.php"> <textarea name="question" cols="52" rows="8"></textarea><br /> <input name="firstname" type="text" /><br /> <input name="email" type="text" /><br /> <input name="submit" type="submit" /> </form> <?php } else { ?> <script type="text/javascript" src="http://forms.aweber.com/form/40/1675361340.js"></script> <?php } ?> I added my IP manualy to test it out and it goes to the else statement no matter what.

I want implement something where the persons IP is looked up in my database and if it is found display something and if it isn't display another thing. The only trouble I have is how would I check for the IP in my table (checkip)?