eugene2009
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Everything posted by eugene2009
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thank you so much.. and another question.. say the previous page "customer_list.php" lists all the names of the customers. when you click on one of the names it will take them to customer_records.php well how exactly can I link all the names with the proper id's ? thank you for the help
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Hey so if i have a table with all the rows numbered with a customerid. Say I wanted to fetch each row on a seperate page with a get method. how will I be able to do that? for instance i have rows with customer information. how will I be able to display them on seperate pages. ?customerid=343 and from there it will show all that customers information in a table. Im not sure how to explain this. Please help.
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So i got this part figured out.. CREATE TABLE category( category_id INT AUTO_INCREMENT PRIMARY KEY, name VARCHAR(20) NOT NULL, parent INT DEFAULT NULL); INSERT INTO category VALUES(1,'ELECTRONICS',NULL),(2,'TELEVISIONS',1),(3,'TUBE',2), (4,'LCD',2),(5,'PLASMA',2),(6,'PORTABLE ELECTRONICS',1), (7,'MP3 PLAYERS',6),(8,'FLASH',7), (9,'CD PLAYERS',6),(10,'2 WAY RADIOS',6); SELECT * FROM category ORDER BY category_id; My question is now.. how do I generate html pages where PAGE 1 (ELECTRONICS) Televisions Portable Electronics PAGE 2 (DEPENDING ON PAGE 1 SELECTION) .. Lists here all the childs of electronics.. PAGE 3 ..Lists the subcategory of previous page. Does anyone know what im talking about? PLEASE HELP
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So i got this part figured out.. CREATE TABLE category( category_id INT AUTO_INCREMENT PRIMARY KEY, name VARCHAR(20) NOT NULL, parent INT DEFAULT NULL); INSERT INTO category VALUES(1,'ELECTRONICS',NULL),(2,'TELEVISIONS',1),(3,'TUBE',2), (4,'LCD',2),(5,'PLASMA',2),(6,'PORTABLE ELECTRONICS',1), (7,'MP3 PLAYERS',6),(8,'FLASH',7), (9,'CD PLAYERS',6),(10,'2 WAY RADIOS',6); SELECT * FROM category ORDER BY category_id; My question is now.. how do I generate html pages where PAGE 1 (ELECTRONICS) Televisions Portable Electronics PAGE 2 (DEPENDING ON PAGE 1 SELECTION) .. Lists here all the childs of electronics.. PAGE 3 ..Lists the subcategory of previous page. Does anyone know what im talking about?
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Your getting this out of your mysql database right?
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Hey. I'm kind of new to this so I need help on making his the easiest way possible.any help would be appreciated. I'm creating a site for car parts. Let's have 3 examples.. Chevrolet Toyota Volkswagen I want viewers to be able to select on them and be Ripken to a page where they select the model.. From there they can select why kind of part they want. So the question is,how do I create the database and tables and also how do I have the HTML form fetch the correct informaion and create automatic HTML pages. Because what if I add a part for a Saturn ion headlight? Is it possible to have it all updated at once? Please help.
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Somebody please helppp
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I foung this tutorial online. I installed it. Everything works except when I try to create a new account it says "Registration Failed! Try again". Even tho it says that, i can still see the new account in the database. Here is the link to the tutorial: http://www.ineedtutorials.com/code/php/complete-advanced-login-member-system-php-tutorial May somebody PLEASE help me? Thank you.
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Yesss
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May I see an example of your code?
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doesnt work.. im pretty sure there needs to be somthing in this line: mysql_select_db (test, blog); thanks in advance
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sorrryy exclude the font formatting.. mysql_select_db (test, blog); $result = mysql_query("SHOW TABLES"); echo '<ul>'; while($row = mysql_fetch_array($result)) { echo '<li>' . $row[0] . '</li>'; } echo '</ul>';
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is it possible to show tables from 2 databases in one list.. how would i make this work???? mysql_select_db ([color=red][b]test, blog[/b][/color]); $result = mysql_query("SHOW TABLES"); echo '<ul>'; while($row = mysql_fetch_array($result)) { echo '<li>' . $row[0] . '</li>'; } echo '</ul>';
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THANK YOU!!!
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yea i know that.. im just wondering if thats possible..
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Hey, is it possible to list all the table names in a database on an html page? For example: Database Name: Cars Table Names: -BMW -Mercedes -Volkswagen -Ford -Volvo How do I have it generate that list automatically if I add new tables later on?
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Hey, is it possible to list all the table names in a database on an html page? For example: Database Name: Cars Table Names: -BMW -Mercedes -Volkswagen -Ford -Volvo How do I have it generate that list automatically if I add new tables later on?
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is this what your talking about? ? <input type=text name="NAME_OF_INPUT" readonly="readonly" value="PUT_TEXT_HERE"> REPLACE "NAME_OF_INPUT" and "PUT_TEXT_HERE" with whatever values you want.
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monkeybidz, thanks alot!!! even tho it didnt work i forgot the WHERE tutorialid='3' statement.. thats the only thing i needed to add to my original code. THANKKKS!
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heres the problem.. i have a table named "comments" and in this code i am fetching inputs "tutorialid" and "name" what i want to fetch is a certain id from the "tutorialid" how will i go about doing this.. heres part of the code. $sql = "SELECT tutorialid, name FROM comments LIMIT $offset, $rowsperpage"; $result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR); while ($list = mysql_fetch_assoc($result)) { echo $list['tutorialid'] . " : " . $list['name'] . "<br />"; } for instance.. i want all the rows with the tutorial id "3" can somebody please help? thanks in advance
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im sorry, but im a little new to mysql may you please give me an example?
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What is the easiest way to make the results display 10 per page? May anybody please help? Here is the code: $commentquery = mysql_query("SELECT * FROM comments WHERE tutorialid='$tutid' ORDER BY date DESC") or die(mysql_error()); $commentNum = mysql_num_rows($commentquery); echo "<table width=\"540\" border=\"1\" align=\"center\" cellpadding=\"0\" cellspacing=\"0\" bordercolor=\"#25b7c1\"bordercolor=\"#25bc1\"><tr><td><div id=\"currentcomments\" class=\"submitcomment\"><br><h2 class=\"formtitle\">Current Comments</center></h2>\n"; echo "<p align=\"left\"><B><u>" . $commentNum . "</u></b> comments so far (<a href=\"#post\">post your own</a>)</p>"; while($commentrow = mysql_fetch_row($commentquery)){ $commentbb = BBCode($commentrow[4]); $commentDate = formatDate($commentrow[6]); echo "<div class=\"commentbody\" id=\"$commentrow[0]\">\n <p class=\"postedby\" align=\"left\">Posted by <B><u>"; if($commentrow[3]){ echo "<a href=\"$commentrow[3]\">$commentrow[2]</a> "; } else { echo "$commentrow[2] "; } echo "</b></u>on $commentDate </p>\n <p align=\"left\">$commentbb</p>\n \n</div>"; } echo "</div></td></tr></table>"; } function submitComments($tutid2,$tuturl){
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i dont need it for just any user.. what I need this for my website.. when I create a new page, i want to place it into a category.. my categories are in different tables... there for i can select an existing table(category) or create a new category if i need it.. is there something simpler I can do? Im just not sure because im new to mysql. thanks
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Heres the tag.. <object width="550" height="400"> <param name="movie" value="somefilename.swf"> <embed src="somefilename.swf" width="550" height="400"> </embed> </object>
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It still says... You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '".$tablename."( id INT NOT NULL AUTO_INCREMENT, PRIMARY KEY(id) please help