Spring

THESE ARE BEING LOADED GOD DAMMIT $autoload['libraries'] = array('database', 'image_lib'); I seriously can't do this without loading the database directly! I get: Call to a member function get() on a non-object WHEN I DONT LOAD THE DB DIRECTLY class Port_model extends CI_Controller { function __construct() { parent::__construct(); } function getData() { $query = $this->db->get('port'); if ($query->num_rows() > 0) { //Lets get our data from announcements and pass it to an array foreach ($query->result() as $row) { $data[] = $row; } } return $data; } } and i think its the damn .htaccess!!! ALSO, I CANT LOAD THE IMAGE LIB LIBRARY WITHOUT GETTING A SIMILAR FUCKING PROBLEM. IS THIS THANKS TO .HTACESS!? <IfModule mod_rewrite.c> RewriteEngine On RewriteBase /ci/ #Removes access to the system folder by users. #Additionally this will allow you to create a System.php controller, #previously this would not have been possible. #'system' can be replaced if you have renamed your system folder. RewriteCond %{REQUEST_URI} ^system.* RewriteRule ^(.*)$ /ci/index.php?/$1 [L] #When your application folder isn't in the system folder #This snippet prevents user access to the application folder #Submitted by: Fabdrol #Rename 'application' to your applications folder name. RewriteCond %{REQUEST_URI} ^application.* RewriteRule ^(.*)$ /ci/index.php?/$1 [L] #Checks to see if the user is attempting to access a valid file, #such as an image or css document, if this isn't true it sends the #request to index.php RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ /ci/index.php?/$1 [L] </IfModule> <IfModule !mod_rewrite.c> # If we don't have mod_rewrite installed, all 404's # can be sent to index.php, and everything works as normal. # Submitted by: ElliotHaughin ErrorDocument 404 /index.php </IfModule>

<?php $db = new Database(); $q = "SELECT post_id, post_title, post_subtitle, post_body, DATE_FORMAT(post_created, '%M %D %Y') AS created_on, post_ext_link FROM blog ORDER BY post_id DESC LIMIT 3"; $r = $db->query($q); if (mysqli_num_rows($r) > 0) { while ($row = mysqli_fetch_array($r, MYSQLI_ASSOC)) { echo "<h2>" . $row['post_title'] . "</h2>" . "<h3" . $row['post_subtitle'] . "</h3>" . "<p" . $row['post_body'] . "</p>" . "<p" . $row['created_on'] . "</p>" ; } } else { echo '<p>No posts to display at present.</p>'; } ?>

I don't understand your question

http://www.phpfreaks.com/tutorial/basic-pagination

I got it, thanks! while($row = $db->sql_fetchrow($result)) { var_dump($row); };

So I should loop this? $result = $db->sql_query($sql);

Shouldn't both values be inside of $row though? When I use a var_dump I'm only getting one value? I tried using a foreach, and every result came out with 59.

$sql = "SELECT * FROM table"; $result = mysql_query($sql); $row = mysql_fetch_array($result); $rand_keys = array_rand($row, 6); then loop it.

$sql = "SELECT poster_id from phpbb_posts WHERE topic_id = ".$topic_id." "; $result = $db->sql_query($sql); //same as mysql_query $row = $db->sql_fetchrow($result); // same as mysql_fetch array. var_dump($row); With this code (i commented the query function for you) im getting array 'poster_id' => string '59' (length=2) When I run this into SQL in phpmyadmin I'm getting 59 56 //this is what I want I need to get all of the records, not just the first one. I have even tried using replacing the function with mysql_query and mysql_fetch_array any ideas? It's a bit late, so I may just be making a simple mistake. Thanks!

I fixed this a few weeks ago, sorry for not letting you all know!

is somefile.html in a separate folder than index.php?

Set a root path var. For example: $root_path = http://www.google.com/ require($root_path . 'anyfolder/any.php')

Well yeah, I just didn't know how to approach it, but thanks! (Keeping the function name)

Is there a function which will allow me to throw the values into an array and post them into the DB as separate records? If so a little help would be appreciated! if(empty($row)) { //Need a better way. $sql = "INSERT INTO phpbb_user_items VALUES (13, '$user_id', '0'), (12, '$user_id', '0'), (11, '$user_id', '0'), (9, '$user_id', '0'), (27, '$user_id', '0'), (15, '$user_id', '0'), (16, '$user_id', '0'), (22, '$user_id', '0'), (21, '$user_id', '0'), (23, '$user_id', '0'), (24, '$user_id', '0'), (26, '$user_id', '0'), (29, '$user_id', '0'), (30, '$user_id', '0'), (31, '$user_id', '0'), (32, '$user_id', '0'), (33, '$user_id', '0') "; $result = $db->sql_query($sql); }

It would be an ajax call. You'd have javascript talk to a php file which would check that specific table to see if it's been updated. Afterwards, you'd display a message saying that it has been updated, or display the information that was inserted/updated with ajax. http://api.jquery.com/jQuery.ajax/

Where's your mysql connection?

Just throw a variable into the slider and in the interval? var refreshId = setInterval(function() { $("#container").load('stats.php'); },time); (I didnt download the slider or anything, so bare with me..) time = 800;

The image is showing up fine, but when i does, its black. It's suppose to just be a transparent square.

function buildAvatar(array $imgArray = array()) { $img1 = imagecreatefrompng($phpbb_root_path.'images/spacer.png'); foreach($imgArray as $img) { $img2 = imagecreatefrompng($phpbb_root_path.'avatars/equip_img/'.$img); $this->imagecopymerge_alpha($img1, $img2, 0, 0, 0, 0, 210, 300, 100); } imagealphablending($img1, false); imagesavealpha($img1, true); return $img1; } The background of my PNG was transparent, I don't know what I did, but it's now black! I'm thinking it's the image! Not the code, this same code worked before, and I've tried tons of different ways of fixing it. How should I save the image to work correctly?

My site has had all of it's tables dropped TWICE I CAN'T FIND THE INJECTION, can anyone help? http://www.threechan.org/e/ http://www.threechan.org/e/phpfreaks.txt please, someone help

I'm trying to alow users to reference links, but I'm stumped. $com = preg_replace("/(^|<<)(<<[^<]*[0-9])/", "\\1<a href = #".$com.">#$com</a>\\2</div>", $com); If I typed <<#123 I would get: #<<123<<123 and it would link to <<123 The output I'm looking for is <<#123 and have it link to #123

Thanks guys.

Thanks! Really appreciate it.

Hey sounds good! And yeah, an example would be fabulous!!

My first time writing HTML and CSS from scratch i usually use a free template but i got bored a decided to try it myself, what do you guys think? most link will be broken. concido.tk