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Hi guys, I really hope this will make sense. I am creating a dynamic field on a button click for Pickup Location. That works fine and submitting the form to the database works fine. However, instead of one entry, each time I submit the form with multiple Pickup Locations, it creates multiple separate database entries. Here is the PHP for submitting: if(isset($_POST['new']) && $_POST['new']==1){ $pickups = ''; foreach($_POST['pickups'] as $cnt => $pickups) $pickups .= ',' .$pickups; $locations = count($_POST["pickups"]); if ($locations > 0) { for ($i=0; $i < $locations; $i++) { if (trim($_POST['pickups'] != '')) { $name = mysqli_real_escape_string($con, $_POST['name']); $price = mysqli_real_escape_string($con, $_POST['price']); //$origin = $_POST['origin']; $pickups = $_POST["pickups"][$i]; $destination = mysqli_real_escape_string($con, $_POST['destination']); $dep_date = mysqli_real_escape_string($con, $_POST['dep_date']); $ret_date = mysqli_real_escape_string($con, $_POST['ret_date']); $fleet_number = mysqli_real_escape_string($con, $_POST['fleet_number']); $driver = mysqli_real_escape_string($con, $_POST['driver']); $itinerary = mysqli_real_escape_string($con, $_POST['itinerary']); $submittedby = mysqli_real_escape_string($con, $_SESSION["username"]); $trn_date = mysqli_real_escape_string($con, date("Y-m-d H:i:s")); $query="insert into tours (`name`, `price`, `pickups`, `destination`, `dep_date`, `ret_date`, `fleet_number`, `driver`, `itinerary`, `submittedby`, `trn_date`)values ('$name', '$price', '$pickups', '$destination', '$dep_date', '$ret_date', '$fleet_number', '$driver', '$itinerary', '$submittedby', '$trn_date')"; mysqli_query($con,$query) or die(mysqli_error($con)); if(mysqli_affected_rows($con)== 1 ){ $message = '<i class="fa fa-check"></i> - Record Inserted Successfully'; } } } } } Here is the HTML form: <form role="form" method="post" name="add_tour" id="add_tour" action""> <input type="hidden" name="new" value="1" /> <div class="modal-body"> <div class="row form-group"> <div class="col-6"> <div class="form-group"><label for="name" class=" form-control-label">Name</label><input type="text" id="name" name="name" placeholder="Tour Name" class="form-control"> </div> </div> <div class="col-6"> <div class="form-group"><label for="price" class=" form-control-label">Price</label><input type="text" id="price" name="price" placeholder="0.00" class="form-control"> </div> </div> </div> <div class="row form-group"> <div class="col-6"> <div class="form-group origin" id="pickupsfield"><label for="pickups" class=" form-control-label">Pickup Location</label><input type="text" id="pickups" name="pickups[]" placeholder="Start Typing..." class="form-control"></div> <button type="button" class="btn btn-success add-field" id="add" name="add">Add New Location &nbsp; <span style="font-size:16px; font-weight:bold;">+ </span> </button> </div> <div class="col-6"> <div class="form-group"><label for="destination" class=" form-control-label">Destination</label><input type="text" id="destination" name="destination" placeholder="Start Typing..." class="form-control"></div> </div> </div> <div class="row form-group"> <div class="col-6"> <div class="form-group"><label for="dep_date" class=" form-control-label">Departure Date</label><input type="date" id="dep_date" name="dep_date" placeholder="" class="form-control"></div> </div> <div class="col-6"> <div class="form-group"><label for="ret_date" class=" form-control-label">Return Date</label><input type="date" id="ret_date" name="ret_date" placeholder="" class="form-control"></div> </div> </div> <div class="row form-group"> <div class="col-6"> <div class="form-group"><label for="fleet_number" class=" form-control-label">Fleet Number</label> <select class="form-control" id="fleet_number" name="fleet_number"> <option value="Select">== Select Fleet Number ==</option> <?php $sql = "SELECT fleet_number FROM fleet"; $result = $con->query($sql); while(list($fleet_number) = mysqli_fetch_row($result)){ $option = '<option value="'.$fleet_number.'">'.$fleet_number.'</option>'; echo ($option); } ?> </select> </div> </div> <div class="col-6"> <?php ?> <div class="form-group"><label for="driver" class=" form-control-label">Driver</label> <select class="form-control" id="driver" name="driver"> <option value="Select">== Select Driver ==</option> <?php $sql = "SELECT name FROM drivers"; $result = $con->query($sql); while(list($driver) = mysqli_fetch_row($result)){ $option = '<option value="'.$driver.'">'.$driver.'</option>'; echo ($option); } ?> </select> </div> </div> </div> <div class="form-group"><label for="itinerary" class=" form-control-label">Itinerary</label> <textarea class="form-control" id="itinerary" name="itinerary"></textarea> </div> <div class="modal-footer"> <button type="reset" class="btn btn-warning">Clear Form</button> <button type="submit" name="submit" id="submit" class="btn btn-primary">Confirm</button> </div> </form> And the Javascript for adding the new fields: <script> $(document).ready(function(){ var i = 1; $("#add").click(function(){ i++; $('#pickupsfield').append('<div id="row'+i+'"><input type="text" name="pickups[]" placeholder="Enter pickup" class="form-control"/></div><div><button type="button" name="remove" id="'+i+'" class="btn btn-danger btn_remove">X</button></div>'); }); $(document).on('click', '.btn_remove', function(){ var button_id = $(this).attr("id"); $('#row'+button_id+'').remove(); }); $("#submit").on('click',function(){ var formdata = $("#add_tour").serialize(); $.ajax({ url :"", type :"POST", data :formdata, cache :false, success:function(result){ alert(result); $("#add_tour")[0].reset(); } }); }); }); </script> Anyone have any idea where I am going wrong? Before you say it, Yes, I know, Use Prepared statements 😷

http://www.tirerack.com/content/tirerack/desktop/en/wheels.html See the window where it says "Shop by Vehicle"? Is there a script already out there that does the dropdown search by make/model/year? I am only looking for the front-end code; javascript/jquery code in particular.

Hi all, I was hoping you could point me in the right direction, I have 2 questions. 1. I want to have an option drop down which uses the array of a returned sql query. I have the following code which uses onchange to submit the selection, how do I use the mysql_fetch_array($result1) to give a list of the two selected columns in the $Site=array() bit. 2. The selected result will be used in more SQL select statements, so once a site from the list is selected the relevant data from other tables will be displayed using e.g. select person from people [some inner join statement] where site="site 1"; Therefore the $_POST value must be available to be passed to other queries once selected. Thanks for any help, I still feel like a noob, but I'm getting there. Gary <?php include 'header.php'; ?> <div class='container'> <?php include 'menu.php'; ?> <?php include 'connect.php'; ?> <?php $sql1="SELECT Sites.Site_ID, Sites.Site_name_1 FROM `Sites`"; $result1=mysql_query($sql1); ?> <?php function get_options() { $site=array('Site 1'=>'Site 1', 'Site 2'=>'Site 2', 'Site 3'=>'Site 3'); $options=''; while(list($k,$v)=each($site)) { $options.='<option value="'.$v.'">'.$k.'</option>'; } return $options; } if(isset($_POST['site'])) { echo $_POST['site']; } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST"> <select name="site" onchange="this.form.submit();"> <?php echo get_options(); ?> </select>