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Found 1 result

  1. Hi all, I was hoping you could point me in the right direction, I have 2 questions. 1. I want to have an option drop down which uses the array of a returned sql query. I have the following code which uses onchange to submit the selection, how do I use the mysql_fetch_array($result1) to give a list of the two selected columns in the $Site=array() bit. 2. The selected result will be used in more SQL select statements, so once a site from the list is selected the relevant data from other tables will be displayed using e.g. select person from people [some inner join statement] where site="site 1"; Therefore the $_POST value must be available to be passed to other queries once selected. Thanks for any help, I still feel like a noob, but I'm getting there. Gary <?php include 'header.php'; ?> <div class='container'> <?php include 'menu.php'; ?> <?php include 'connect.php'; ?> <?php $sql1="SELECT Sites.Site_ID, Sites.Site_name_1 FROM `Sites`"; $result1=mysql_query($sql1); ?> <?php function get_options() { $site=array('Site 1'=>'Site 1', 'Site 2'=>'Site 2', 'Site 3'=>'Site 3'); $options=''; while(list($k,$v)=each($site)) { $options.='<option value="'.$v.'">'.$k.'</option>'; } return $options; } if(isset($_POST['site'])) { echo $_POST['site']; } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="POST"> <select name="site" onchange="this.form.submit();"> <?php echo get_options(); ?> </select>
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