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Found 2 results

  1. Hi guys, I really hope this will make sense. I am creating a dynamic field on a button click for Pickup Location. That works fine and submitting the form to the database works fine. However, instead of one entry, each time I submit the form with multiple Pickup Locations, it creates multiple separate database entries. Here is the PHP for submitting: if(isset($_POST['new']) && $_POST['new']==1){ $pickups = ''; foreach($_POST['pickups'] as $cnt => $pickups) $pickups .= ',' .$pickups; $locations = count($_POST["pickups"]); if ($locations > 0) { for ($
  2. This is the code for a dynamic dropdown list which i use to create a record. It works. But i find it slow when updating a record. It takes time to load the cities dropdown data. I am wondering, is there a more efficient way to do this dropdown so it loads the data more quickly? <script> function getCity(val) { $.ajax({ type: "POST", url: "../snippets/get_cities.php", data:'state_id='+val, success: function(data){ $("#city-list").html(data); } }); } function getState(val) { $.ajax({ type: "POST", url: "../snippets/get_states.php"
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