Logged_In Display

[DeanWhitehouse]

<?php
if ($_SESSION['is_valid'] == true){
if ($_SESSION['user_level'] == 2){
mysql_query("SELECT * from `$user` WHERE user_name");
echo "<table class='logged_in'><tr><td>
Welcome $user_name,<br>
<a href=''>User Profile</a><br>
<a href=''>Settings</a>
<a href='logout.php'>Logout</a>
</td></tr><tr><td><font color='white'>Logged In</font></td></tr></table>";
}
if ($_SESSION['user_level'] == 1){
mysql_query("SELECT * from `$user` WHERE user_name");
echo "<table class='logged_in'><tr><td>
Welcome $user_name,<br>
<a href=''>User Profile</a><br>
<a href=''>Settings</a>
<a href='logout.php'>Logout</a>
</td></tr><tr><td><font color='white'>Logged In</font></td></tr></table>";
}
else
{
include_once'login.php';
}
}
?>

 

this code is ment to display a login form if the user is not logged in, but it doesn't, and i dunno why

[DarkWater]

Dude. Stop using these `````` quotes on the queries. >_>

[Fadion]

Shouldnt a normal query be:

 

"SELECT * FROM users WHERE username='$user_name'";

 

???

[DeanWhitehouse]

the table name is saved as a variable, so no to "SELECT * FROM users and i want to display the users username, but i can't think of a way to.

Anyway back to the main problem, of the login page not displaying

[DarkWater]

Yeah, Guiltygear is right.  Your WHERE statement is messed up too.

[DeanWhitehouse]

ok, people ignore the sql statement,

[DarkWater]

I see the problem.

The last lines look like this:

else

{

include_once'login.php';

}

}

 

Should be:

}

else

{

include_once ('login.php');

}

 

So that the else statement applies to the if ($_SESSION['is_valid'] == true){ conditional. =)

And the include should be:

include_once ('login.php');

Not:

include_once'login.php';

 

[DeanWhitehouse]

when i remove the curly bracket i get this error

Parse error: syntax error, unexpected $end in /home/www/deanwhitehouse.awardspace.co.uk/logged_in.php on line 26

and you can write includes and requires without the brackets

[redarrow]

Do you mean this?

 

<?php session_start();

if ($_SESSION['is_valid'] == true){

if ( ($_SESSION['user_level'] == 1) || ($_SESSION['user_level2'] == 2) ){

	mysql_query("SELECT * from `$user` WHERE user_name='$user_name'");

	echo "<table class='logged_in'><tr><td>
Welcome $user_name,<br>
<a href=''>User Profile</a><br>
<a href=''>Settings</a>
<a href='logout.php'>Logout</a>
</td></tr><tr><td><font color='white'>Logged In</font></td></tr></table>";

}else{

include_once'login.php';
}
}
?>

[DarkWater]

when i remove the curly bracket i get this error

Parse error: syntax error, unexpected $end in /home/www/deanwhitehouse.awardspace.co.uk/logged_in.php on line 26

and you can write includes and requires without the brackets

 

You missed what I said.  Move the last } to right above the else block. >_>  Copy and paste exactly what I put. =/

[DeanWhitehouse]

ok, thanks,

this is now my working code

<?php
require_once 'includes/config_table.inc.php';
require_once 'includes/db_connect.php';
mysql_query("SELECT * from `$user` WHERE user_name='$user_name'");
if ($_SESSION['is_valid'] == true){
if ($_SESSION['user_level'] == 2){
echo "<table class='logged_in'><tr><td>
Welcome $user_name,<br>
<a href=''>User Profile</a><br>
<a href=''>Settings</a>
<a href='logout.php'>Logout</a>
</td></tr><tr><td><font color='white'>Logged In</font></td></tr></table>";
}
if ($_SESSION['user_level'] == 1){

echo "<table class='logged_in'><tr><td>
Welcome $user_name,<br>
<a href=''>User Profile</a><br>
<a href=''>Settings</a>
<a href='logout.php'>Logout</a>
</td></tr><tr><td><font color='white'>Logged In</font></td></tr></table>";
}
}
else
{
include_once ('login.php');
}
?>

how can i display the user name of the user, i am using sessions and cookies

[iarp]

<?php echo $_SESSION['user_name']; ?>

[DeanWhitehouse]

ok, thanks for all the help.