HELP !!!! include (' $_GET['file'] ')

[Sangha-08]

The header says it all, could someone please tell me how to do this 

 

include(' Get this part from the url after file=') 

 

Thanks

[DeanWhitehouse]

you would do

 

include ($_GET['file']);

[kenrbnsn]

Doing that way without some checking can be very insecure.

 

To be more secure, put the files you know to be safe into an array and check the value being sent against those values.

 

Ken

[Sangha-08]

well .. i need more help now, i thought i could do what i want to do this way but it wont work

 

i want to do something like this -

<?php
include(http://someotherwebsite.com/video.php?id=$_GET['file']);
?>

 

Could you help me on that  ??? thanks for the quick reply, i appreciate it mate =)

 

[wildteen88]

From that url your provided seems you want to place a movie in your webpage. You should use file_get_contents instead. include/require should be use for including PHP source code.

 

You should make sure allow_url_fopen is enabled.

[Sangha-08]

i see.. but i want to copy the whole web page and make it look like its mine

 

for instance

 

I want to turn http://www.somerandomwebsite.com/video.php?id=110019 

to http://www.mywebsite.com/video.php?id=110019

[DeanWhitehouse]

I dunno if people are going to help you do that.

[wildteen88]

i see.. but i want to copy the whole web page and make it look like its mine

 

for instance

 

I want to turn http://www.somerandomwebsite.com/video.php?id=110019

to http://www.mywebsite.com/video.php?id=110019

As long as your are not ripping the other site then file_get_contents will do what you want. There is no point in using a http url within include/require as only the output (text/html) of the requested script (video.php) will be returned, not the PHP source code. This is why I told you to use file_get_contents.

[Sangha-08]

OH NO NO I HAVE permission, my bro owns the other website

[DeanWhitehouse]

then why not get the code from the pages from him and just make them on your website?

[Sangha-08]

because my server is not powerful enough to do that

[DeanWhitehouse]

then include won't work, as it will basically put the code into the page and load it.

[wildteen88]

Whats the server got to do with it? Whats wrong with my suggestion earlier?

[Sangha-08]

well , i cant get it to work .. i need to make it look like http://www.mydomain.com/vid.php?id=1199191818 from http://www.mybroswebsite.com/vid.php?id=1199191818

[Sangha-08]

OMG IS Any1 gonna help me ?  ??? ??? ??? ???

[DarkWater]

We're all trying to help you.  If your brother has such an amazing website that your server can't handle, he should know how to do this, right?  Why don't you show us what you have right now and tell us which errors (if any) it displays.  How about that?

[wildteen88]

You're not explaining yourself properly, What do want it to look like? How are we supposed to know whats supposed to look like if you give us fake urls.

 

If you did:

echo file_get_contents('http://www.google.com');

The google homepage will be displayed on your site. The same applies to the urls you're providing.