[SOLVED] echo file_get_contents query

[e1seix]

Problem... and hopefully an easy one to solve with someone's help.

 

My page in question is "video.php" from whose address bar i use $vidID=$_GET['vidID']; to obtain the vidID variable. Now, within my page i use quite a few of echo file_get_contents to break down my website and make it easier to design and manage.

 

From "video.php" i use echo file_get_contents to load "screen.php"

 

My problem is that I need to be able to use the $vidID variable WITHIN screen.php, but the information doesn't seem to work...

 

how can i invisibly transport the value of $vidID into screen.php?

 

Many thanks in advance my favourite people!

[JasonLewis]

Are you thinking of including files? Or do you want to load their contents?

[e1seix]

load the file and its code in it's entirety

[MasterACE14]

<?php
include("file.php"); // includes the file
file_get_contents("file.php"); // grabs the file
?>

[Fadion]

Including the file is the way to go and you'll retain variable scope within the included file.

[e1seix]

isn't including the file getting phased out?

 

stupid question, but can I ask... what is the sodding difference between the two? lol. I always get confused and play about until one or the other works the way I want it to

[DarkWater]

*facepalm*

 

When you use file_get_contents() and pass it a filesystem filename rather than a URL, it just reads the file.  If you pass it a full URL so PHP uses its file wrapper, you get the output of the script.  include actually executes a file on the filesystem and incorporates it into the current script.

[JasonLewis]

Did you read the link that I posted?

The manual is a great place to read up on these things.

[e1seix]

a-ha... so how do we explain the error message?

 

Warning: include() [function.include]: URL file-access is disabled in the server configuration in /home/e1seix/public_html/advice/video.php on line 16

[DarkWater]

Use the filename on the filesystem and NOT the URL.

 

include('foo.php'); <- Right

include('http://www.example.com/foo.php'); <- Wrong

[e1seix]

it is actually beginning to sink in, and i am grateful for having patience to explain it to me. Having one last error though...

 

the url of the page in question is "...co.uk/advice/video.php" and the one i'm trying to include is "...co.uk/contents/screen.php"

 

they're no hierarchy, they're in completely different folders. shouldn't the follwing be working so?

 

video.php contains...

 

echo include("/contents/screen.php");

 

cos now i'm getting

 

Warning: include(/contents/screen.php) [function.include]: failed to open stream: No such file or directory in /home/e1seix/public_html/advice/video.php on line 16

 

Warning: include() [function.include]: Failed opening '/contents/screen.php' for inclusion (include_path='.:/usr/lib/php:/usr/local/lib/php') in /home/e1seix/public_html/advice/video.php on line 16

 

in my defence, it's late for me. lol

[DarkWater]

You cannot echo an include, by the way.  Just include(), with no echo.

 

include('../contents/screen.php');

 

P.S: For anyone who wants to correct me, I know that you CAN echo an include() if it returns something, but that's not the case here and it's not all too common anyway.

[e1seix]

Wasn't too sure about that one, but the exact same error remains even with the echo removed... any ideas?

[JasonLewis]

If you echo an include, if the include was successful it will just echo 1, meaning true. No point really.

You need the ../ to go to the directory lower. Look at DarkWaters post carefully.

[Fadion]

If you echo an include, if the include was successful it will just echo 1, meaning true. No point really.

 

<?php
//file phpfreaks.php
echo 'phpfreaks';
?>
<?php
//some other file
echo include('phpfreaks.php'); //will return: phpfreaks1
?>

 

Your point is right though, what's the meaning of echoing an included file