Dan06 Posted November 17, 2008 Share Posted November 17, 2008 I'm trying to create a dynamic form that is made up of dynamically created check boxes. I can't figure out why I'm getting the following error message: Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING Below is my code, if anyone has any idea or suggestions as to how I can get my code to work, please share them. Thanks. $domesticGoods = "SELECT categoryName FROM categories WHERE categoryType="."'".Domestic."'"; $domesticGoodsResult = mysql_query($domesticGoods, $connected); $internationalGoods = "SELECT categoryName FROM categories WHERE categoryType=". "'".International."'"; $internationalGoodsResult = mysql_query($internationalGoods, $connected); echo <<<END <form name="categoryRegister" id="categoryRegister" method="post" onsubmit="return categoryRegistration()"> <table width="600" border="0" cellpadding="10" cellspacing="0"> <tr> <td> while($row = msql_fetch_assoc($domesticGoodsResult)){ <center><input type="checkbox" name=$row['categoryName'] id=$row['categoryName'] value=$row['categoryName']/>$row['categoryName']</center><br/> } </td> <td> while($row = msql_fetch_assoc($internationalGoodsResult)){ <center><input type="checkbox" name=$row['categoryName'] id=$row['categoryName'] value=$row['categoryName']/>$row['categoryName']</center><br/> } </td> </tr> <tr> <td colspan="2"><center><input type="submit" name="submit" value="Sign-Up"/></center> <input type="hidden" name="type" value="goodsInfo" /> </td> Quote Link to comment https://forums.phpfreaks.com/topic/133129-trouble-with-form-creation/ Share on other sites More sharing options...
premiso Posted November 17, 2008 Share Posted November 17, 2008 You are mixing PHP with HTML and php cannot parse that you need to exit in and out of PHP or echo the html out. <?php $domesticGoods = "SELECT categoryName FROM categories WHERE categoryType='Domestic' OR categoryType='International' "; $domesticGoodsResult = mysql_query($domesticGoods, $connected); $internationalGoods = "SELECT categoryName FROM categories WHERE categoryType='International'"; $internationalGoodsResult = mysql_query($internationalGoods, $connected); echo '<form name="categoryRegister" id="categoryRegister" method="post" onsubmit="return categoryRegistration()"> <table width="600" border="0" cellpadding="10" cellspacing="0"> <tr> <td>'; while($row = msql_fetch_assoc($domesticGoodsResult)){ echo '<center><input type="checkbox" name= ' . $row['categoryName'] . ' id=' . $row['categoryName'] . ' value=' . $row['categoryName'] . ' />' . $row['categoryName'] . '</center><br/>'; } echo '</td> <td>'; while($row = msql_fetch_assoc($internationalGoodsResult)){ echo '<center><input type="checkbox" name= ' . $row['categoryName'] . ' id=' . $row['categoryName'] . ' value=' . $row['categoryName'] . ' />' . $row['categoryName'] . '</center><br/>'; } echo ' </td> </tr> <tr> <td colspan="2"><center><input type="submit" name="submit" value="Sign-Up"/></center> <input type="hidden" name="type" value="goodsInfo" /> </td>'; ?> Edit also assumed that you wanted it to be just "International" or "Domestic" and changed that portion as well. Quote Link to comment https://forums.phpfreaks.com/topic/133129-trouble-with-form-creation/#findComment-692332 Share on other sites More sharing options...
flyhoney Posted November 17, 2008 Share Posted November 17, 2008 $domesticGoods = "SELECT categoryName FROM categories WHERE categoryType="."'".Domestic."'"; That needs to be either: $domesticGoods = "SELECT categoryName FROM categories WHERE categoryType='$Domestic'"; or $domesticGoods = "SELECT categoryName FROM categories WHERE categoryType='Domestic'"; depending on what you are trying to do. And you need to end your heredoc with END; Quote Link to comment https://forums.phpfreaks.com/topic/133129-trouble-with-form-creation/#findComment-692333 Share on other sites More sharing options...
flyhoney Posted November 17, 2008 Share Posted November 17, 2008 Here are some updates to your code. However, like premiso said, you are mixing PHP and HTML and you cannot do that. <?php $domesticGoods = "SELECT categoryName FROM categories WHERE categoryType='Domestic'"; $domesticGoodsResult = mysql_query($domesticGoods, $connected); $internationalGoods = "SELECT categoryName FROM categories WHERE categoryType='International'"; $internationalGoodsResult = mysql_query($internationalGoods, $connected); ?> <form name="categoryRegister" id="categoryRegister" method="post" onsubmit="return categoryRegistration()"> <table width="600" border="0" cellpadding="10" cellspacing="0"> <tr> <td> <?php while($row = msql_fetch_assoc($domesticGoodsResult)){ ?> <center> <input type="checkbox" name="<?php echo $row['categoryName'] ?>" id="<?php echo $row['categoryName']?>" value="<?php echo $row['categoryName'] ?>" /> <?php echo $row['categoryName'] ?> </center><br/> <?php } ?> </td> <td> <?php while($row = msql_fetch_assoc($internationalGoodsResult)){ ?> <center> <input type="checkbox" name="<?php echo $row['categoryName'] ?>" id="<?php echo $row['categoryName']?>" value="<?php echo $row['categoryName'] ?>" /> <?php echo $row['categoryName'] ?> </center><br/> <?php } ?> </td> </tr> <tr> <td colspan="2"><center><input type="submit" name="submit" value="Sign-Up"/></center> <input type="hidden" name="type" value="goodsInfo" /> </td> Quote Link to comment https://forums.phpfreaks.com/topic/133129-trouble-with-form-creation/#findComment-692339 Share on other sites More sharing options...
Dan06 Posted November 18, 2008 Author Share Posted November 18, 2008 Thanks premiso and flyhoney for the responses. The problem, as you two correctly pointed out, was with the improper intermingling of php and html. I intended to use this form with my AJAX code, that is why I needed to echo/output the form. My focus was on making sure this dynamic form correctly produced the checkboxes and so I overlooked the important rule that php can't parse a heredoc with combined php and html. Quote Link to comment https://forums.phpfreaks.com/topic/133129-trouble-with-form-creation/#findComment-692788 Share on other sites More sharing options...
Dan06 Posted November 19, 2008 Author Share Posted November 19, 2008 I'd like to check this dynamic form to see if it properly creates checkboxes and the selected checkboxes have their values assigned to an array. I've put together some code to perform that check, but it is unable to: 1. Determine which (if any) checkboxes are selected. 2. Assign the selected checkbox value to an array. At this point I'm not sure if the form code is wrong or the code for checking the form is wrong. Below is my code. If anyone could tell me what is wrong with the verifying portion of the code or the dynamic form it would be appreciated. Thanks. <html> <head> <?php $domesticGoods = "SELECT categoryName FROM categories WHERE categoryType='Domestic'"; $domesticGoodsResult = mysql_query($domesticGoods, $connected); $internationalGoods = "SELECT categoryName FROM categories WHERE categoryType='International'"; $internationalGoodsResult = mysql_query($internationalGoods, $connected); echo '<form name="categoryRegister" id="categoryRegister" method="post"> <table width="600" border="0" cellpadding="10" cellspacing="0"> <tr> <td>'; while($domesticRow = msql_fetch_assoc($domesticGoodsResult)){ echo '<center><input type="checkbox" name= "' . $domesticRow['categoryName'] . '" id="' . $domesticRow['categoryName'] . '" value="' . $domesticRow['categoryName'] . '" />' . $domesticRow['categoryName'] . '</center><br/>'; } echo '</td> <td>'; while($interRow = msql_fetch_assoc($internationalGoodsResult)){ echo '<center><input type="checkbox" name= "' . $interRow['categoryName'] . '" id="' . $interRow['categoryName'] . '" value="' . $interRow['categoryName'] . '" />' . $interRow['categoryName'] . '</center><br/>'; } echo ' </td> </tr> <tr> <td colspan="2"><center><input type="submit" name="save" value="save"/></center>'; </head> <body> if(isset($_POST['save'])){ while($domesticRow = mysql_fetch_assoc($domesticCategoriesResult)){ if(isset($_POST[$domesticRow['categoryName']])){ $domesticCategoryArray[] = $domesticRow['categoryName']; } } while($interRow = mysql_fetch_assoc($interCategoriesResult)){ if(isset($_POST[$interRow['categoryName']])){ $interCategoryArray[] = $interRow['categoryName']; } } $domesticCategoryString = implode("," , $domesticCategoryArray); echo $dom = ($domesticCategoryString != "") ? 'NOT EMPTY' : 'Product String EMPTY'; $interCategoryString = implode("," , $interCategoryArray); echo '<br/>'; echo $inter = ($interCategoryString != "") ? 'NOT EMPTY' : 'Service String EMPTY'; $categoryList = $domesticCategoryString . $interCategoryString; ?> </body> </html> Quote Link to comment https://forums.phpfreaks.com/topic/133129-trouble-with-form-creation/#findComment-693703 Share on other sites More sharing options...
flyhoney Posted November 19, 2008 Share Posted November 19, 2008 You should probably use checkbox arrays. That might be easier. Here is an example of how that is accomplished <?php if ($_POST['action'] == 'Go') { $domestic = $_POST['domestic']; print_r($domestic); // the above will print an array, and the items in the array are all the values that were checked } ?> <form> <input type="checkbox" name="domestic[]" value="value 1" />Value 1 <input type="checkbox" name="domestic[]" value="value 2" />Value 2 <input type="submit" name="action" value="Go" /> </form> Quote Link to comment https://forums.phpfreaks.com/topic/133129-trouble-with-form-creation/#findComment-693762 Share on other sites More sharing options...
Dan06 Posted November 20, 2008 Author Share Posted November 20, 2008 I got the code to work using checkbox arrays; and you were right, it was a lot easier. Thanks for the suggestion and the example code. Quote Link to comment https://forums.phpfreaks.com/topic/133129-trouble-with-form-creation/#findComment-694652 Share on other sites More sharing options...
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