[SOLVED] Dont Display Link if already clicked

[gevans]

That will check if id is checked, and if it is only show that one title

[jnerotrix]

ok one last piece to edit

 

the index.php where it displays available surveys

 

===================================

 

Heres the code We need to make it so if it is in the complete_surveys then dont show that survey

 

<td><font size="6"> Surveys Available </font></td>
<td>
<?php
mysql_connect("localhost", "sex1800_admin", "12921993") or die(mysql_error()); //add you password
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$query = "SELECT * FROM survey";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<a href=\"survey.php?id={$row['id']}\">{$row['title']}</a><br>\n";
}
?>
</td></tr>
</table>

[gevans]

First of all we need to do some work on survey.php to run an sql query

 

You need to say

 

insert into the second table survey id and user id

 

let me know how u get on!

[jnerotrix]

Heres The Code I have to Do This

 

mysql_connect("localhost", "sex1800_admin", "12921993") or die(mysql_error());
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$member = mysql_real_escape_string($_SESSION['userid']);
$survey = mysql_real_escape_string($_GET['id']);

mysql_query("INSERT INTO completed_surveys 
(member_id, survey_id) VALUES('$member', '$survey') ") 
or die(mysql_error());  

 

[jnerotrix]

All we need to do is edit this code to only show surveys that havent been completed

 

 

<td><font size="6"> Surveys Available </font></td>
<td>
<?php
mysql_connect("localhost", "sex1800_admin", "12921993") or die(mysql_error()); //add you password
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$query = "SELECT * FROM survey";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<a href=\"survey.php?id={$row['id']}\">{$row['title']}</a><br>\n";
}
?>
</td></tr>
</table>

[premiso]

How do you know that a survey has not been completed? Answer that then add that identifier to the survey query in a WHERE clause and you got your answer.

[jnerotrix]

Thats alot of confusing stuff you just

 

I know its completed if its in the member id and survey id is in completed_surveys

table

 

but i dont know how to make it so if its in the table to tell the survey to be hidden

 

[gevans]

change this;

 

</tr>

<?php
mysql_connect("localhost", "sex1800_admin", "****") or die(mysql_error()); //add you password
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$query = "SELECT * FROM surveys";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<tr><td><a href="survey.php?id={$row['id']}">{$row['title']}</a></td></tr> ";
}

 

to this;

 

</tr>

<?php
mysql_connect("localhost", "sex1800_admin", "****") or die(mysql_error()); //add you password
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$query = "SELECT * FROM surveys JOIN completed_surveys ON surveys.id!=completed_surveys.survey_id AND memberid={$_SESSION['userid']}";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<tr><td><a href="survey.php?id={$row['id']}">{$row['title']}</a></td></tr> ";
}

[jnerotrix]

Now i get this Error

 

Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /home3/sex1800/public_html/epicbux/index.php on line 95

 

Heres lines 85 - 100

 

<tr>
<td><font size="6"> Surveys Available </font></td>
<td>
<?php
mysql_connect("localhost", "sex1800_admin", "12921993") or die(mysql_error()); //add you password
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$query = "SELECT * FROM surveys JOIN completed_surveys ON surveys.id!=completed_surveys.survey_id AND memberid={$_SESSION['userid']}";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<tr><td><a href="survey.php?id={$row['id']}">{$row['title']}</a></td></tr>";
}
?>
</td></tr>
</table>

[premiso]

echo "<tr><td><a href="survey.php?id={$row['id']}">{$row['title']}</a></td></tr>";

should be

echo "<tr><td><a href=\"survey.php?id={$row['id']}\">{$row['title']}</a></td></tr>";

 

You have to escape " inside of ".

[gevans]

<tr>
<td><font size="6"> Surveys Available </font></td>
<td>
<?php
mysql_connect("localhost", "sex1800_admin", "****") or die(mysql_error()); //add you password
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$query = "SELECT * FROM surveys JOIN completed_surveys ON surveys.id!=completed_surveys.survey_id AND memberid={$_SESSION['userid']}";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<tr><td><a href="survey.php?id={$row['id']}">{$row['title']}</a></td></tr>";
}
?>
</td></tr>
</table>

[jnerotrix]

now it displays the page but where it should display the surveys it displays

 

Unknown column 'df1063585e41cc161b358347877f900c' in 'on clause'

 

Heres the code though i fixed it to match my tables

 

<?php
mysql_connect("localhost", "sex1800_admin", "12921993") or die(mysql_error()); //add you password
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$query = "SELECT * FROM survey JOIN completed_surveys ON survey.id!=completed_surveys.survey_id AND member_id={$_SESSION['userid']}";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<tr><td><a href=\"survey.php?id={$row['id']}\">{$row['title']}</a></td></tr>";
}
?>

[gevans]

did you get the same error after doing that?

[jnerotrix]

yea

 

Tables:

 

survey

*id

*title

*adlink

 

completed_surveys

*member_id

*survey_id

[gevans]

put this in for an error check;

 

<?php
mysql_connect("localhost", "sex1800_admin", "12921993") or die(mysql_error()); //add you password
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$query = "SELECT * FROM survey JOIN completed_surveys ON survey.id!=completed_surveys.survey_id AND member_id={$_SESSION['userid']}";
echo $query;
die();
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<tr><td><a href=\"survey.php?id={$row['id']}\">{$row['title']}</a></td></tr>";
}
?>

[jnerotrix]

it says

 

SELECT * FROM survey JOIN completed_surveys ON survey.id!=completed_surveys.survey_id AND member_id=df1063585e41cc161b358347877f900c <-- this is the problem

[gevans]

Can you look into the completed_surveys table and see what data you currently have in there?

[jnerotrix]

member_id - survey_id

0 - 1

0 - 2

0 - 1

[gevans]

ok, having a little error

 

didn't realise that the member_id was hashed.

 

in the table completed_surveys change member_id from INT to VARCHAR 32

[jnerotrix]

what should i put for the mysql code

 

instead of this

<?php
mysql_connect("localhost", "sex1800_admin", "12921993") or die(mysql_error()); //add you password
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$query = "SELECT * FROM survey JOIN completed_surveys ON survey.id!=completed_surveys.survey_id AND member_id={$_SESSION['userid']}";
echo $query;
die();
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<tr><td><a href=\"survey.php?id={$row['id']}\">{$row['title']}</a></td></tr>";
}
?>

[gevans]

ok, having a little error

 

didn't realise that the member_id was hashed.

 

in the table completed_surveys change member_id from INT to VARCHAR 32

 

 

did you do that??

 

If you did delete all the entries in the table and it should work fine

[jnerotrix]

yes i did and deleted all that data in it so and i open the index page and still get this

 

SELECT * FROM survey JOIN completed_surveys ON survey.id!=completed_surveys.survey_id AND member_id=324a6953910123430fa8e36e055d3c41

[gevans]

ok, change this

 

<?php
mysql_connect("localhost", "sex1800_admin", "12921993") or die(mysql_error()); //add you password
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$query = "SELECT * FROM survey JOIN completed_surveys ON survey.id!=completed_surveys.survey_id AND member_id={$_SESSION['userid']}";
echo $query;
die();
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<tr><td><a href=\"survey.php?id={$row['id']}\">{$row['title']}</a></td></tr>";
}
?>

 

back to this

 

<?php
mysql_connect("localhost", "sex1800_admin", "12921993") or die(mysql_error()); //add you password
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$query = "SELECT * FROM survey JOIN completed_surveys ON survey.id!=completed_surveys.survey_id AND member_id={$_SESSION['userid']}";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<tr><td><a href=\"survey.php?id={$row['id']}\">{$row['title']}</a></td></tr>";
}
?>

[jnerotrix]

Now it says

 

Unknown column '8190ef16bc01b56546027a349806ad2a' in 'on clause'

[gevans]

try this;

 

<?php
mysql_connect("localhost", "sex1800_admin", "12921993") or die(mysql_error()); //add you password
mysql_select_db("sex1800_loginbux") or die(mysql_error());

$query = "SELECT * FROM survey JOIN completed_surveys ON survey.id!=completed_surveys.survey_id WHERE member_id={$_SESSION['userid']}";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result)){
echo "<tr><td><a href=\"survey.php?id={$row['id']}\">{$row['title']}</a></td></tr>";
}
?>