rugzo Posted December 27, 2008 Share Posted December 27, 2008 Hi all, i have a question where i am stucked. We want to build a database for our work. There will be a html and a php page. In the html page you will have a list of subjects. If you click on the subject it should post it to the php page where the result from mysql is shown. But i have a problem by building the variable. I will give a simple example. the html page is ---> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-9" /> <script type="text/javascript" language="javascript1.2"> function goster_gizle(x) { if ( document.getElementById(x).style.display == '' ) { document.getElementById(x).style.display = 'none' } else { document.getElementById(x).style.display = '' } } </script> <style type="text/css"> .ust_menu{ width: 150px; padding: 3px; border:1px solid #ccc; } .ust_menu a{ text-decoration: none } .alt_menu { padding-left: 10px; } </style> </head> <body> <form action="result.php" method="post"> <div class="ust_menu"><a href="javascript:goster_gizle('alt_menu_1')">VPN</a> <div class="alt_menu" id="alt_menu_1" style="display:none"> <a href="javascript:goster_gizle('alt_menu_2')">Corina</a> <br> <div class="alt_menu" id="alt_menu_2" style="display:none"> [b]<input type="submit" name="corina_account_request" value="corina account request">[/b] </div> <a href="javascript:goster_gizle('alt_menu_3')">Nira</a> <br> <div class="alt_menu" id="alt_menu_3" style="display:none"> Konu 2-2</div> <a href="javascript:goster_gizle('alt_menu_4')">RLA</a> <br> <div class="alt_menu" id="alt_menu_4" style="display:none"> Konu 3-3</div> <a href="javascript:goster_gizle('alt_menu_5')">Cisco</a> <br> <div class="alt_menu" id="alt_menu_5" style="display:none"> <a href="1.htm">Konu 4-4 </a></div> <a href="javascript:goster_gizle('alt_menu_6')">CheckPoint</a> <div class="alt_menu" id="alt_menu_6" style="display:none"> <a href="1.htm">Konu 4-4</a></div> </div> </div> I marked the important thing here with green. If for example the subject "corina account request" is clicked it should post the value "corina_account_request" to the php page. The php page should get this and put it into the sql query. here is the php page -->>> <?php @mysql_connect ("localhost","root","123*qwe123") or die ("nix sql") ; @mysql_select_db ("kb") or die ("nix db") ; $search = $_POST["name"] ?> <table border="1" cellpadding="0" cellspacing="0"> <tr> <td>Id</td> <td><?php $sql = mysql_query ("SELECT * FROM subjects where Subject = '$search' ") ; while ($liste = mysql_fetch_array($sql)) { echo "$liste[0]"; ?><? } mysql_free_result($sql); echo mysql_error() ; ?></td> </tr> but off course it doesn't work. The important thing for me is to get the value into this variable--> $search = $_POST["name"] it should basicly take the subject from the html page (there will be many) and put it into the query. Can please someone help me. thanks very much Quote Link to comment Share on other sites More sharing options...
Philip Posted December 27, 2008 Share Posted December 27, 2008 Why not just use GET variables? Instead of the form/submit button: <a href='result.php?name=corina_account_request'>Corina account request</a> In the PHP file: <?php mysql_connect ("localhost","user","pass") or die (mysql_error()) ; mysql_select_db ("kb") or die (mysql_error()) ; $search = $_GET["name"]; // make sure to clean this variable - running the risk of SQL injection ?> <table border="1" cellpadding="0" cellspacing="0"> <tr> <td>Id</td> <td><?php $sql = mysql_query ("SELECT * FROM subjects where Subject = '$search' ") ; while ($liste = mysql_fetch_array($sql)) { echo $liste[0]; } mysql_free_result($sql); ?></td> </tr> If you don't like my way, thats fine. You do have a missing semicolon though (in result.php): $search = $_POST["name"] Oh, and next time, don't forget the [ code ][/ code ] tags It makes it easier on us to read your code. Quote Link to comment Share on other sites More sharing options...
revraz Posted December 27, 2008 Share Posted December 27, 2008 Why are you putting a SQL query into a Table? Sounds like you need to learn PHP and HTML a bit more. Quote Link to comment Share on other sites More sharing options...
shadiadiph Posted December 27, 2008 Share Posted December 27, 2008 you could try this $search = ($_POST["corina_account_request"]); but that will only post corina_account_request as that is the value of name= Quote Link to comment Share on other sites More sharing options...
rugzo Posted December 27, 2008 Author Share Posted December 27, 2008 Thanks for the quick replies... Hi shadiadiph, thanks for the suggestion, but as you said it would only post corina. Hi revraz, i am a beginner who is trying to learn from e-books and forums by himself. Thats why i wrote here in hope for help. You should not criticise people but help if you are a member in such a forum like this. This only demoralizes people who are searching for help. I think this is the right topic "PHP Help". And Hi KingPhilip, your suggestion was exactly what i needed, i tried it and it worked fine. Your the king Thank you... Problem Solved Quote Link to comment Share on other sites More sharing options...
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