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PHP class help


Imad

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Hi guys. I put this code together to connect to MySQL using PHP Classes. The connection worked beautifully. I then created another class to process the fetch_assoc, etc. I keep getting this error however:

Fatal error: Call to a member function fetch_assoc() on a non-object in XXXX

 

I'm pretty much going to explode after hours of debugging with no results.

 

Here's my code:

 

//Now lets throw the classes
//But first, let's associate the connection to the db

Class Db_connection {
protected $db_user;
protected $db_pass;
protected $db_host;
protected $db_name;
protected $db;

public function __construct($db_host, $db_user, $db_pass, $db_name)
{
   $this->db_host = $db_host;
   $this->db_user = $db_user;
   $this->db_pass = $db_pass;
   $this->db_name = $db_name;
}

public function connect()
{
   $this->db = mysql_connect($this->db_host, $this->db_user, $this->db_pass);
   if(!is_resource($this->db)) {
     throw new Exception;
   }
   if(!mysql_select_db($this->db_name, $this->db)) {
     throw new Exception;
   }
}

public function query($query) {
   if(!$this->db) {
     $this->connect();
   }
   //throw the result "rest"
   $rest = mysql_query($query, $this->db);
   if(!$rest) {
     throw new Exception;
   }
   elseif (is_resource($rest)) {
     return TRUE;
   }
   else {
     //throw the statement and process the query
     $stmt = new Db_mysql_statement($this->db, $query);
     $stmt->result = $rest;
     return $stmt;
   }
}
}

//fetch the MySQL rows
Class Db_mysql_statement{
  protected $result;
  public $query;
  protected $db;
  
  public function __construct($db, $query)
  {
    $this->query = $query;
    $this->db = $db;
    if(!is_resource($db)) {
      throw new Exception("Need new class to log error [40: No DB Connection!]");
    }
  }
  
  public function fetch_row()
  {

    if(!$this->result) {
      throw new Exception("Neeed new class to log error [50: Query Not Executed!]");
    }
    return mysql_fetch_row($this->result);
  }
  
  public function fetch_assoc()
  {
    return mysql_fetch_assoc($this->result);
  }
}

 

Here's where I create a query:

 

//connect to the MySQL database
$db = New Db_connection($db_host, $db_user, $db_pass, $db_name);

$query = $db->query("SELECT * FROM users");
$row = $query->fetch_assoc();
$user = $row['username'];

 

Thanks in advanced.

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The object

$query->

has not been created to access the functions in class Db_mysql_statement

 

I thought I defined it here:

 


Class Db_mysql_statement{
  protected $result;
  public $query;
  protected $db;

  public function __construct($db, $query)
  {
    $this->query = $query;
    $this->db = $db;
//........

 

Excuse my ignorance. I've just grasped the OOP way of developing in PHP after a long time of developing in standard form.

Thanks in advanced.

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Thanks for your input guys, I'm definitely still in the learning process of OOP. Everyone's input and criticism are more then welcome since it helps me improve. :P

 

I'll definitely rebuild the classes again in a more neater way based on your comments and I'll post it up again here for further criticism.

Thanks a bunch!

Best Regards.

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Alright, so I rewrote this again, now the query and connect works, but for some reason the mysql_fetch_assoc doesn't work. Here's my new classes:

 

Class Db_connect {
protected $db_host;
protected $db_user;
protected $db_pass;
protected $db_name;
protected $db; //connection handler

public function __construct($db_host, $db_user, $db_pass, $db_name) 
{
   $this->db_host = $db_host;
   $this->db_user = $db_user;
   $this->db_pass = $db_pass;
   $this->db_user = $db_user;
}

public function connect()
{
   $this->db = mysql_connect($this->db_host, $this->db_user, $this->db_pass);
   if (!$this->db) 
   { 
     die(" Encountered an Error as Follows: Error: [40]
          Please contact us with the error number");
   }
   return mysql_select_db($this->db_name, $this->db);
}

public function query($query) 
{
   if(!$this->db)
   {
     $this->connect();
   }
   
   //now process the queries
   $result = mysql_query($query, $this->db);
   
   if(is_resource($result)) 
   {
     return TRUE;
   }
   
   //now process the statement
   else 
   {
     $stmt = new Mysql_statement($this->db, $query);
     $stmt->result = $result;
     return $stmt;
   }
}
}

Class Mysql_statement Extends Db_connect {
  protected $db;
  protected $result;
  public $query;
  
  public function __construct($db, $query)
  {
    $this->db = $db;
    $this->query = $query;
    if(!is_resource($db)) 
    {
      Throw New Exception("Encountered an Error as Follows: Error: [41]
                           Please contact us with the error number");
    }
  }
  
  public function fetchRows()
  {
    if(!$this->result)
    {
      Die("Encountered an Error as Follows: Error: [42]
                           Please contact us with the error number");
    }
    return mysql_fetch_row($this->result);
  }
  
  public function fetchAssoc()
  {
    if(!$this->result)
    {
      Die("Encountered an Error as Follows: Error: [43]
                           Please contact us with the error number");
    }
    return mysql_fetch_assoc($this->result);
  }
}

 

Here's where I connect to everything and create a query:

 

//let's initaite the database information to be used for db connection
$db_host = 'xxxx';
$db_user = 'xxxx';
$db_pass = 'xxxx';
$db_name = 'xxxx';

//connect to the MySQL database
$db = new Db_connect($db_host, $db_user, $db_pass, $db_name);

$query = $db->query("SELECT * FROM users");

while($row = $query->fetchAssoc()) {
  $user = $row['username'];
  echo $user;
}

 

Any help would be greatly appreciated. The error I'm getting is the set 43 error. I don't think the query is being properly set. :-/

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public function query($query) 
{
   if(!$this->db)
   {
     $this->connect();
   }
   
   //now process the queries
   $result = mysql_query($query, $this->db);
   
   if(is_resource($result)) 
   {
     return $result;
   }
   
   //now process the statement
   else 
   {
     $stmt = new Mysql_statement($this->db, $query);
     $stmt->result = $result;
     return $stmt;
   }
}

 

return $result instead of return TRUE

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