[SOLVED] PHP Function

[killah]

Is there any php function that i can use to check if a number is in a string?

 

I have this code

 

$errno = array($soc['oUPGRADES']);
if( in_array($soc['upID'], $errno[0]) )
{
echo '
<option value="null">'.$soc['upNAME'].' (Already Bought)</option>';
}

 

but it does not seem to work

 

I am trying to do something like this in other word's.

 

if( 1 is in (9,7,1, )

{

  //already bought

}

 

Any help would be appreciated.

[DeanWhitehouse]

You can use a regex to check for numbers

[phpSensei]

edit: nvm already posted

[killah]

Problem is $soc['oUPGRADES'] is always updated with more number's. And each time a number is added it put's it like this

 

$OLD = '98,76,3,4';

$new_n = '1';

$NEW = $OLD.','.$new_n;

 

$NEW = '98,76,3,4,1';

[trq]

Why is that the problem?

[gevans]

You can use a regex to check for numbers

 

That would make it a lot more draining process than necessary when you could use strpos()

 

<?php
$your_var = '9,7,1,8';
if(strpos($your_var,1) !== FALSE)
{
  //already bought
}

[DeanWhitehouse]

And then what if they want to check for a whole range of different numbers, they would need an array from 0 to 9, when they could just something like *(0-9) (or whtever it is)

[gevans]

By the sounds of thins he's going to be checking if the id number of a product is in an array so will already have the number to check against, if there are a few products it would still be faster to do this using strpos()

 

And I think you're looking for /\d*/

[killah]

	$errno = $soc['oUPGRADES'];
if( strpos($errno,$soc['upID']) !== FALSE )
{
echo '
<option value="null">'.$soc['upNAME'].' (Already Bought)</option>';
}

 

Work's so far. Just got to second mysql error. So i will post back when fixed.

 

Work's