Problem with var_dump and array

[g_p_java]

Hi i would like to insert some values in the same array and i do:

 

$arr_codes = array("0" => 'j');
$arr_codes = array("1" => 'a');
$arr_codes = array("2" => 'b');
$arr_codes = array("3" => 'c');
$arr_codes = array("4" => 'd');
$arr_codes = array("5" => 'e');
$arr_codes = array("6" => 'f');
$arr_codes = array("7" => 'g');
$arr_codes = array("8" => 'h');
$arr_codes = array("9" => 'i');

var_dump($arr_codes);

 

The output i get is :

 

array(1) { [9]=>  string(1) "i" } count : , 0

 

it seems that every time i overwrite:

 

what i have written before!!!

 

What shall i correct in that? I guess, i shall use a for loop and "playing with indexes".

 

like for ($i = 0; etc);

 

May you please help me?

 

Thanks in advance!

[premiso]

<?php
$arr_codes = array();
$arr_codes["0"] = 'j';
$arr_codes["1"] = 'a';

//etc

?>

 

Is how you would need to do it. Each time you are overwriting the other way.

[kenrbnsn]

Nice easy way of doing this:

<?php
$arr_codes = array_merge(array('j'),range('a','i'));
echo '<pre>' . print_r($arr_codes,true) . '</pre>';
?>

 

Ken