[SOLVED] using counters

[dadamssg]

i found this script to build a selection list based on the current year...this script always selects the current year and then adds one to the current year for an option. what i want to do is modify this to build a selection list for a set of years that displays this year and then 90 years before...so like 2009 through 1919. but im not familiar with how to use counters.

 

/* build selection list for the year */
$today = time();
$startYr = date("Y", $today);  //get the year from $today
echo "<select name='syear'>\n";
for ($syear=$startYr;$syear<=$startYr+1;$syear++)
{
   echo " <option value=$syear";
   if ($startYr == $syear )
   {
     echo " selected";
   }
   echo "> $syear\n";
}
echo "</select>\n";
?>

[dadamssg]

i think i have to change the + signs to - signs, and then maybe change that < to a >, but i can't seem to get it right

[Philip]

/* build selection list for the year */
$today = time();
$startYr = date("Y", $today);  //get the year from $today
echo "<select name='syear'>\n";

$endYr = $startYr-90; // get the date you want to end up at
for ($syear=$startYr;$syear<=$endYr;$syear--)
{
echo " <option value=$syear";
if ($startYr == $syear )
{
	echo " selected";
}
echo "> $syear\n";
}
echo "</select>\n";

[dadamssg]

awesome thanks...you did forget to switch the < sign to a >. but doing that and it works perfect. thanks a mil 

[Philip]

Oops, sorry

 

I should be in bed sleeping instead of surfin' the web