dimisdas Posted March 25, 2009 Share Posted March 25, 2009 I can not find whats wrong! Any ideas? $id1=rand(100,999) . "\n"; $id2=rand(1000,9999) . "\n"; $id3=rand(1000,9999) . "\n"; $id4=rand(1000,9999) . "\n"; $id5=rand(1000,9999) . "\n"; $all="$id1 $id2 $id3 $id4 $id5"; mysql_connect(localhost,$username1,$password1); @mysql_select_db($database1) or die( "There is a problem with the MySQL database"); $query = "INSERT INTO accounts (username, fullname, password, rank, banned, code, enabled) VALUES ('$user', '$name', '$pass', '1', '0', '$all', '0')"; mysql_query($query) or die('Error, insert query failed'); mysql_close(); Quote Link to comment Share on other sites More sharing options...
Maq Posted March 25, 2009 Share Posted March 25, 2009 Change this line to this and tell me what the output is: mysql_query($query) or die(mysql_error()); Quote Link to comment Share on other sites More sharing options...
dimisdas Posted March 25, 2009 Author Share Posted March 25, 2009 Username already existed. that was so silly. I took me hours to understand why it is not working. Ty! Quote Link to comment Share on other sites More sharing options...
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