sungpeng Posted March 30, 2009 Share Posted March 30, 2009 hi check I keep having this error when dealing with session Warning session_start()[function.session-start]: Cannot send session cookie - headers already sent by (output started at /home2/example/public_html/house/test2.php. Can anyone please help explain? Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/ Share on other sites More sharing options...
premiso Posted March 30, 2009 Share Posted March 30, 2009 session_Start cannot be called after output has been sent. Post the code of test2.php as that is where the output is started. Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796892 Share on other sites More sharing options...
sungpeng Posted March 30, 2009 Author Share Posted March 30, 2009 accesscontrol.php <?php include ("".$_SERVER['DOCUMENT_ROOT']."/housing/includes/config.php"); session_start(); if (isset($_POST['uid'])) { $uid = $_POST['uid']; } else { $uid = $_SESSION['uid']; } if (isset($_POST['pwd'])) { $pwd = md5($_POST['pwd']); } else { $pwd = $_SESSION['pwd']; } if(!isset($uid) || !isset($pwd) ) { ?> <html> <head> <title> Please Log In for Access </title> </head> <body> <table align=center width=300 border=0 cellspacing=0 cellpadding=0 bgcolor="#2f4f4f"> <tr><td> <table border=0 width=100% cellspacing=1 cellpadding=1> <form action="<?=$_SERVER['PHP_SELF']?>" method=POST> <tr><td BGCOLOR="#2f4f4f"><FONT SIZE="-1" FACE="Verdana,Tahoma,Arial,Helvetica,sans-serif" COLOR="#FFFFFF"> <B>Please Log In For Access:</B> </td></tr> <tr><td BGCOLOR="#c7c7c7"><FONT SIZE="-1" FACE="Verdana,Tahoma,Arial,Helvetica,sans-serif"> You must log in to access this area of the site. </td></tr> <tr> <td BGCOLOR="#fffff0"> <table width=100% border=0 cellspacing=0 cellpadding=0> <tr> <td><FONT SIZE="-1" FACE="Verdana,Tahoma,Arial,Helvetica,sans-serif">Email Address:</td> <td><input type=text name="uid" size="20" value=""></td> </tr> <tr> <td><FONT SIZE="-1" FACE="Verdana,Tahoma,Arial,Helvetica,sans-serif">Password:</td> <td><input type=password name="pwd" size="20"></td> </tr> <tr> <td colspan=2 align=center> <input type=submit name="Login" value="Login"> </td> </tr> </form> </table> </td> </tr> </table> </td></tr> </table> </body> </html> <?php exit; } //Clean the input submitted to mysql $uid=addslashes($uid); $pwd=addslashes($pwd); //this puts the variable into the session $_SESSION['uid'] = $uid; $_SESSION['pwd'] = $pwd; $sql = "SELECT * FROM users WHERE email = '$uid' AND passwd = '$pwd' "; $result = mysql_query($sql); if (!$result) { echo "A database error occurred while checking your login details"; } //if bad user/pass combo access denied if (mysql_num_rows($result) == 0) { unset($_SESSION['uid']); unset($_SESSION['pwd']); ?> <html> <head> <title> Access Denied </title> </head> <body> <h1> Access Denied </h1> <p>There are several reasons this may be happening:<BR> <UL><LI>Your username or password is incorrect</LI> <LI>You have forgotten your login information. <a href="password_reset.php">Lost Password</a></LI></UL> To return to our login page, <a href="index.php">click here</a>.</p> </body> </html> <?php exit; } ?> test2.php <?php if($_POST[action]=="Update") { echo "hello"; } ?> <html> <title>Upload an image to a database</title> <body> <h2>Update with new information</h2> <form name="form" enctype="multipart/form-data" method="post" action="<?php echo"$PHP_SELF?rid=$_GET[rid]"; ?>"> <?php include ("".$_SERVER['DOCUMENT_ROOT']."/housing/accesscontrol.php"); ?> <input type=text name='images' class='bginput'> <input type="submit" name="action" value="Update"> </form> </body> </html> Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796923 Share on other sites More sharing options...
Brian W Posted March 30, 2009 Share Posted March 30, 2009 Please use the [ code ] tags around your code please. I suspect that config.php has a extra space at the beginning or end of the file... Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796927 Share on other sites More sharing options...
sungpeng Posted March 30, 2009 Author Share Posted March 30, 2009 sorry amended see above, it is cracking my head! Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796929 Share on other sites More sharing options...
sungpeng Posted March 30, 2009 Author Share Posted March 30, 2009 even after log in, it will prompt again to key in user name and password.. which I think is unneccessary because I thought session already register the first time i log in.. on test2.php Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796937 Share on other sites More sharing options...
kenrbnsn Posted March 30, 2009 Share Posted March 30, 2009 The session_start() MUST be called before any output is sent to the browser. In your case make sure there is no white space (or blank lines) before the first "<?php" in test2.php and then put the session_start() right after the "<?php". Remove it from accesscontrol.php Ken Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796940 Share on other sites More sharing options...
Brian W Posted March 30, 2009 Share Posted March 30, 2009 What's in housing/accesscontrol.php ? if it declares session_start(), that may be where the issue is coming from Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796942 Share on other sites More sharing options...
sungpeng Posted March 30, 2009 Author Share Posted March 30, 2009 housing accesscontrol.php <?php include ("".$_SERVER['DOCUMENT_ROOT']."/housing/includes/config.php"); session_start(); if (isset($_POST['uid'])) { $uid = $_POST['uid']; } else { $uid = $_SESSION['uid']; } if (isset($_POST['pwd'])) { $pwd = md5($_POST['pwd']); } else { $pwd = $_SESSION['pwd']; } if(!isset($uid) || !isset($pwd) ) { ?> <html> <head> <title> Please Log In for Access </title> </head> <body> <table align=center width=300 border=0 cellspacing=0 cellpadding=0 bgcolor="#2f4f4f"> <tr><td> <table border=0 width=100% cellspacing=1 cellpadding=1> <form action="<?=$_SERVER['PHP_SELF']?>" method=POST> <tr><td BGCOLOR="#2f4f4f"><FONT SIZE="-1" FACE="Verdana,Tahoma,Arial,Helvetica,sans-serif" COLOR="#FFFFFF"> <B>Please Log In For Access:</B> </td></tr> <tr><td BGCOLOR="#c7c7c7"><FONT SIZE="-1" FACE="Verdana,Tahoma,Arial,Helvetica,sans-serif"> You must log in to access this area of the site. </td></tr> <tr> <td BGCOLOR="#fffff0"> <table width=100% border=0 cellspacing=0 cellpadding=0> <tr> <td><FONT SIZE="-1" FACE="Verdana,Tahoma,Arial,Helvetica,sans-serif">Email Address:</td> <td><input type=text name="uid" size="20" value=""></td> </tr> <tr> <td><FONT SIZE="-1" FACE="Verdana,Tahoma,Arial,Helvetica,sans-serif">Password:</td> <td><input type=password name="pwd" size="20"></td> </tr> <tr> <td colspan=2 align=center> <input type=submit name="Login" value="Login"> </td> </tr> </form> </table> </td> </tr> </table> </td></tr> </table> </body> </html> <?php exit; } //Clean the input submitted to mysql $uid=addslashes($uid); $pwd=addslashes($pwd); //this puts the variable into the session $_SESSION['uid'] = $uid; $_SESSION['pwd'] = $pwd; $sql = "SELECT * FROM users WHERE email = '$uid' AND passwd = '$pwd' "; $result = mysql_query($sql); if (!$result) { echo "A database error occurred while checking your login details"; } //if bad user/pass combo access denied if (mysql_num_rows($result) == 0) { unset($_SESSION['uid']); unset($_SESSION['pwd']); ?> <html> <head> <title> Access Denied </title> </head> <body> <h1> Access Denied </h1> <p>There are several reasons this may be happening:<BR> <UL><LI>Your username or password is incorrect</LI> <LI>You have forgotten your login information. <a href="password_reset.php">Lost Password</a></LI></UL> To return to our login page, <a href="index.php">click here</a>.</p> </body> </html> <?php exit; } ?> Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796945 Share on other sites More sharing options...
sungpeng Posted March 30, 2009 Author Share Posted March 30, 2009 Hi brian why I cannot declare session start? Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796948 Share on other sites More sharing options...
Brian W Posted March 30, 2009 Share Posted March 30, 2009 You can't because you already have "output". Once any html, plain text, or even white-space/line-breaks has been output, you cannot declare session_start(). I'd suggest removing it from accesscontrol.php and simply placing it at the top of test2.php . That should alleviate the problem, but remember that all pages that are using accesscontrol.php will need session_start() declared. Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796962 Share on other sites More sharing options...
kenrbnsn Posted March 30, 2009 Share Posted March 30, 2009 Didn't I say that in reply #6? Ken Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796964 Share on other sites More sharing options...
Brian W Posted March 30, 2009 Share Posted March 30, 2009 Didn't I say that in reply #6? Ken You did, I reiterated it. Not trying to step on toes. Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796974 Share on other sites More sharing options...
sungpeng Posted March 30, 2009 Author Share Posted March 30, 2009 sorry ken, just now don't quite understand. Finally got it..Thank you all really solid.. Link to comment https://forums.phpfreaks.com/topic/151762-solved-error-when-dealing-with-session/#findComment-796979 Share on other sites More sharing options...
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