If statement executing when it shouldn't

[ILMV]

I cannot figure this one out, I have an array:

 

$errors=array();

 

When I go to check the count of the array:

 

if(count($errors>0)) {
    echo(count($errors));  // output is 0
}

 

...the condition executes! Even when I echo the count it says 0, how on earth is that happening? I didn't put >=, how is 0 > 0?

 

 

Cheers, Ben

[mrMarcus]

print_r($errors);

 

you'll probably notice that there's an empty value in the array with a key of 0, right?

[ILMV]

Hey Marcus

 

No, I have print_r'd it, and it returns an empty array, not keys or values...

 

Array
(
)

[kenrbnsn]

Your "if" statement is wrong. It should be:

<?php
if(count($errors) > 0) {
?>

 

I prefer to use:

<?php
if (!empty($errors)) {
?>

 

Ken

[ILMV]

Oh hang on...

 

  Quote

Caution

 

count() may return 0 for a variable that isn't set, but it may also return 0 for a variable that has been initialized with an empty array. Use isset() to test if a variable is set.

 

http://uk2.php.net/count

 

 

Maybe I will have not initialise it, and check if it has been set... seems slightly backwards to me

[ILMV]

  Quote

Your "if" statement is wrong. It should be:

<?php
if(count($errors) > 0) {
?>

 

I prefer to use:

<?php
if (!empty($errors)) {
?>

 

Ken

 

Hello kenrbnsn!

 

Thanks for your suggestion, it works a whole lot better than count, also it looks neater.

 

Many Thanks!