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Hi All,

 

I am not sure if this is an HTML or PHP question but thought I would try in here first:

 

I have this

 

<form id="banddisco" name="banddisco" method="post" action="do/banddiscodo.php">

  <table border="0">
  <tr>
    <td width="216">Album Name</td>
    <td width="216"><input name="albumname" type="text" id="albumname" size="60"></td>
  </tr>
  <tr>
    <tr>
    <td width="216" valign="top">Tracks Names (One Per Line)</td>
    <td width="216"><textarea name="tracks" cols="60" rows="30" id="tracks"></textarea></td>
  </tr>
  

</table>


  <br />
  <br />

		        
			    
  <input type="submit"  name="Submit" value="Go" />
</form>

 

Which is a simple form for entering an albbum name and then the tracks. Is it possibe to add a line break at the end of each line in the tracks field? Basically when echoed from the database I want them one line after another.

 

Cheers

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What gnawz is saying on using the n tag, is when you echo, use "\n" to create a new line.

 

When printing out each row, use the \n character in double quotes:

foreach ( $track_names_array as $value ) {
echo $value . "\n";
}

 

This way will have a result of :

 

sometrack

another track

Beetles Track

 

The text area will have line breaks.

 

I hope this is what you are looking for.

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Ok, so I am currently showing the results like so:

 

<?php 

$sql = "SELECT * FROM banddisco WHERE userid = '$userid' ORDER BY RAND() LIMIT 10";
$result = mysql_query($sql ,$con);
while($myrow = mysql_fetch_array($result))
{

echo "<table width ='90%'>";
echo "<tr>";
echo "<td>";
echo  $myrow['albumname'];
echo "</td>";
echo "<td>";
echo  $myrow['tracks'];
echo "</td>";


echo "</table>";
}
?></p>

 

and they are being stored in a database like so:

 

<?php
   //Start session
   session_start();
   
   //Include database connection details
   require_once('../include/database.php');
   
   //Array to store validation errors
   $errmsg_arr = array();
   
   //Validation error flag
   $errflag = false;
   
   
   //Function to sanitize values received from the form. Prevents SQL injection
   function clean($str) {
      $str = @trim($str);
      if(get_magic_quotes_gpc()) {
         $str = stripslashes($str);
      }
      return mysql_real_escape_string($str);
   }
   
   //Sanitize the POST values
   $userid = $_SESSION['SESS_USERID'];
   $albumname = clean($_POST['albumname']);
   $tracks = clean($_POST['tracks']);
  
   
   
   $sql = mysql_query("SELECT * FROM banddisco WHERE userid = '$userid'");
if(mysql_num_rows($sql) == 0)
{
   //Create INSERT query
   $qry = "INSERT INTO banddisco
   (userid, albumno, albumname, tracks) 
   
   VALUES
   ('$userid', '', '$albumname', '$tracks')";
}


   
    $result = mysql_query($qry) or die(mysql_error());


   //Check whether the query was successful or not
   if($result) {
      header("location: ../member_home.php?disco=1");
      exit();
   }else {
      die(mysql_error());
      
   }
   
   ?>

 

What would I have to do to save them to an array so I can display using /n?

 

Guess this has moved to an php question now!

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<?php
session_start();

include('include/database.php');
$userid = $_GET['userid'];
$_SESSION['bandid'] = $userid;
?>

<?php 

$sql = "SELECT * FROM banddisco WHERE userid = '$userid' ORDER BY RAND() LIMIT 10";
$result = mysql_query($sql ,$con);
while($myrow = mysql_fetch_array($result))
{

echo "<table width ='90%'>";
echo "<tr>";
echo "<td>";
echo  $myrow['albumname'];
echo  "\n";
echo "</td>";
echo "<td>";
echo  $myrow['tracks'];
echo  "\n";
echo "</td>";


echo "</table>";
}
?></p>

 

Table in loop? Gap in my knowledge I think!

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Something like:

 

echo '<br><h5>These are your results</h5></br>';//showing featured listings		
	echo '<table border=1 table width="980" align="center">'; 
	echo "<tr>"; 
	$count = 5;//rows
	$l = 0;
		for($i=0;$i<mysql_num_fields($listing);$i++) 
		{ 
			echo "<th>"; 
			echo mysql_field_name($listing, $i); 			
			echo "</th>";
		} 

		while($l < $count) 
		{ 
		$row=mysql_fetch_row($listing);
			echo "<tr>"; 
			for($j=0;$j<$i;$j++) 

			{ 

			echo "<td>"; 
			echo $row[$j]; 
			echo "</td>"; 
			} 
			echo "</tr>"; 
			$l++;
		} 


	echo "</tr>"; 
	echo "</table>"; 

 

 

////////OR

 

echo '<table border = "1" bordercolor="#000000">';
  			echo '<tr>';
			//displaying the headings
		echo '</tr>';
		echo '<tr>';
			echo '<td width="20" height="20">';
				echo '<b>Fld1</b>';
			echo '</td>';
			echo '<td width="20" height="20">';
				echo '<b>Fld2</b>';
			echo '</td>';
			echo '<td width="20" height="20">';
				echo '<b>Fld3</b>';
			echo '</td>';
			echo '<td width="20" height="20">';
				echo '<b>Fld4</b>';
			echo '</td>';
			echo '<td width="20" height="20">';
				echo '<b>Fld5</b>';
			echo '</td>';
			echo '<td width="20" height="20">';
				echo '<b>Fld6</b>';
			echo '</td>';
		echo '</tr>';
	//getting the database fields
      while($row = mysql_fetch_array($query))
  		  {
		echo '<tr>';
			echo '<td>';
				$name = $row["Fld1"];
				echo $name. "<br>";
			echo '</td>';
			echo '<td>';
				$add = $row["Fld2"];
				echo $add. "<br>";
			echo '</td>';
			echo '<td>';
				$email = $row["Fld3"];
				echo $email. "<br>";
			echo '</td>';
			echo '<td>';
				$web = $row["Fld4"];
				echo ('<b><a href="'.$web.'">'.$web.'</a></b>');
			echo '</td>';
			echo '<td>';
				$tel = $row["Fld5"];
				echo $tel. "<br>";
			echo '</td>';
			echo '<td>';
				$loca = $row["Fld6"];
				echo $loca. "<br>";
			echo '</td>';
			echo '<td>';
		  }
  		echo '</table><br/>';
	}				

 

Hope it helps....

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Thanks,

 

I have this error:

 

These are your results


Warning: mysql_num_fields(): supplied argument is not a valid MySQL result resource in C:\wamp\www\fanjunky\banddiscoview.php on line 41

Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in C:\wamp\www\fanjunky\banddiscoview.php on line 50

Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in C:\wamp\www\fanjunky\banddiscoview.php on line 50

Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in C:\wamp\www\fanjunky\banddiscoview.php on line 50

Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in C:\wamp\www\fanjunky\banddiscoview.php on line 50

Warning: mysql_fetch_row(): supplied argument is not a valid MySQL result resource in C:\wamp\www\fanjunky\banddiscoview.php on line 50

 

and this is my code

 

<?php
session_start();

include('include/database.php');
$userid = $_GET['userid'];
$_SESSION['bandid'] = $userid;
?>



//$sql = "SELECT * FROM banddisco WHERE userid = '$userid' ORDER BY RAND() LIMIT 10";
//$result = mysql_query($sql ,$con);
//while($myrow = mysql_fetch_array($result))
//{

//echo "<table width ='90%'>";
//echo "<tr>";
//echo "<td>";
//echo  $myrow['albumname'];
//echo  "\n";
//echo "</td>";
//echo "<td>";
//echo  $myrow['tracks'];
//echo  "\n";
//echo "</td>";


//echo "</table>";
//}
//

<?php

$sql = "SELECT * FROM banddisco WHERE userid = '$userid' ORDER BY RAND() LIMIT 10";
$result = mysql_query($sql ,$con);
echo '<br><h5>These are your results</h5></br>';//showing featured listings      
      echo '<table border=1 table width="980" align="center">';
      echo "<tr>";
      $count = 5;//rows
      $l = 0;
         for($i=0;$i<mysql_num_fields($userid);$i++)
         {
            echo "<th>";
            echo mysql_field_name($userid, $i);          
            echo "</th>";
         }
            
         while($l < $count)
         {
         $row=mysql_fetch_row($userid);
            echo "<tr>";
            for($j=0;$j<$i;$j++)
            
            {
            
            echo "<td>";
            echo $row[$j];
            echo "</td>";
            }
            echo "</tr>";
            $l++;
         }
         
         
      echo "</tr>";
      echo "</table>"; ?>

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Ignore Aove!

 

I have now had a long overdue brainwave and have this:

 

<?php

$sql = "SELECT * FROM banddisco WHERE userid = '$userid' ORDER BY RAND() LIMIT 10";
$result = mysql_query($sql ,$con);

echo '<br><h5>These are your results</h5></br>';//showing featured listings      
      echo '<table border=1 table width="980" align="center">';
      echo "<tr>";
      $count = 5;//rows
      $l = 0;
         for($i=0;$i<mysql_num_fields($result);$i++)
         {
            echo "<th>";
            echo mysql_field_name($result, $i);          
            echo "</th>";
         }
            
         while($l < $count)
         {
         $row=mysql_fetch_row($result);
            echo "<tr>";
            for($j=0;$j<$i;$j++)
            
            {
            
            echo "<td>";
            echo $row[$j];
            echo "</td>";
            }
            echo "</tr>";
            $l++;
         }
         
         
      echo "</tr>";
      echo "</table>"; ?>

 

However it still lists the tracks one after another and not on a seperate line, as well as displaying all the fields in the database. I can I get it to display just the fields `album` and `tracks`, with the tracks one per line?

 

Cheers

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/n only creates a new linebreak in the source - not necessarily the final image.

 

Html is non-white-space sensitive. You could format Hello like this:

 

<!-- HTML -->

H

e

l

l

o

<!-- End of HTML -->

 

And you still get: Hello.

 

To create a linebreak in html/final image, use a <br />

 

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