[SOLVED] getimagesize() stopped working?

[acctman]

i noticed today that all my sites that use the fuction getimagesize() have stop working... I ran a test script and received the error below.

 

Warning: getimagesize(http://www.site.com/files/tfile.jpg) [function.getimagesize]: failed to open stream: Cannot assign requested address in /home/site/public_html/files/test4.php on line 2

width:

height:

 

$size = getimagesize("http://www.ratemybottom.com/files/tfile.jpg");

echo "width: $size[0]<br>";
echo "height: $size[1]<br>";
echo "$size[3]";  

[hchsk]

give us the function. . . .

[DarkWater]

give us the function. . . .

 

What?  It's in the GD library.  Any change in PHP version or ini settings on your site?

[hchsk]

oh, haha, i was unaware. well i might suggest in that case simply making your own getimagesize() function, which should be simple enough

 

 

 

also, the link is dead, the image does not load, perhaps that is the problem?

 

after all it says "failed to open stream: "

[acctman]

oh, haha, i was unaware. well i might suggest in that case simply making your own getimagesize() function, which should be simple enough

 

 

 

also, the link is dead, the image does not load, perhaps that is the problem?

 

after all it says  "failed to open stream: "

 

uhhh, i'm not being rude but please stop responding.

[acctman]

give us the function. . . .

 

What?  It's in the GD library.  Any change in PHP version or ini settings on your site?

 

no recent changes, last change to php.ini was on May 23rd. everything was working fine yesterday

[hchsk]

wwow, yeah i realize now how stupid that was, however yes, you are a prick. but my point still stands, make your own function, then you can customize it, and it becomes easier to troubleshoot

[mattal999]

Can we see the code of test4.php please?

[acctman]

Can we see the code of test4.php please?

 

this is all that is inside the test4.php file... i'm trying to figure out why it would just stop working

<?php
$size = getimagesize("http://www.site.com/files/tfile.jpg");

echo "width: $size[0]<br>";
echo "height: $size[1]<br>";
echo "$size[3]";  
?>

[mattal999]

Sorry to act like an idiot, but shouldn't http://www.site.com/files/tfile.jpg be http://www.ratemybottom.com/files/tfile.jpg

[acctman]

Sorry to act like an idiot, but shouldn't http://www.site.com/files/tfile.jpg be http://www.ratemybottom.com/files/tfile.jpg

 

I used "site.com" out side of the coded tag so my url wouldn't be picked up in SE searchs, most users on the site do the same thing. The actual url and link in the script on my server is 100% correct. I also have 5 our sites in which the coding hasn't been touched, and the getimagesize has stopped working.

 

the problem is not the coding, it seems like something was auto updated or a bug in GD or something

[gevans]

Depending on what version of php you're using you might want to try the following, Otherwise uncomment the second line and see if you are getting an array assigned to the size var.

<?php
$size = getimagesize("http://www.site.com/files/tfile.jpg");
//var_dump($size);
echo "width: {$size[0]}<br>";
echo "height: {$size[1]}<br>";
echo "{$size[3]}";
?>

[kenrbnsn]

Is the file you're trying to access a local file (i.e. on the same server as your script) or a remote file?

 

Ken

[acctman]

Is the file you're trying to access a local file (i.e. on the same server as your script) or a remote file?

 

Ken

 

yes the test file in local in the same folder as the test file. test4.php and tfile.jpg are in the same folder

[acctman]

Depending on what version of php you're using you might want to try the following, Otherwise uncomment the second line and see if you are getting an array assigned to the size var.

<?php
$size = getimagesize("http://www.site.com/files/tfile.jpg");
//var_dump($size);
echo "width: {$size[0]}<br>";
echo "height: {$size[1]}<br>";
echo "{$size[3]}";
?>

 

i just tried that, var dump uncommented produces the same error but with bool(false)

[gevans]

Is the file you're trying to access a local file (i.e. on the same server as your script) or a remote file?

 

Ken

 

yes the test file in local in the same folder as the test file. test4.php and tfile.jpg are in the same folder

 

If you're doing it locally why don't you do it without the url?

 

<?php
$size = getimagesize("tfile.jpg");
var_dump($size);
echo "width: {$size[0]}<br>";
echo "height: {$size[1]}<br>";
echo "{$size[3]}";
?>

 

EDIT

 

And if that doesn't work test it qith a different image to make sure the image itself isn't corrupt

[acctman]

Is the file you're trying to access a local file (i.e. on the same server as your script) or a remote file?

 

Ken

 

yes the test file in local in the same folder as the test file. test4.php and tfile.jpg are in the same folder

 

If you're doing it locally why don't you do it without the url?

 

<?php
$size = getimagesize("tfile.jpg");
var_dump($size);
echo "width: {$size[0]}<br>";
echo "height: {$size[1]}<br>";
echo "{$size[3]}";
?>

 

EDIT

 

And if that doesn't work test it qith a different image to make sure the image itself isn't corrupt

 

i did some more testing and it works without putting the in http://... just the test file was in the same directory. so what works now is inputing the abosolute server path to the image folders and locations. very odd considering the original examples I got for getimagesize came from php.net which gives the usage of http:// url as an example http://us2.php.net/getimagesize

[gevans]

Maybe something to do with local configurations, who knows. At least it's working now