garethhall Posted May 24, 2009 Share Posted May 24, 2009 Hi I have a table with 3 fields in it optionID, optionName, optionPrice. I neew for loop though the rows a couple of time but mysql does not allow me to do that. So I am trying the read the values in to an array. I got the first part working but can't get the second par to work or shall I say the second value. I need to output the price as well. How can I add the extra value into the array? To be honest I really just don't know how. Please help <? $SQL_selectOptions = "SELECT * FROM options"; $rs_selectOptions = mysql_query($SQL_selectOptions, $admin); $row_selectOptions = mysql_fetch_assoc($rs_selectOptions); $optionsPrice = array(); do{$i++; $optionsName[$i] = $row_selectOptions['optionName']; }while($row_selectOptions = mysql_fetch_assoc($rs_selectOptions)); foreach($optionsName as $name){ echo $Name; } ?> Quote Link to comment Share on other sites More sharing options...
wildteen88 Posted May 24, 2009 Share Posted May 24, 2009 This is what you'll want to do $SQL_selectOptions = "SELECT optionID, optionName, optionPrice FROM options"; $rs_selectOptions = mysql_query($SQL_selectOptions, $admin); $selectOptions = array(); while($row_selectOptions = mysql_fetch_assoc($rs_selectOptions)) { $selectOptions[] = $row_selectOptions; } All your results will be stored into the $selectOptions array. Now to display all your results foreach($selectOptions as $options) { echo $options['optionID'] .'<br />'; echo $options['optionName'] .'<br />'; echo $options['optionPrice'] . '<br /><br />'; } Quote Link to comment Share on other sites More sharing options...
jackpf Posted May 24, 2009 Share Posted May 24, 2009 Surely you don't need the while() loop. $SQL_selectOptions = "SELECT optionID, optionName, optionPrice FROM options"; $rs_selectOptions = mysql_query($SQL_selectOptions, $admin); $row_selectOptions = mysql_fetch_assoc($rs_selectOptions) Then $row_selectOptions will have all of the results in an array. Doesn't your while loop just kind of...put it into another array? Thus isn't needed. Forgive me if I am wrong Oh, and also, in your original code, $Name is not $name. You need to be careful with cases. Quote Link to comment Share on other sites More sharing options...
trq Posted May 24, 2009 Share Posted May 24, 2009 Surely you don't need the while() loop. $SQL_selectOptions = "SELECT optionID, optionName, optionPrice FROM options"; $rs_selectOptions = mysql_query($SQL_selectOptions, $admin); $row_selectOptions = mysql_fetch_assoc($rs_selectOptions) Then $row_selectOptions will have all of the results in an array. Doesn't your while loop just kind of...put it into another array? Thus isn't needed. Forgive me if I am wrong Oh, and also, in your original code, $Name is not $name. You need to be careful with cases. mysql_fetch_assoc returns one row each time it is called. So if you want all your results, you need a loop. Quote Link to comment Share on other sites More sharing options...
jackpf Posted May 24, 2009 Share Posted May 24, 2009 Ugh...just woke up. Ignore me. Quote Link to comment Share on other sites More sharing options...
garethhall Posted May 25, 2009 Author Share Posted May 25, 2009 Thanks it is working great now :) Quote Link to comment Share on other sites More sharing options...
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