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$_GET help please FIXED


maxic0

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Hi, i haven't been doing PHP for to long, so i don't know about some thing at all. I have never quite got my head around the $_GET thing
My friend was kind enout to make this little script just to show how it works.
[code]
<?php
$sentence = 'Hello, ' . $_GET['name'] . ', and welcome to my little page.';
echo $sentence;
?>
<br /> <br />
<a href="indexx.php?name=Simon">Simon</a><br />
<a href="indexx.php?name=John">John</a><br />
<a href="indexx.php?name=Max">Max</a><br />
[/code]

This code is easy to understand, but in my site i want to create a page where the information is stored in a database and then the information is collected from there. So for example if a had a table called "people " and then a little information about Simon, John and Max was stored stored in there in a field called "info" how would i echo the information about them when their name is clicked.

Any help would be very appreciated.
Thanks
maxic0
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1. You will always want to escape $_GET variables so that people do not enter malicious content onto your site.
2. Here's what I think you want:
[code]
<?php
if (isset($_GET['name'])) {
  $name = $_GET['name'];
  $query = "SELECT * FROM users WHERE name='$name'";
  $result = mysql_query($result) or die(mysql_error());
  if ($result) {
    while ($row = mysql_fetch_array($result)) {
      echo $row['name']; // Output all information.
    }
  }
  else {
    echo 'Error with query: '.$query.'<br>'.mysql_error();
  }
}
else {
  echo 'You must specify a name.';
}
?>
[/code]
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Try:

[code]
<?php
if (isset($_GET['name'])) {
  $name = $_GET['name'];
  $query = "SELECT * FROM users WHERE name='$name'";
  $result = mysql_query($result) or die(mysql_error());
  if ($result) {
    while ($row = mysql_fetch_array($result)) {
      $name = $row["name"];
      echo $row['name']; // Output all information.
    }
  }
  else {
    echo 'Error with query: '.$query.'<br>'.mysql_error();
  }
}
else {
  echo 'You must specify a name.';
}
?>
[/code]
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Change
[code]<?php $result = mysql_query($result) or die(mysql_error()); ?>[/code]
to
[code]<?php $result = mysql_query($query) or die("Problem with the query: $query<br>" . mysql_error()); [/code]
You are trying to use the contents of the variable [b]$result[/b] instead of [b][color=red]$query[/color][/b].

Ken
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