Jessica Posted August 6, 2006 Share Posted August 6, 2006 SELECT name, id FROM all_items WHERE name LIKE '%pirate\\\'s%'MySQL returned an empty result set (i.e. zero rows). (Query took 0.0030 sec)SELECT name, id FROM all_items WHERE name LIKE '%pirate\'s%'MySQL returned an empty result set (i.e. zero rows). (Query took 0.0030 sec)SELECT name, id FROM all_items WHERE name LIKE '%pirate%'The Pirate\'s Code 30Famous Pirates 32I need to be able to search for the entry "The Pirate\'s Code" using "pirate\'s" or "pirate\\\'s". Why do the first two not work? Quote Link to comment https://forums.phpfreaks.com/topic/16678-like-and-problem/ Share on other sites More sharing options...
king arthur Posted August 6, 2006 Share Posted August 6, 2006 Have you got magic_quotes_runtime turned on? Because maybe the string in the database has been escaped twice and is actually "The Pirate\\\'s Code"? Quote Link to comment https://forums.phpfreaks.com/topic/16678-like-and-problem/#findComment-70184 Share on other sites More sharing options...
fenway Posted August 6, 2006 Share Posted August 6, 2006 I'm not sure I understand why the string in your DB has the backslash at all... sounds like it got "over-escaped" on the way in, as king arthur suggested. Quote Link to comment https://forums.phpfreaks.com/topic/16678-like-and-problem/#findComment-70217 Share on other sites More sharing options...
Jessica Posted August 6, 2006 Author Share Posted August 6, 2006 The actual record in the database is The Pirate\'s Code, and that's what I need to find. :(Here's what happens. The user enters pirate's in a search form.Then:$item = mysql_real_escape_string(strip_tags($_POST['search']));$shop_info = "SELECT name, id FROM all_items WHERE name LIKE '%$item%'";At that point $shop_info = "SELECT name, id FROM all_items WHERE name LIKE '%Pirate\\\'s%'"Which if I understand the escaping, it should find pirate\'s.And, I have no idea why it's overescaped, when I put it in the database I used "mysql_real_escape_string(strip_tags($_POST['search']));" to get the string and put it in. ARGH Quote Link to comment https://forums.phpfreaks.com/topic/16678-like-and-problem/#findComment-70246 Share on other sites More sharing options...
fenway Posted August 6, 2006 Share Posted August 6, 2006 Why does the actual data have escape characters in it? Quote Link to comment https://forums.phpfreaks.com/topic/16678-like-and-problem/#findComment-70268 Share on other sites More sharing options...
Jessica Posted August 6, 2006 Author Share Posted August 6, 2006 [quote author=fenway link=topic=103135.msg410746#msg410746 date=1154881440]Why does the actual data have escape characters in it?[/quote]And, I have no idea why it's overescaped, when I put it in the database I used "mysql_real_escape_string(strip_tags($_POST['item']));" to get the string and put it in.In that case, 'item' was The Pirate's Code.Now I've gone into the database and changed the entry to "The Pirate's Code" unescaped, and the query SELECT name, id FROM all_items WHERE name LIKE '%Pirate\\\'s%'Finds it.WTF is going on here? Something is wrong with my database settings. Quote Link to comment https://forums.phpfreaks.com/topic/16678-like-and-problem/#findComment-70286 Share on other sites More sharing options...
fenway Posted August 6, 2006 Share Posted August 6, 2006 Sounds like you have magic quotes turned on, and then you're running escape string again. You need to have a wrapper function that handles this... there are many such examples. However, if it's stored "properly" now in the DB, you should need to include the extra backlash in your query. Quote Link to comment https://forums.phpfreaks.com/topic/16678-like-and-problem/#findComment-70300 Share on other sites More sharing options...
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