[WARNING! Only a Super Genius can solve this] Array with unique values?

[onedumbcoder]

wow... never mind i just realized i was the one that said that

[Daniel0]

 

I don't want to sound demeaning, but looking at your topics, maybe you should reconsider your hobby/career choice? Or maybe you should just stop for a while and take a look at what you're doing. You are failing at really elementary logic all the time.

 

Before someone says I can't say that, I'm saying this as Daniel, not as PHP Freaks admin.

[l0ve2hat3]

 

I don't want to sound demeaning, but looking at your topics, maybe you should reconsider your hobby/career choice? Or maybe you should just stop for a while and take a look at what you're doing. You are failing at really elementary logic all the time.

 

Before someone says I can't say that, I'm saying this as Daniel, not as PHP Freaks admin.

 

ouch

[onedumbcoder]

 

I don't want to sound demeaning, but looking at your topics, maybe you should reconsider your hobby/career choice? Or maybe you should just stop for a while and take a look at what you're doing. You are failing at really elementary logic all the time.

 

Before someone says I can't say that, I'm saying this as Daniel, not as PHP Freaks admin.

 

Are u talking about preg_match? I know its failing, that is why i have been trying to solve. Please reads the question before.

[PugJr]

Onedumbcoder, what is wrong with what these people have already shown you? They have given you the code so whats hard to just use it or is this something you want to learn how to do yourself?

[l0ve2hat3]

using exactly what garethp suggested but in a function...

 

 

function is_unique($array){
    return (count(array_unique($array)) == count($array))?true:false;
}

//FIRST ARRAY - NOT UNIQUE
$arr1[]=123;
$arr1[]=123;

//SECOND ARRAY - UNIQUE
$arr2[]=1;
$arr2[]=2;

//CHECK IF arr1 IS UNIQUE
if(is_unique($arr1)){
    echo "arr1 IS UNIQUE!<BR>\n";
}else{
    echo "arr1 IS NOT UNIQUE!<BR>\n";
}

//CHECK IF arr2 IS UNIQUE
if(is_unique($arr2)){
    echo "arr2 IS UNIQUE!<BR>\n";
}else{
    echo "arr2 IS NOT UNIQUE!<BR>\n";
}

 

This should output:

 

arr1 IS NOT UNIQUE!

arr2 IS UNIQUE!

 

 

[Garethp]

using exactly what garethp suggested but in a function...

 

 

function is_unique($array){
    return (count(array_unique($array)) == count($array))?true:false;
}

//FIRST ARRAY - NOT UNIQUE
$arr1[]=123;
$arr1[]=123;

//SECOND ARRAY - UNIQUE
$arr2[]=1;
$arr2[]=2;

//CHECK IF arr1 IS UNIQUE
if(is_unique($arr1)){
    echo "arr1 IS UNIQUE!<BR>\n";
}else{
    echo "arr1 IS NOT UNIQUE!<BR>\n";
}

//CHECK IF arr2 IS UNIQUE
if(is_unique($arr2)){
    echo "arr2 IS UNIQUE!<BR>\n";
}else{
    echo "arr2 IS NOT UNIQUE!<BR>\n";
}

 

This should output:

 

arr1 IS NOT UNIQUE!

arr2 IS UNIQUE!

 

 

 

Thanks, but this wasn't my code. In fact, if it were me, I would have looped through the whole array to check for the value. But now I know about this function, so I'd use this in the future. I actually have to give the credit to Daniel0 on Page 1

[RussellReal]

honestly guys.. I think hes acting retarded on purpose.. so just don't reply to this post.. delete the topic.. and ban this kid..

[newbtophp]

honestly guys.. I think hes acting retarded on purpose.. so just don't reply to this post.. delete the topic.. and ban this kid..

 

i agree, im new to php but i dont go around acting dumb on purpose. hes got quite alot of replies and yet he has not solved it, usually 1-3 replies do the trick.