[SOLVED] General questions about PHP?

[samoi]

Hello guys, sorry for bothering!

 

I have some questions about PHP!

 

 

Now so many times I see something like!

<?php

@preg_replace($pat, $rep, $str); // what does the *@* [AT] sign means in front of the function or include function?


// also sometimes I see the question mark! *?*

$question_mark = $samoi ? 0:1 // I don't know if this syntax is correct, but I want to explain where I usually see it!



?>

 

 

 

Thank you.

[severndigital]

@ operator

 

good explanation here ..

http://thesmithfam.org/blog/2006/05/07/php-the-operator/

 

 

single line if statement

$question_mark = $samoi == 'Yes'  ? 0 : 1;

//is the same as 

if($samoi == 'Yes'){
    $question_mark = 0;
}else{
     $question_mark = 1;
}

 

Hope that helps.

 

 

 

[Maq]

The ampersand suppresses error messages for that particular line.

 

Your second question can be answered here: http://php.net/manual/en/language.operators.comparison.php (search for ternary operator).

[samoi]

Thank you very much guys!

 

that helps a lot!

 

I really appreciate it!

[salathe]

Just because it's helpful to know terminology (e.g. to aid further research):

• @ is the error control operator (or error suppression operator, manual)
  
• ?: is the ternary operator (manual)
  

[cags]

The ampersand suppresses error messages for that particular line.

 

Unless that is some alternate method I've never heard of I don't think you meant ampersand which is & and is used for signalling byRef variables. I'm sure Maq is aware of that, but thought I'd point it out for anybody else who reads the thread like me and becomes a little puzzled.

[Maq]

The ampersand suppresses error messages for that particular line.

 

Unless that is some alternate method I've never heard of I don't think you meant ampersand which is & and is used for signalling byRef variables. I'm sure Maq is aware of that, but thought I'd point it out for anybody else who reads the thread like me and becomes a little puzzled.

 

Oops, yeah good catch.  I meant '@' not '&'.