[SOLVED] !in_array() problem...

[blacksmoke26]

<?php

$wgt_places = array('all', 'index', 'view', 'search');

$place = 'all, index';
$data = str_replace(', ', ',', $place);

$places = explode (',', $data);

if (!in_array ($places , $wgt_places))
{
    echo 'ERROR';
    exit;
}

echo 'PASS';
exit;

?>

 

Not found error in_array()  :'(

 

Anyone can solve this? 

[Mchl]

First argument of in_array cannot be an array itself AFAIK.

[MadTechie]

$places would be an array, your need to use a loop,

ie

foreach($places AS $p){
if (!in_array ($places , $wgt_places))
{
    echo 'ERROR';
    exit;
}
}

[premiso]

First argument of in_array cannot be an array itself AFAIK.

 

It can be as of 4.2 they added that ability, but the how the OP was using it is incorrect. The original array would need to be multi-dimensional and the array needle would need to match an array inside the multi-dimm array being searched exactly, as far as I know

 

But yea, see Mad's response for the solution.

 

EDIT:

An alternative to doing the in_array would possibly doing an array_search, depending on what the OP is looking to get out of this.

[blacksmoke26]

but i found an example in PHP manual:

 

<?php
$a = array(array('p', 'h'), array('p', 'r'), 'o');

if (in_array(array('p', 'h'), $a)) {
    echo "'ph' was found\n";
}

if (in_array(array('f', 'i'), $a)) {
    echo "'fi' was found\n";
}

if (in_array('o', $a)) {
    echo "'o' was found\n";
}
?> 

 

In this example, $needle is as array. Me also searching for array to array.

[Alex]

Your problem is that you're searching for the array $wgt_places, not each element separately. So it would work if your array looked like this: $wtg_places = array(array('all', 'index')); To get the functionality that you want you can do this:

 

foreach($places as $place)
{
if(!in_array($place, $wdt_places))
{
	echo "$place was not found<br />\n";
}
}

Or if you want a single function just to check if all the elements of $places are in $wgt_places something like this will work:

 

function ein_array($search, $array)
{
     $found = true;
     foreach($search as $element)
          if(!in_array($element, $array)
               $found = false;
     return $found;
}

[cags]

I'm going to assume English isn't your main language. What exactly is your question?

 

Firstly why replace ', ', with ',' then explode on ','. Surely you may as well have just exploded on ', ' in the first place.

 

Secondly, when passing an array as the first argument (the needle), PHP will search the second argument (the haystack) for that array. It will not seach 'the haystack' to see if it contains all values within 'the needle'. As an example, this is a value that will pass your current criteria...

 

$wgt_places = array(array('all', 'index'),'all', 'index', 'view', 'search');

$place = 'all, index';
$data = str_replace(', ', ',', $place);

$places = explode (',', $data);

print_r($places);
if (!in_array ($places , $wgt_places))
{
    echo 'ERROR';
    exit;
}

echo 'PASS';
exit;

It seems more like you want to do something like this...

 

foreach($places as $v) {
   if(!in_array($v, $wgt_places)) {
      echo 'Error';
      exit;
   }
}

echo 'Pass';
exit;

 

Edit: D'oh, snap!

[blacksmoke26]

Thanks! AlexWD