for loop without same $i digits?

[Alicia]

Hi,

 

Can some guru please advise how can I accomplish this with a simple for loop ?

 

I want to use for loop to echo all number from 000 to 999

for($i=0;$i<1000;$i++)

{

echo "$i<br>";

}

 

My question is how can I skip the values that have the the same digits from displaying more than once ?

 

e.g 1)

001 displayed

and 101, 100 should not be displayed in the page anymore since it is the same value with different permutation

 

e.g 2)

127 displayed

and 217, 712, 172 and etc with the same digits should not be displayed.

 

Please advise how can I accomplish the above. Thanks.

 

 

 

 

 

 

[cags]

Couple of questions/comments.

 

a.) Your current code wouldn't display 001, is that what you want it to do?

b.) 101, 001 and 100 don't hold the same numbers, should 101 have been 010?

c.) You say list all numbers between 000 and 999, I assume that means it's always the permutation closest to 001 that you wish to display?

[Mark Baker]

for($i=0; $i<1000; ++$i) {
$formattedi = str_split(str_pad($i,4,'0',STR_PAD_LEFT));
sort($formattedi);
$formattedi = implode('',$formattedi);
if ($formattedi == $i) {
	echo $formattedi.'<br />';
}
}

[Alicia]

Yes. 101 is a typo. SOrry...

 

I dont have problem getting extra 0 for 001 or 010.. i just have a big problem getting the same digits display only once. I have the permutation script but it doesnt seem to fit into the for loop.

 

Any gurus have any advice?

[cags]

As far as I can tell Mark Baker's suggestion fits the requirements you laid out (with the slight exception he put 4 in string pad, whereas your original requirements specified 3 digits). It pads the string out to 3 digits, splits it up and orders them into numeric order. It then implodes them back into a string in numeric order and compares it to the starting number. Basically that means that only the first permatation will match.

 

What part of that isn't a suitable solution?

[sasa]

try

<?php
for ($i = 1; $i < 1000; $i++){
$a = str_pad($i,3,'0',STR_PAD_LEFT);
if (count(array_unique(str_split($a)))==3) echo $a, "<br />\n";
}
?>

[Alicia]

Thanks guys, that one is solved and now follow up :

 

May I how can I actually create a function that can perform the following :

 

Assuming that we have 4 digits in ABCD, ABCD can be any numbers from 0000 to 9999. I need to filter and arrange the numbers in the following way without recurring numbers (permuted)

 

ABCD - all different numbers

AABB - same numbers in pair

AAAB - 3 same numbers

AABC - 2 same numbers only

 

I do have the permutation code and used strstr all to array but I think it works because I have spent some time performing the matches and it failed to work as I wanted.

 

Please advise and thanks.

 

 

 

[sasa]

try

<?php
    for($i = 0; $i < 10000; $i++){
$formattedi = str_split(str_pad($i,4,'0',STR_PAD_LEFT));
$count = array_count_values($formattedi);
$min = min($count);
$max = max($count);
if($max == 1) $group = 'all different numbers';
if($max == 2 and $min == 2) $group = 'same numbers in pair';
if ($max == 3) $group = '3 same numbers';
if ($max == 2 and $min ==1) $group = '2 same numbers only';
if($max == 4) $group = '4 same numbers';
$out[$group][] = implode('', $formattedi);
}
echo '<pre>', print_r($out), '</pre>';
?>

[Alicia]

Thanks it works fine if I test your full code but I tried to filter and only display 2 same digits as below, it doesn't work anymore. Numbers will less or more than 2 same digits are all displayed. Can you please advise whether I have updated the code wrongly as below? Thank you.

 

// show 2 same numbers digit
  for($i = 0; $i < 10000; $i++){
   $formattedi = str_split(str_pad($i,4,'0',STR_PAD_LEFT));
   $count = array_count_values($formattedi);
   $min = 2;
   $max = 2;

   $out[$group][] = implode('', $formattedi);
}
echo '<pre>', print_r($out), '</pre>';



// show 3 same numbers 
  for($i = 0; $i < 10000; $i++){
   $formattedi = str_split(str_pad($i,4,'0',STR_PAD_LEFT));
   $count = array_count_values($formattedi);
   $min = 3;
   $max = 3;

   $out[$group][] = implode('', $formattedi);
}
echo '<pre>', print_r($out), '</pre>';

[sasa]

<?php
    for($i = 0; $i < 10000; $i++){
$formattedi = str_split(str_pad($i,4,'0',STR_PAD_LEFT));
$count = array_count_values($formattedi);
$min = min($count);
$max = max($count);
if ($max == 2 and $min == 2) $out[] = implode('', $formattedi);
}
echo '<pre>', print_r($out), '</pre>';
?> 

[Alicia]

Thanks. It is working now.

 

Last question, how can I remove the [xxx] => from the output ? I just need the numbers in the page. Please advise and thanks again

[sasa]

implode $out

[Alicia]

syntax error occur after I added this line. 

implode $out;

 

Please advise and thanks.

 

 

<?php
    for($i = 0; $i < 10000; $i++){
   $formattedi = str_split(str_pad($i,4,'0',STR_PAD_LEFT));
   $count = array_count_values($formattedi);
   $min = min($count);
   $max = max($count);
      if ($max == 3) $out[] = implode('', $formattedi);
}
implode $out;
?> 

 

[cags]

implode is a function and as such requires parentheses.

 

implode($out);

[Alicia]

Actually I tried that too before I posted that to you and it returned empty page. =(

[sasa]

http://php.net/manual/en/function.implode.php

[Alicia]

It is working now but it is not in line break.

 

I tried this but not working .

 

echo implode($out)."<br />";

[sasa]

echo implode("<br />", $out);

[Alicia]

Thank you very much. It is working now.

 

May I know why it is not working when I placed the br behind ?

 

 

[sasa]

http://php.net/manual/en/function.implode.php

read manual

[Alicia]

Is there anyway we can set if the same digits are not side by side, don't display the input.. how can I edit from the existing script. So sorry for asking too many questions. Still noob in this.

 

For instance for AABC, it will show only something like 1123, 3122 and not 2129, 1091. Remove those with 2 counts but not side by side.

 

Thank you very much.

[Alicia]

any guru can assists me please.....