preg_match help

[asmith]

Hi,

 

I have a content looks like this:  (it is the  bin2hex() of a file with a space between each)

 

01 68 34 12 0c 0f 02 03 04 43 1f 09 04 32 01 45 29 81 02 03 04 ...

 

I want to get the content starting with 01 and end with 02 03 04. (the red text between bold ones)This phrase may be anywhere in the content and repeating any number.

 

So far I did:

<?php
preg_match_all('/01 (^(02 03 04)+[0-9a-z]{2} )+02 03 04 /', $content, $result, PREG_OFFSET_CAPTURE);
print_r($result);
?>

[JAY6390]

'/01 (.*?) 02 03 04/'

[asmith]

Thanks for the replay

 

How do you exclude 01 and 02 03 04?  for example:

01 68 34 12 0c 0f  02 03 04 43 1f 09 01 04 32 01 45 29 81 02 03 04 ...

 

your suggestion will give:

01 04 32 01 45 29 81 02 03 04

 

while it must give:

01 45 29 81 02 03 04

[salathe]

As you'll see, this slightly (not by much, really) complicates things.  The regex below looks for the sets of hex numbers and checks that none of the ones to be captured are "01".  It uses a negative lookbehind assertion to do that (peeking at the last two characters and asserting that they are not "01").  It also captures the space after the last number before "02 03 04", so (to save further complicating the regex) that's why rtrim is applied to the captured values.  It would be possible to not capture that trailing space, at the risk of making the regex more difficult to decipher at-a-glance.

 

$subject = '01 68 34 12 0c 0f 02 03 04 43 1f 09 01 04 32 01 45 29 81 02 03 04 ...';
$pattern = '/01 ((?:[0-9a-f]{2}(?<!01) )+?)02 03 04/';

preg_match_all($pattern, $subject, $matches, PREG_PATTERN_ORDER);
$contents = array_map('rtrim', $matches[1]);

var_dump($contents);

[asmith]

Thanks mate. It was perfect